Congratulations for your video. Very well explained. It is difficult to find so good and professional plasticity explanations in internet. I’ve found out that the p-q diagram is very useful to visualize pressure dependency and to progress to Drucker-Prager models for example with tension-compression asymmetries.We are using more and more pressure dependent plastic models for metals in car crash finite element simulations. We need pressure dependent models to build up accurate fracture models.
Excellent Video I understand the concept of effective stress for various cases. how do you write effective stress equal to Sqrt(2/3 sigma':sigma'), any derivation is available?
Congratulations for your video. Very well explained. It is difficult to find so good and professional plasticity explanations in internet. I’ve found out that the p-q diagram is very useful to visualize pressure dependency and to progress to Drucker-Prager models for example with tension-compression asymmetries.We are using more and more pressure dependent plastic models for metals in car crash finite element simulations. We need pressure dependent models to build up accurate fracture models.
Good Explanation. Appreciate the efforts to explain so nicely.
thanks a lot for the vedio! But in 13:08, it should be subtract sign in stead of add sign in the maternal
good one
Good explanation
great great
excellent
@ 7.21 Why we are calculating the effective plastic strain rate tensor instead of effective plastic strain?
plastic deformation depends on loading history therefore the problem is solved incrementally.
Thankyou
Hi, the equation of the linear hardening (time 2:44) does not match with the figure; the intercept of the line is less than sigma y.
Please note that in the formula plastic strain is used while in the curve horizontal axis shows total strain.
👍
in 11:28 , when calculating the normal (n), why did we divide by 2*sqrt(3/2 sigma':sigma') ?
Please note that we are making a derivation from sigma-e, which its definition contains square root.
@@engineering_software oh yes, thank you so much :)
Excellent Video I understand the concept of effective stress for various cases. how do you write effective stress equal to Sqrt(2/3 sigma':sigma'), any derivation is available?
2/3 can be found by this fact:
In simple tension effective stress is equal to applied stress.
@@engineering_software Thank you very much, This is my long-time doubt, it is clear Now. Still, I am wondering how they introduce the factor!