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- Опубликовано: 20 янв 2014
- MIT RES.TLL-004 Concept Vignettes
View the complete course: ocw.mit.edu/RES-TLL-004F13
Instructor: George Zaidan
In this video, Legos ¬ are used to create possible molecular level models of a buffer. This is done to better understand how a buffer works and the components a buffer must contain in order to be effective.
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu
This is the best explaination of buffers I have ever heard, read or watched.
This may be the most lucid explanation of a concept I have ever seen and heard. Sets a new standard.
Merci Madame Sophie Demoustier de nous avoir fait découvrir cette incroyable vidéo
it took me 45min to watch this video! My brain didnt handle this much fast paced explanation
the best explanation ever..It's been 10 years since I have graduated from the school of Medicine with the same questions about Buffer system in the blood & this is the 1st time ever I could really comprehend it..
just need one clarification as long as Buffer systems in Blood are basically made by H2CO3 and its same Conjugate base HCO3, not by another base
thanks alot
him: pause the video and discuss with a friend
me, alone in my dorm room: ...
Beautiful presentation and quality of video. Thank you for your efforts.
Finally, a good explanation! This was useful. Thanks.
1. H+ reacts with A-, forming HA.
2. OH- reacts with HA forming A-.
They can do this as long as enough HA/A- is present. Once you run out, the buffer stops working...
But why doesn't the OH- just react with the H+ from the dissociation?
I think it's because H+ is at very low concentrations. The chances of an OH- finding an H+ are much less likely than finding an HA. Compare something like 10^-10 M of H+ and 1 M of HA.
This video is very, very thorough. Thank you so much.
Thank you, tough material ... well explained with the lego.
I refreshed my browser at least three times because I thought that the momentary stop right after he added the NaOH was my computer...wait for it....buffering!
Keirah but he continued to speak !
Wow.. it's so amazing. Thanks a lot of your presentation in video. It is enough for understanding for me.
Thankyou very much. You have cleared my whole concept .Great!!!!!!!!
the best explanation...
Thanks the explanation was really helpful.
Perfect! Thank you.
Brilliant video
best explanation
So helpful! Thanks :)
best equilibrum video explening omg so good
how did you gave a moving photo as youtube profile
Fantastic
Awesome.
What happens if you add water to a buffert?
I think that what I appreciate the most about this video--perhaps what sets it apart from most or all other on the same topic--is that there is no possible way to misunderstand what is being discussed. There is no ambiguity whatsoever. Brilliant!
Thank you so much. :D
Oh yeah! Master Class for free
When you say that OH- + HA > H20 + A-, why would this happen as it is a weak acid, to begin with. Would it make sense to say that the OH- reacts with the H+ from the equilibrium established with HA, and then from Le Chatliers Principle, show that the H+ ion concentration in the equilibrium HA > H+ + A- is decreased, and as such more H+ is produced, but only enough to reach the equilibrium. This shows that the H+ ion concentration does not change thus the solution does not change in pH.
if MIT is explaining it with legos it cant be that hard
very good tq a lot!!!!!😊🐴
I liked it very much when you asked why should a strong base/acid not act as a buffer, well it made me think.. I came up with an answer that I think does make sense. for the Ka to remain constant.. say [A+][H-]\[HA] A loss in say
So if add OH-
SAY 2% loss of H+ that is numerator will be compensated by decrease in around 2%of the denominator so as to keep the value of [A+][H-]\[HA] constant,,, now since there are a lot less HA in comparisom to H+ the increase of H+ due to decrease of HA that is by dissociation will provide negliable compensation...
butter?
thanks 4 vedio
Why does HA not give a proton (H+) to the A- conjugate base?
Conjugate base is formed when the acid loses one proton and conjugate acid is formed when it gains one proton
Shout out to Mrs. Mathews Chem class
Great👍
Good
I just want to know what buffering means
you sound like ben shapiro
I wonder there is a love button near te like button
Thoda dimag kharab hua par samaj aya
Too much ! Please just tell us and show us how it works ! From 4 minutes onwards I would say this is too much for age 16+ at school..... (as a teacher) .... if you are watching a video it is not easy to suddenly have a hypothesis about something like this ! The guy in video might have as he has been working with this and knows what he is about to say !! its a shame as he is interesting to listen to - but just the level is too much for high school level
+Jenny Wilson You don't learn this in high school, unless you're taking AP/IB Chemistry which are college level courses.
you do learn it in Scotland in high schools - unfortunately !
Jenny Wilson Doubt it. It's probably a college preparatory class. I learned this in high school and relearned it in college. It's not too bad, compared to other things you learn.
well actually we do learn this at High School in Scotland - I do believe American High Schools are not as high a level as Scottish ones - we start University at quite a high level and typically most people do just one degree. We dont have the college followed by University as you do in America.
Jenny Wilson The United States doesn't have college followed by University. This topic is taught in all high schools in America - in IB/AP courses which literally every high school student takes
Perhaps one of the lost unintuitive and unnecessarily complex explanations of a buffer. I expected better from MIT; please remove this injustice.