@@bdafeesh the bat went straight up and came straight back down like that makes zero sense for how long it was in the air and how soft he threw that thing so yeah a bird caught it and then dropped it makes more sense
Or just realize the velocity is zero at the top, divide 11.83 by 2 square it and multiply by 9.8, gives you the answer. ((11.83/2)^2)*9.8= 317.285 meters. Then you realize thats impossible and the bat got stuck in a tree.
@@thenathanthomasno need to divide by 2 twice. Additionally, we should use the expression 4.9(t/2)^2 to find the height. This is derived from integrating a=9.8 to get v=9.8t, then further integrating velocity to arrive at x(t)=4.9t^2. Suppose t to equal 11.83/2. Plugging this in for t yields approximately 171m.
Had to be stuck in something. Isnt gravity about 32ft/second/second? Meaning that thing would have had quite the aerial journey were it actually flying the whole time.
Or you can just assume that half the time was spent falling then use the apex as your starting time. Therefore, both your initial conditions are zero and you use half the time so 171.4m = 557ft. He did not actually throw the bat this high.
Since the bat is rotating, you have to calculate this using its center of mass, not the tip of the bat. Tho, your answer will still be very close as is.
@@murcurialmuroid5850 No, it doesn't matter. The initial and ending velocity would be about 200 feet per second. A difference of 2 feet is a difference of about 1%. That means that, when he starts and stops the stopwatch to measure the time in the air, the initial position will be off by 2 feet for every 1/100th of a second the timing is off. That's less than the framerate of this video. Which means, 2 feet difference in starting position is well within the margin of error for the calculation.
Thank you for looking for it! It was posted Oct 24, 2023. The title is "How high was the throw?" There should be a link on this short, but if the link doesn't work hopefully you can search for it.
@@AndyMath Found it, thanks. However the results are surprisingly disappointing as they seem absolutely unrealistic. Unless the guy's name is Clark, of course.
Technically this is incorrect because you are assuming the bat is a particle. You would need to model it is a rotational and translation model for the true height
You could just use the frame rate of the camera and the length of the bat to realise the bat is only barely going fast enough to get caught in the cage above the batter before it dislodges and falls back down
It is clear from the amount of energy he put into the bat... that it was just a toss. For a bat to ACTUALLY stay aloft for that long... he would have to swing the bat from the ground up while fully extending his body. Judging from the teammates' reactions... this was a setup. Most likely a lifting boom out of frame with a guy that caught & held the bat and then let it go.
Aside from the question of the legitimacy of the video, wouldn't 11.83 be the final time at which the bat returns to the ground and the time at peak height is half the final time?
if the bat followed a ballistic trajectory, then v0 would be 4.9 *11.83 m/s. but... it's impossible that it did. firstly, the dude only gently tossed it up, which means it got caught on something like a tree, or a chain link cage. secondly, even if he did actually toss it up at the predicted 130 mph, that's close enough to the bat's terminal velocity that it would alter the trajectory from being ballistic to being more complicated, which means that it wouldn't be in the air for that long.
you're the sort of student who I end up having to tutor for their entire academic career, because you're just too dumb to understand what's happening. you can do the math just fine, but you have absolutely no clue why you're doing it or what it means.
I think a wiffle ball bat is going to reach terminal velocity if there wasnt an obstruction (net/tree limb). And that would of course be some enormously exceeded human limitations 😅 but im sure this is addressed in the full video lol
This is literally impossible. With the-clear to see-amount of force he used, the bat wouldn’t have gone up for six seconds… it would’ve had to be launched from canon to get anything like those results. My theory:it got caught on whatever piece of the cage was reaching over the field. No he didn’t THROW it that hard.
