Slope of the tangent line to the polar curve r = tan(theta) at pi/3

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  • Опубликовано: 13 дек 2024

Комментарии • 10

  • @khawajaadeel7966
    @khawajaadeel7966 3 года назад +3

    Sir some distortion are create in your voice

  • @hongtruong5377
    @hongtruong5377 8 лет назад

    hi, love your videos it really helped me alot. i was wondering if you could do a problem from this same chapter but any number from 29-46. 10.3. "sketch the curve with the given polar equation by first sketching the graph of r as a function of theta in cartesian coordinates." really kind of lost about doing the cartesian part. thank you very much!!

  • @dr.dragon8322
    @dr.dragon8322 2 года назад

    Why can you not just take the derivative in terms of d(theta)/dr? Doing this wouldn’t achieve the same result I realize, but I’m wondering why mathematically you need to convert this to Cartesian coordinates at all to begin with? (If you don’t respond I will understand I’m just wondering.)

  • @aparnaaap7124
    @aparnaaap7124 3 года назад

    I like the class

  • @cats_of_neptune
    @cats_of_neptune 5 лет назад

    Thankyou!

  • @Iloveyou-qy3gr
    @Iloveyou-qy3gr 6 лет назад

    than

  • @LK-dn7wm
    @LK-dn7wm 3 года назад

    I love u

  • @DanDart
    @DanDart 8 лет назад +3

    Hahaa speaking massively fast... I understood, maybe more people should do that :o

    • @blackpenredpen
      @blackpenredpen  8 лет назад +2

      Lol. Also, I want to thank you for pointing out 5sqrt(3)

    • @DanDart
      @DanDart 8 лет назад

      +blackpenredpen Heheh no worries, not everyone spots the small stuff, no one is perfect but you make a great job of making these! Keep on winning! :D