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@@XFLAME07 ikr, Who the hell Gave This much Questions 😭 My teacher just solved a Few questions in the exercise and Told us to do the Rest. What am I ? A Chemist ?
Hi sir... Good morning.... can u teach maths for class 11th because for me exam starts pls sir first exam is maths pls teach on 17th July I have maths exam pls teach
Sir engaluku chapter 6 Gaseous State teach panranga sir please sir athayum teach panunga sir konjam fast agh aprm quantum numbers um teach pannunga sir
@@sivausha2006A certain compound contains, X = 50% (Atomic weight = 10) ; Y = 50% (Atomic weight = 20) ∴ The molar ratio is given by, X:Y=50/10 : 50/20 = 2 : 1. Hence, the simplest formula of the compound is X2Y.
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Where to watch the next part?
Ans is
Element. %. Relative no.of moles.
X. 50. 50/10=5.
Y. 50. 50/20 2.5.
Simple ratio
X 5/2.5 =2
Y. 2.5/2.5=1
So the simplest compound is X2Y
Hey tq so much now i under stood it 😊
Sir neenga nadathurathu puriyuthu sir u r our gift 🎁
Class 11 2025 batch students like here👇
Idu da last lecture AA inda lesson ku
@@ayeshahanifa2124 aama
B
X
2
Y
no. of atoms of
X
=
50
10
=5
no. of atoms of
Y
=
50
20
=2.5
Simplest ratio: for
X
=
5
2.5
=2
for
Y
=
2.5
2.5
=1
Empirical formula is
X
2
Y
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Entha ooru bro
@@DEVIL_GAMER16 NEENGA??
telangana bhai
@@DEVIL_GAMER16
answer for last questiion X2Y
How
Sir, Book back exercise Solve pannunga sir... Romba helpful ah irukkum. 😢
Yea ;-; it has like 50+ questions ☠️
@@XFLAME07 ikr, Who the hell Gave This much Questions 😭 My teacher just solved a Few questions in the exercise and Told us to do the Rest. What am I ? A Chemist ?
@@HariniRamesh15 same problem goes for me too..... My sir solved just 10 questions in that 😩
@@XFLAME07 Don't worry friend. I'm sure we will Figure out How to solve every sums on our own without their Help! Stay Strong! 💪🏻
Sir tomorrow chemistry exam i am just hopeless but now fire (AD)²
Hi sir... Good morning.... can u teach maths for class 11th because for me exam starts pls sir first exam is maths pls teach on 17th July I have maths exam pls teach
😂😂😂😂
Sir...normality formality eqiwalent weight atha topics..edukala...nega
Thank you sir ❤ love it 🔥🔥🔥🔥🔥🔥💯
Sir normality edukalaya?
I couldn't find the next part of normality. Where to watch?
sir ans X2Y
amazing sessions sir thank you
Please do a problem solving session on motion in a straight line..
sir andha new ncert solving channel peru enna??pls telll
Link kuduthurukaga bro
Sir so much tq for this brilliant questions it made to give the confident in chemistry
Sir answer of 20th is (c) x2y
Thank you sir love you ❤🔥🔥🔥🔥
Sir engaluku chapter 6 Gaseous State teach panranga sir please sir athayum teach panunga sir konjam fast agh aprm quantum numbers um teach pannunga sir
Answer for the HW question :
Option B
B
@sreenidhiabhinandhan How?
Sir physics motion in 1d problem solving poduga , it will be useful for our midterm exams
Option b
How?
Hii could you explain how
Intha ppt enka sir available
v helpful sir, thank u
Sir can you please solve book back problems it's helpful for stateboard students sir
Suberb sir 🎉
Answers:-X2Y
B X2Y
Sir, Can u post a pdf containing all these questions!
Mass sir... What is your salary 😅😅
10000000000
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100000000000000000⁰0⁰0000000000⁰00⁰0000⁰00000
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ANSWER FOR LAST IS {B}(X2Y)
How
Sir in 17:59 [ 2×1.15 = 2.3] only sir then why u put 23 sir
There is 10
30
The answer for the last question is X2Y
Thank you sir 🙏 you had made lots of efforts for us 😊
Bro can u explain please
@@sivausha2006A certain compound contains,
X = 50% (Atomic weight = 10) ;
Y = 50% (Atomic weight = 20)
∴ The molar ratio is given by,
X:Y=50/10 : 50/20 = 2 : 1.
Hence, the simplest formula of the compound is X2Y.
@@sivausha2006 I hope it would be helpful for you
@@Srinivas-uw6lm thanks brotha
🔥🔥🔥🔥🔥
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90:56
57:56
B
❤
Sir new syllabus topics
thank you sir.
Is this video helpful for neet
Yah of course
Sir neet
Last question answer B
Ss
How??
Can anyone share the ncert channel link...
sir it is good
Thank you so much sir
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sir ncert channel la videos podunga pls
After reaching 5L followers
@@rajandarun149Link please
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Sir neega CBSE ku matum tha edupigala 🙄🙄🙄🙄
XY2 is answer
Sir I am able to solve only few sums😢😢
b
A2d❤
last questions answer b
vv gud
A
Sir teach social also
sir salary 😂
₹n+1
n=99999999.....n times
😂
Ad²
X2Y
xy3
😊😊😊
Sir ur channel name
Ad2
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SUPER SIR
Ad²
X²Y
ADad
,💯
$³
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🎉🎉🎉
Thank you sir
Ad²
B
X2Y
Ad²
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B