I don’t know what the hell buddy was talkin’ about but according to MY math , that went high enough to come down and kill somebody 😆! Ain’t no way it was in the air for that long for everyone to forgot about it like it was already put away 😮
the original formula is gt^2/2. g is the gravitional force of the earth so it's 9.8 m/s^2, because it's working against the way of the bat (bat goes up, and earth pulls it back down) it is a minus, which gives -9.8/2 = -4.9
Basically the bat would have fallen for 6.5 seconds. The displacement vs time function for freefall is y(t)=16t^2. So if the video is to be interpreted as simply throwing the bat up into the air and back down, the height it reached would be 16*6.5^2, or about 675 feet.
![KSI - Thick Of It (feat. Trippie Redd) [Official Music Video]](http://i.ytimg.com/vi/At8v_Yc044Y/mqdefault.jpg)
The bat got about 10ft off the ground because it was in a tree branch......
Or you can just realize that it caught the cage and finally fell out I don't know
Even a tree branch would make sense, yea
@@bdafeesh the bat went straight up and came straight back down like that makes zero sense for how long it was in the air and how soft he threw that thing so yeah a bird caught it and then dropped it makes more sense
💀
Yea if you pay very close attention you can see the vibration from the impact of the bat on the cage go through the orange zip tie.
Was about to say this
It would be 171 meters or 563 feet which would be insane. Got stuck on the top net
171 meters is exactly 570 simplified feet
171m is 561ft.... How is everyone here wrong @@FebruaryHas30Days
🎯🎯🎯👍
Well I’ll be damned 😅
Or just realize the velocity is zero at the top, divide 11.83 by 2 square it and multiply by 9.8, gives you the answer. ((11.83/2)^2)*9.8= 317.285 meters. Then you realize thats impossible and the bat got stuck in a tree.
You're off by a factor of 2. But, yeah, really high
@stephenfreeman5490 you're right, I forgot to divide by 2, my bad the correct height would be ((11.38/2)^2*9.8)/2= 158.75m
@@thenathanthomasno need to divide by 2 twice. Additionally, we should use the expression 4.9(t/2)^2 to find the height. This is derived from integrating a=9.8 to get v=9.8t, then further integrating velocity to arrive at x(t)=4.9t^2. Suppose t to equal 11.83/2. Plugging this in for t yields approximately 171m.
Could the rotation cause it to remain going up but slower. Like a spinning wheel stone is lighter to lift if you go with the rotation
@@LuckyTheSaintno. Not in a case like this
It's more likely it got stuck on some tree above
The bat reached the height of: I don't want to play baseball with you because you endanger other players.
I think this guy is smart enough to know that it wasn't really in the air that long
Bro just casually trew that bat into the stratosphere
That’s when Jesus said, “You only see one pair of footprints because I was carrying your bat for 11.83 seconds.” How. Exciting.
Dying thank you
Had to be stuck in something. Isnt gravity about 32ft/second/second? Meaning that thing would have had quite the aerial journey were it actually flying the whole time.
Gravity is also -9.8m/s² but for some reason it was halved
@@zephthezquirrellord Acceleration is the second derivative of position. That's where the 1/2 factor comes from. 1/2at^2
An eagle mistook it for a chicken leg.
So, he threw it 40 stories high?
Or, more than likely, the video is edited and fake.
There's probably a callers box with a roof right behind the triangle....
Information is important and this proves it.
Thanks for finishing
Btw he used -4.9 t² because the derivation would be 9.8m/s² which is the gravity constant (sorry for bad English am from GER)
It looks to be a hollow plastic bat, air resistance will make a huge difference
Yeah...no
Where does the -4.9 coefficient come from??
Or you can just assume that half the time was spent falling then use the apex as your starting time. Therefore, both your initial conditions are zero and you use half the time so 171.4m = 557ft. He did not actually throw the bat this high.
Tree.
Since the bat is rotating, you have to calculate this using its center of mass, not the tip of the bat. Tho, your answer will still be very close as is.
It's within the margin of error since it isn't actually starting from the ground.
