Inverse Distance Weighted Interpolation Worked Example

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  • Опубликовано: 1 дек 2024

Комментарии • 9

  • @tylerdurden5924
    @tylerdurden5924 4 года назад +7

    Interesting. I had wonder if that could be correct. My nose told me it isn't. 107.95 don't fit very well. And indeed the correct value is 103.7
    But thank you very much. Good explanation.👌

    • @TheGeomatician
      @TheGeomatician  4 года назад

      Of course, it cannot be larger than the surrounding values. I will fix the video. Thanks for noticing. Cheers.

    • @anthonator1033
      @anthonator1033 Год назад

      @@TheGeomatician cap

  • @jackcampbell4165
    @jackcampbell4165 2 года назад +1

    I love your videos and will continue to watch them, they have been an enormous help. However, you may consider getting a new microphone or doing some audio preprocessing, the volume fluctuations almost blow out my eardrums every time

  • @JuliusUnscripted
    @JuliusUnscripted Год назад

    really great video!!! thanks a lot! :)

  • @neekhilsingh2114
    @neekhilsingh2114 3 года назад

    Explain the weight value how u caculated weight

    • @abdullamasud4278
      @abdullamasud4278 2 года назад

      As mentioned in the video, w = 1/d^p
      take p as whatever you want (0.25 is most used as mentioned in the video)

  • @ushakachari4473
    @ushakachari4473 3 года назад +1

    How the weight is plotted against the distance directly. Please elaborate

    • @abdullamasud4278
      @abdullamasud4278 2 года назад

      I don't really know if this is what you are asking for but,
      To get that graph you need to plot distance with weight.
      For Distance:
      You take a series of values for distance, say 0 to 100.
      For Weight:
      Weight is just a function of distance,
      w = 1/d^p
      where p = power (determines how strongly distance affect weight)
      take p=1 for now and substitute it in the formula.
      Now you simply plot distance as x and weight as y. You get that graph.