Harvard University's MOST CHALLENGING Algebra Problem? k=?
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- Опубликовано: 27 окт 2024
- Are you ready to put your algebra skills to the test? In this video, we're going to tackle the most challenging algebra problem from Harvard University.
From complex equations to mind-bending formulas, we'll break it down step by step and show you how to solve it. If you think you're up for the challenge, join us as we dive into the world of advanced algebra and see if you can keep up with the best of the best from Harvard.
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@ShittuMathematicsClass01
Are you ready to put your algebra skills to the test? In this video, we're going to tackle the most challenging algebra problem from Harvard University.
From complex equations to mind-bending formulas, we'll break it down step by step and show you how to solve it. If you think you're up for the challenge, join us as we dive into the world of advanced algebra and see if you can keep up with the best of the best from Harvard.
k=2. 2^6=2^6
k⁶ = 2⁶ k = 2*x where x⁶ = 1.
The solutions to x⁶ = 1 are e^(i*2pi*l/6) where 0
k_j=2[cos(jπ/3)+i*sin(jπ/3)],j=0,1,...,5
Super cool!!! Make a video showing how you arrived at that general expression, please