Normal Operators

[@garfieldnate]

About the last result: can anything be said about eigenvectors corresponding to multiplicities of eigenvalues? Are they also orthogonal?

[@artunsaday6391]

If lambda is an eigenvalue of T with multiplicity, then the eigenspace of lambda (null(T-I*lambda)) has dimension more than 1. Any vector from this subspace is an eigenvector of T, so eigenvectors of T corresponding to multiplicities of eigenvalues does not have to be orthogonal. (Although you can pick orthogonal ones)

[@zakirreshi6737]

Thanks for the video

[@sebastiantrent8160]

Very well expalined

[@isuryashashank]

He is legend

[@Pp-pl2hh]

This kind of explanation feels like robotic

[@fouadalrefai5590]

Thanks for the video