I was a bit confused, too. But if we stop to think, y-intercept is when x=0, and 62 is y-cordinate for when x=140. I hope it makes sense to you, that was the way that I would think to explain this question.
The bad part about 24 is that b isn't the same in both functions, but r, s, and t are the same. The quickest way to do it is draw the two points, then see the only place the line is above the exponential function is between those two points, between the x (which are r) values of those two points. Think simple. Once you start finding points on the graphs, solving both, you'll see it's taking too long. There has to be a faster way.
Main point in problem 21. is that the sum sys,the car was at rest.That means the car is stopped.Then accelerated,which means the initial value is o:the graph must start from 0
The x mark is on the top of the side of the tire, and they are asking for the distance between the x and the ground. So the x would start on top and then when accelerated, it comes down.
Can someone explain number 24 please I didn't get how did he solve it. I figured out the formulas and tried on my calculator and got the answer(but it took much time)
Why in #29 the new model (3 centimeters) is double the old model (6 centimeters) if the new model is around 21.4 (the half of the new model) that is 64.2? The answer would be C)
I think you meant 2 and not 24. He chose the 2 points (1,3) and (2,4) that were already given to him because he thought to find the slope and the equation of the linear equation which might help him in the problem
I’ve seen problems where it states a particular number, indicates the margin of error, and the confidence level. For example, 16,000 with a margin of error of 450 with a confidence level of 97%. Could you tell me what to do in these cases, please?
Your no.24 is wrong. Y = (3/2)(2^x) doesn't support answer B. The correct equation is Y = (9/4)((4/3)^x) which we get when put the two points mentioned. It's also assumed that two b(s) in the question are different. My equation satisfies option B. For e.g. you can put .5 and 1.5 to test both the equations and it gets satisfied.
I really appreciate your effort to help sat takers! You r the best, man. All your videos are really crucial for us.
Thank you, man
I respect you)
You're welcome; thank you for the kind words!!
Your channel must have at least 1 million subscribers! It's Amazing
Thank you for your support!!
24 is so hard, I didn’t get the explanation(
Sorry about that, let me know if you a have a more specific question and I'll try my best to help
This is very helpful. First I do the practice test and then I review it using your walkthroughs. Thank you.
You’re welcome!
Thank you scaler learning
I really feel my skills are better now in math
Great to hear!
I love these videos, you also look like a smarter version of Cody Ko
Lol, I just looked him up hahah
LMAOOOOO
30:00
thanks for the video.
You're welcome
38:29 what did you say here? Why can’t it be wider then 62? Because it is already at 140??
I was a bit confused, too. But if we stop to think, y-intercept is when x=0, and 62 is y-cordinate for when x=140. I hope it makes sense to you, that was the way that I would think to explain this question.
@@lucasprier9902 ohhhh that makes sense
nice work
Thank you
The bad part about 24 is that b isn't the same in both functions, but r, s, and t are the same.
The quickest way to do it is draw the two points, then see the only place the line is above the exponential function is between those two points, between the x (which are r) values of those two points.
Think simple. Once you start finding points on the graphs, solving both, you'll see it's taking too long. There has to be a faster way.
thank you thank you thank you
Would you ever make calc 1 videos? Your channel helped me for SAT so much! Hoping to come back here for college math help LOL
Yes that's the plan
Main point in problem 21. is that the sum sys,the car was at rest.That means the car is stopped.Then accelerated,which means the initial value is o:the graph must start from 0
The x mark is on the top of the side of the tire, and they are asking for the distance between the x and the ground. So the x would start on top and then when accelerated, it comes down.
Q21
Shouldn't the distance between X and the ground be 0 when X touches the ground?
And the distance in graph A is never 0
Question 26 really threw me off with that wording
thanks
Can someone explain number 24 please I didn't get how did he solve it. I figured out the formulas and tried on my calculator and got the answer(but it took much time)
Huzefa, please solve October 2020 SAT (INTERNATIONAL)..you have solved US SAT but haven't solved International. Plz solve that as well.
I know, I can't bc not officially released.
Why in #29 the new model (3 centimeters) is double the old model (6 centimeters) if the new model is around 21.4 (the half of the new model) that is 64.2? The answer would be C)
C is backwards - 1 cm use to represent 6 meters and now 1 cm represents 3 meters.
Why Don't you explain while doing the math? At 24 how did you get y=x+24?
What do you mean? This is a timed attempt so it's a little faster
I think you meant 2 and not 24. He chose the 2 points (1,3) and (2,4) that were already given to him because he thought to find the slope and the equation of the linear equation which might help him in the problem
Do you double check while ans the question usually or do it at the end
I’ve seen problems where it states a particular number, indicates the margin of error, and the confidence level. For example, 16,000 with a margin of error of 450 with a confidence level of 97%. Could you tell me what to do in these cases, please?
It's in this video: ruclips.net/video/u18NskySeS0/видео.html
How did you calculate the gradient in Number 27
For Q5, Is there ever a case where the sample size might nor match the same place?
very very tough though!
Yes
Can you help me
Email me for tutoring inquiries: huzefa@scalarlearning.com
Why did u do (1+1.28) in 30 but keep it 250% in 19
Exactly. I got 30 wrong because I followed the principle in 19
Hi Huzefa I have a problem with Q 29, how can 21.4 be the double of 64.2????
64 is the airplane
We’re comparing wingspans
So the old wingspan is 10.7
The new wingspan is 21.4
=> the new wingspan is double the old wingspan
Your no.24 is wrong. Y = (3/2)(2^x) doesn't support answer B. The correct equation is Y = (9/4)((4/3)^x) which we get when put the two points mentioned. It's also assumed that two b(s) in the question are different. My equation satisfies option B. For e.g. you can put .5 and 1.5 to test both the equations and it gets satisfied.
I check all the answers at the end.
Weed smokers definitely failed