You're absolutely right, calculating the inverse of a 4x4 matrix by hand can be quite time-consuming and complex, which is why it's often not covered at A-level without the aid of technology. It's great for deepening your understanding of matrix operations, though! If you ever decide to tackle it, patience and practice are key. Thanks for watching and sharing your thoughts 😇
I know I'm 10 months late, but I loved your vid... I needed it for school and some of my personal game dev projects... hope you the best in life + earnt a sub :)
Better late than never, and I'm so glad you found the video helpful for both school and your game dev projects! Thank you for the support and for subscribing. Wishing you great success with your studies and your game development. Keep up the fantastic work! 😊
hi i wanna say i love your videos but i have a question for linear systems with 3 variables and 2 constants such as a and b what do we do for example c) For what values of a and b does the system below have (i) No solution? (ii) Many solutions? (iii) A unique solution? x-2y+3z+4 2x-3y+az = 5 3x-4y+5z=b
Hi, I'm glad to hear that 😇 To solve your question, you have to make the last row like this [0 0 variable|variable]. Then, you'll figure out which value of a and b will give you a unique solution, no solution, or infinitely many solutions. As an example, in the last row you will get [0 0 (number+a)|(b+number)]. Watch this video on my Linear Algebra playlist that's almost the same as your question: ruclips.net/video/gPOL-hwzIUc/видео.html Here's another video: ruclips.net/video/61vt1nDHOKo/видео.html Also, here's a video with an overview of types of the linear system solutions: ruclips.net/video/18_oG-cD9Ck/видео.html The idea is to make the last row look like this: [0 0 (unknown value)|(unknown value)]. Good luck & feel free to ask👍
God help me
Wishing you the best & if you're struggling with the material here, I'm happy to help
im guessing this is why we don't do inverse of a 4x4 at A-level, inverse of a 3x3 without a calculator takes enough time by itself
You're absolutely right, calculating the inverse of a 4x4 matrix by hand can be quite time-consuming and complex, which is why it's often not covered at A-level without the aid of technology. It's great for deepening your understanding of matrix operations, though! If you ever decide to tackle it, patience and practice are key. Thanks for watching and sharing your thoughts 😇
Finding the Inverse of 4×4 matrix was very use ful to me... Nd the explanation was very clear and understandable
I'm glad you found the video useful & clear! Thanks for watching 😊
I know I'm 10 months late, but I loved your vid... I needed it for school and some of my personal game dev projects... hope you the best in life + earnt a sub :)
Better late than never, and I'm so glad you found the video helpful for both school and your game dev projects! Thank you for the support and for subscribing. Wishing you great success with your studies and your game development. Keep up the fantastic work! 😊
Great. I watched it 2 times!
Glad you liked it! Your support keeps me motivated to create more 👍😇
hi i wanna say i love your videos but i have a question for linear systems with 3 variables and 2 constants such as a and b what do we do
for example
c) For what values of a and b does the system below have (i) No solution?
(ii) Many solutions? (iii) A unique solution?
x-2y+3z+4
2x-3y+az = 5
3x-4y+5z=b
Hi, I'm glad to hear that 😇
To solve your question, you have to make the last row like this [0 0 variable|variable]. Then, you'll figure out which value of a and b will give you a unique solution, no solution, or infinitely many solutions.
As an example, in the last row you will get [0 0 (number+a)|(b+number)].
Watch this video on my Linear Algebra playlist that's almost the same as your question:
ruclips.net/video/gPOL-hwzIUc/видео.html
Here's another video:
ruclips.net/video/61vt1nDHOKo/видео.html
Also, here's a video with an overview of types of the linear system solutions:
ruclips.net/video/18_oG-cD9Ck/видео.html
The idea is to make the last row look like this: [0 0 (unknown value)|(unknown value)].
Good luck & feel free to ask👍
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