3PHASE -Concept of balanced and unbalanced load in tamil

Concept of balanced and unbalanced load:
Balanced load:
The balanced load is a load in which each phase have identical impedances.
i.e each impedance has the same magnitude and phase angle. Hence each impedances draws equal current and power factor.
Unbalanced load:
The unbalanced load is a load in which eac h phase have unequal impedances.
i.e each impedance has the different magnitude and phase angle. Hence each impedances draws unequal current and power factor.
Phase current:
The current flowing through any one of th current and is denoted by Iph
Line current:
e phase windings of the system is called phase Line current means the current flowing through the AC supply lines and it is denoted by IL
Thank You for watching

[@velmurugan-gp1wp]

I like your way of teaching sir

[@ethayath6296]

Thank you so much it's very useful for me i understand very easily I request you to more videos sir again thank you 🙏🙏

[@mahasewansivam6453]

Sir your explanation about electrical really appreciated and easy to understand
Sir by the way please explain about earthing and their culculation thanks

[@___alone_king_____4588]

Thank you sir...good explain sir

[@durairaj8838]

Thank you very much sir

[@Electrical_engineer003]

Very useful sir 🙏

[@dhinakaran4926]

Very very use ful

[@buragaprasadbabu9226]

Very good sir

[@rajagpgtbotany7706]

Dear sir good morning. ..if the balanced load have same voltage in each phase ok. ..but the unbalanced supply have the loads are may differ ...ok but votages are differ or same ? ..please explain ...in my 3 phase energy meter shows following voltages R phase 450 voltages y phase 240 voltages and b phase 455 voltages. ... can you explain to me. ..what is the problems occurred here ? Nobody can't rectify me including EB officer. ..it will cause more EB bill to me ...another one example if I connect a 20 watts LED FLOOD LIGHTS to R phase it's consume 0.10 amphere current so...450 v× 0.10 amp × 1 PF× 1 hour = 45 watts / hours energy consumed. ..I know well no one take other than the maximum keposity of energy ...but how to possible 20 w light comsumed 45 w energy. ..I thing voltage of R PHASE is higher than 230?...please sir...please solve my problem. ..thank you

[@chesstech6250]

Rombaaa rombaaaa rombaaaa nadriiiiiiii 🎉🎉🎉🎉🎉🎉🎉 ayyaaaa

[@vnorola]

Sin (a-b) formula also needs to correct

[@mdazar790]

One doubt sir... Balanced supply is only for theory nu sonninga... But a 3 phase induction motor or pump balanced supply thana?

[@devarajanrasu1187]

Not balanced supply, it act as balanced load

[@palanivelan4516]

Thank you, sir,
I would like to get clarification on the reason why the same phase of prepaid energy meters only keeps on burning.at first time yellow phase of prepaid meter was burnt and we replaced the new 3 pH meters , but after some time again the same phase was burnt.

[@EEEVIDS]

Very good

[@a.kamesha.kamesh823]

How to apply the triper connection in home

[@siddiquebasha4726]

3 phase la anyone phase return path use aaga sullringa aappo 3phase la voltage check pannambothu 3phase layum voltage sariya irrukay appade nenga sullramathire irrundha any one phase la voltage irrukkay kudhathu illaya sir pls explain

[@siddiquebasha4726]

Explain

[@dineshm4564]

yappede bro yannaku puriyalla konjam explain bro plz plz

[@prabudeva2547]

Sin a+b sin a-b formula incorrect sir...

[@dhinakaran4926]

Supr sir

[@EEEVIDS]

Thank u

[@ARUNKUMAR-xc1tu]

Sir naa Ac mac yanaku line tha konjam puriyamattithu but vonga help venum sir....

[@ARUNKUMAR-xc1tu]

Vonga numper send pannuga sir....

[@ARUNKUMAR-xc1tu]

But neega explain panna yanaku puriyoum...sir

[@vnorola]

Sir...Small mistake

[@vnorola]

Sin (a+b) formula is wrong

[@vnorola]

Cos 120deg = -0.5