This presentation deserves far much more appreciation and attention than it has received. Seriously, only 14k views and 117 Likes in 5 years?! I found this video immensely helpful - especially the SketchUp 3D models of the sheets and layers - and have a much better understanding of clay minerals now. Thank you so much for creating and uploading!
Have been trawling the internet for exactly the information provided in this lecture. Very nice structure and breakdown, really appreciated the recap on primary and secondary bonding.
In the section about surface charges at 21:20 he says if we replace 4O2- on the tetrahedral sheet with OH1- on the octahedral sheet a bond is created that balances the negative charge of the tetrahedral sheet. What is the chemistry behind this bond? How does this balance?
I will simplify it. We have +4 on si and -2 on O so (Si4O10) will give overall -4. If we take 4 O ion then it will become 16-(4*2)=+8 and replace it with 4OH- we will get (8-4=+4). Overall it will have 4Si 6O and 4OH and overall charge is 0.
This presentation deserves far much more appreciation and attention than it has received. Seriously, only 14k views and 117 Likes in 5 years?! I found this video immensely helpful - especially the SketchUp 3D models of the sheets and layers - and have a much better understanding of clay minerals now. Thank you so much for creating and uploading!
You are right. This video deserves more views and likes.
Have been trawling the internet for exactly the information provided in this lecture. Very nice structure and breakdown, really appreciated the recap on primary and secondary bonding.
Thank you, prof. for explanation. I really enjoyed this lecture.
Excellent. Thanks
nice work thanks a lot.
In the section about surface charges at 21:20 he says if we replace 4O2- on the tetrahedral sheet with OH1- on the octahedral sheet a bond is created that balances the negative charge of the tetrahedral sheet. What is the chemistry behind this bond? How does this balance?
I will simplify it. We have +4 on si and -2 on O so (Si4O10) will give overall -4. If we take 4 O ion then it will become 16-(4*2)=+8 and replace it with 4OH- we will get (8-4=+4). Overall it will have 4Si 6O and 4OH and overall charge is 0.
Thank you
I think 84% of the clay materials are 'lost', not 74%. (100-12-4 = 84)
please share the sketchup with us? any link? Its gonna help me a lot
If one Al is 3+, then why are there six OH's around ONE Al ion? For the octahedron...
That would make it net negative 3-
can i just know how on earth ms powerpoint gives this kinda background with all these extensions like pen, eraser and all?????
I think he's using an ipad or something to present from...which would have features like this.
Nice