@@murcurialmuroid5850 No, it doesn't matter. The initial and ending velocity would be about 200 feet per second. A difference of 2 feet is a difference of about 1%. That means that, when he starts and stops the stopwatch to measure the time in the air, the initial position will be off by 2 feet for every 1/100th of a second the timing is off. That's less than the framerate of this video. Which means, 2 feet difference in starting position is well within the margin of error for the calculation.
@@dbridges82 It. Was. Sarcasm.
@@murcurialmuroid5850 Oh... Good one.
thank you for doing that. a true hero. maths for the win!
Around 171m
Could you may be half the time and figure out how high 5.5 ish seconds would take to drop if you know what i mean and just multiply by 2
Tricking ppl to do math. You almost had me.
Theoretically you must throw it 57.84m/s up and that's not even factoring air resistance
Where’s the full video? Not on your regular channel at this time.
Right I’m now curious how high was the bat
Thank you for looking for it! It was posted Oct 24, 2023. The title is "How high was the throw?" There should be a link on this short, but if the link doesn't work hopefully you can search for it.
@@AndyMath
Found it, thanks.
However the results are surprisingly disappointing as they seem absolutely unrealistic. Unless the guy's name is Clark, of course.
Screw you for not showing the answer. I see why you don’t have many subs. Garbage.
How did you get -4.8t squared?
You ever think that he threw the bat behind him an then 11 seconds later someone else threw the bag back. Logic over maths
Real physics gs use the intial velocity of zero and 1/2t as the time to drop from peak to ground. D=1/2at^2
It also changed direction mid flight lands not at predicted place
He threw it higher than the Statue of Liberty.
Technically this is incorrect because you are assuming the bat is a particle. You would need to model it is a rotational and translation model for the true height
You could just use the frame rate of the camera and the length of the bat to realise the bat is only barely going fast enough to get caught in the cage above the batter before it dislodges and falls back down
It is clear from the amount of energy he put into the bat... that it was just a toss.
For a bat to ACTUALLY stay aloft for that long... he would have to swing the bat from the ground up while fully extending his body.
Judging from the teammates' reactions... this was a setup. Most likely a lifting boom out of frame with a guy that caught & held the bat and then let it go.
This is like borderline shitpost and I love it
Roughly 175m, you're lucky I just started learning physics
So he just casually softly threw a bat 150 ft in the air? What else
@@YG-kk4ey actually, i just recalculated and it's more than that
@@YG-kk4ey 175m is closer to 400 ft
Pov resistance left the chat
Based on the footage the initial speed is around 10 m/s, but according to the calculation the initial speed should have been around 60 m/s. Wind?
Also to keep in mind the spinning on the bat, how fast the bat is spinning it has to do alot.
The bat got stuck in the cage above the batters box. And fell out 11 seconds later..
What about the spin on the bat
That's what I was saying. The spin. But either way there is no way he threw it up that high. I had to have gotten caught in something.
How did you say parabola again?
Punts have 4-5 seconds hang time, for 10 seconds it would be 3 times as high, so, no.
This guy just broke physics. The strength of the throw and the speed the bat left his hand doesn't match the time the bat spent spent in the air
Aside from the question of the legitimacy of the video, wouldn't 11.83 be the final time at which the bat returns to the ground and the time at peak height is half the final time?
The bat wasnt thrown off the floor originally, so whatever you get should add an extra h feet
He didn't throw it, he just flicked his wrist, so I'm guessing it got caught in something
What in the physics question is this. I swear I got the exact same time for one of my physics tests lmao
Sorry, where is -4.9 from?
It went over the fence and someone there it back over.
