Chomsky Normal Form and Greibach Normal Form

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  • Опубликовано: 2 фев 2025

Комментарии • 24

  • @yadav211
    @yadav211 8 месяцев назад

    Sida concept no bakwas 🔥

  • @suchitamahajan4189
    @suchitamahajan4189 7 лет назад

    Thank you so much sir its really helpful for me☺️

  • @ayushdabral4232
    @ayushdabral4232 8 лет назад +1

    i found exactly wht i want..thank you..u got a sub

  • @vinaykumarneela4538
    @vinaykumarneela4538 7 лет назад +2

    5:39 if B can have more than one length then it is clear that given grammar is not in Chomsky Normal Form then what is the point of about Griebach Normal Form

  • @suvamroy9426
    @suvamroy9426 8 лет назад

    ssssssssoooooooooo helpful awesome work sir, but i have a question in the GNF the SB part can be assumed as another single varible ?

    • @robinthebright
      @robinthebright 8 лет назад +1

      Yep, that's what I was thinking, B € V* in A -> aB so in S->aSB the SB belongs to V*, so i suppose it's valid answer. But of course we can make another variable C->SB so that S->aC

    • @rishabhmalhotra6474
      @rishabhmalhotra6474 8 лет назад

      but B->b is not in GNF is it??

    • @robinthebright
      @robinthebright 8 лет назад

      +Rishabh Malhotra Yep, it's not GNF.
      And from where are you doing Savitch theorem and Cook's theorem?

    • @serenestrolls-d7b
      @serenestrolls-d7b 7 лет назад +1

      it is in GNF. because A->aB where B can belong to V* so it can also be 0 length string. * is kleen star or closure and it contains 0 length string.

    • @lawn_mower4941
      @lawn_mower4941 7 лет назад

      Vishal Raghav thanks man that's right

  • @nawazishalvi9894
    @nawazishalvi9894 8 лет назад

    sir very nice
    sir plz come here in jhanz bazar at least once plzzz plzzz

  • @kulwantsinghmalik6106
    @kulwantsinghmalik6106 7 лет назад +2

    in the last example B->b is not in GNF form

  • @Playwithus2222
    @Playwithus2222 Год назад

    merci

  • @amirgul8573
    @amirgul8573 8 лет назад

    thanx bro,

  • @fethiourghi
    @fethiourghi 6 лет назад

    thank u

  • @alvdel2126
    @alvdel2126 8 лет назад

    thanks from spain sir

  • @ashishpajapati8032
    @ashishpajapati8032 8 лет назад

    cook s theorem is ..there at last ....

  • @marko93official47
    @marko93official47 7 лет назад

    alway thanks

  • @PiyushKumar-qj8ue
    @PiyushKumar-qj8ue 7 лет назад +1

    watch in speed 1.25 & thank me later.