in another video on an example i used the technique used here on the second example and i thought i was wrong thank you for assuring me that it is a good technique i used it on the second one here as well
When I did such proofs in college maths the tutor would demand the end of proof to be stated as 'Therefore by the Principle of Mathematical Induction statement is true for all n (Natural Numbers).
Thank you for the comment! You mean this (k^2(k+1)^2 + 4(k+1)^3)/4?. You can actually factor out the cube which will be now (k^2(k+1)^2 + 4(k+1)(k+1)^2)/4. And simplifying it, the expression will be now ((k+1)^2(k^2+4(k+1)))/4
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in another video on an example i used the technique used here on the second example and i thought i was wrong thank you for assuring me that it is a good technique i used it on the second one here as well
Excellent session. cant speak highly enough of the outcome
Thank you so much sir.
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When I did such proofs in college maths the tutor would demand the end of proof to be stated as
'Therefore by the Principle of Mathematical Induction statement is true for all n (Natural Numbers).
Good
best 💯💯💯💯
using natural numbers, why didn't you use zero instead of one because natural number starts from zero?
Nice
you made mistake in 7th minute , there is k(squares)+ 4*(k+1) ,and you forget the cube of (k+1) , its changes the whole solution
Thank you for the comment! You mean this (k^2(k+1)^2 + 4(k+1)^3)/4?. You can actually factor out the cube which will be now (k^2(k+1)^2 + 4(k+1)(k+1)^2)/4. And simplifying it, the expression will be now ((k+1)^2(k^2+4(k+1)))/4
Done raterta i learn a lot
Spavanlo
Il
I learn a lot but im gonna memories to night
why did the raise to 3 in 4(k+1)³ disappeared?
because (k+1)² is factored out
4(k+1)³ = 4(k+1)(k+1)²
@@emmanuelescol ohh Thank you 😊
Hoyy Francois Michelle B. Teves
nii bareeda
Ohmaayy memories XD
hahahah plus 5!
@@emmanuelescol hahahaha therefore the statement is true that Winx is Cool