So interesting that everyone ifnored the fact that the bat entered space😂
yh there is no way that just went straight up.
if the bat followed a ballistic trajectory, then v0 would be 4.9 *11.83 m/s. but... it's impossible that it did.
firstly, the dude only gently tossed it up, which means it got caught on something like a tree, or a chain link cage. secondly, even if he did actually toss it up at the predicted 130 mph, that's close enough to the bat's terminal velocity that it would alter the trajectory from being ballistic to being more complicated, which means that it wouldn't be in the air for that long.
you're the sort of student who I end up having to tutor for their entire academic career, because you're just too dumb to understand what's happening.
you can do the math just fine, but you have absolutely no clue why you're doing it or what it means.
I think a wiffle ball bat is going to reach terminal velocity if there wasnt an obstruction (net/tree limb). And that would of course be some enormously exceeded human limitations 😅 but im sure this is addressed in the full video lol
AND THEY STAY THEEERE
The kid tossed it behind the camera and then someone picked it up and tossed it back
And this is why math is important, but asking the right questions *before* you math, is *more* important. Context folks!
How about it flipped over to someone off screen - then they flipped it back in 🧐
Where does the 4.9 come from?
1/2 gravitational acceleration. (9.8m.s-2)
171 meters, or higher than a 50 story building. Also, he threw the bat at over 200 km/hr.
Drag has entered the chat
Looks like he threw it backwards and someone threw it back in after 11 seconds to me.
Impossible, there is a simple explanation, definitely something we can’t see on the screen.
This is literally impossible. With the-clear to see-amount of force he used, the bat wouldn’t have gone up for six seconds… it would’ve had to be launched from canon to get anything like those results. My theory:it got caught on whatever piece of the cage was reaching over the field. No he didn’t THROW it that hard.
Anyone ever seen the movie PI?
560ish feet
The answer is Flubber
About 171.5 meters
This gives me STEM ptsd
He threw it up a quarter mile, cause 11 secs is faster than any car on the street can do a 1/4 mile
They usually don’t put trees inside of baseball fields
But they do put a cage
It hit the cage…
It probably got stuck in an off camera tree or something
171 meters.
When you've just learned GCSE physics:
bruh where did 4.9 come from
On the way down it fell 33 feet per second.
Then it picked up more speed so your math is wrong.
Bat hit the 4th plan that didn't make it to towers
He did not throw the bat that high it may have gotten stuck in the tree he's right-handed you threw it up with his left hand
I don’t know what the hell buddy was talkin’ about but according to MY math , that went high enough to come down and kill somebody 😆! Ain’t no way it was in the air for that long for everyone to forgot about it like it was already put away 😮
This guy trying to calculate everything but the net above
you are not taking into account the bat rotation...
Answer is: very high... 😂🤣
Actually this is Rhythm Heaven's exhibition match :/
He barely threw it up
It got stuck in a tree
Your equation doesn’t factor in video editing
How do you come to the conclusion that it should be -4.9?
the original formula is gt^2/2. g is the gravitional force of the earth so it's 9.8 m/s^2, because it's working against the way of the bat (bat goes up, and earth pulls it back down) it is a minus, which gives -9.8/2 = -4.9
@@guysgamer582 exactly. He should’ve put -4,9m/s^2 though
Can't get the initial velocity from that formula, so the rest is guesswork.
Or somebody was up there and caught the bat.
Does my dude acutely actually think this guy threw a bat 400ft up?
parabola ❌
praabolaww ✔️
Exactly this dudes IQ is problow if I had to guess
I love how he doesn't answer the question
his graphics level is low, it wasnt rendered
wait, how high are you?
Kinematics
more please more
F you for not giving me the answer in the short.
womp womp
womp womp
womp womp
Basically the bat would have fallen for 6.5 seconds.
The displacement vs time function for freefall is y(t)=16t^2.
So if the video is to be interpreted as simply throwing the bat up into the air and back down, the height it reached would be 16*6.5^2, or about 675 feet.
theres a link to the rest of the vid right there
forgot about gravity
Obviously it landed on a roof or caught in tree branches. This is why physics is understanding how the world works not math.
171,6m without Air resistance.
All these comments obvsly not getting the joke lmao