K Closest Points to Origin | LeetCode 973 | C++, Java, Python

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  • Опубликовано: 8 окт 2024
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Комментарии • 8

  • @chetnavarma3486
    @chetnavarma3486 2 года назад +2

    I was just struggling with this problem and you have made it look like a piece of cake. Thank you very much! :)

  • @meharkaur7326
    @meharkaur7326 4 года назад +1

    The for loop can be simplified as follows:
    for(int[] temp: points){
    pq.add(new Point(temp));
    if(pq.size() > K){
    pq.remove();
    }
    }

  • @vireshdeshamane
    @vireshdeshamane Год назад +1

    legendary

  • @Star_Bawa9
    @Star_Bawa9 2 года назад

    Can't we just take priority queue with min heap and just the pop the element k times

  • @medhak7322
    @medhak7322 4 года назад

    Sir, why do we need to define the comparison method in a structure?