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Thanks for the amazing explanation!! By the way will you upload Past Papers of A2 Chemistry in the near future? You're an amazing teacher and I'd love to learn more from you!
@LucidMindChem Assalam o alaikum Sir, in Q:10 calculation of Kp 21:00 you did not include the calculations of partial pressure, is it because the temperature is kept constant, kindly clarify..
the best chemistry tutor. sir i also had a question in q22 ( 45:40 ) why was the nomenclature of cooh not taken as no.1? as the priority of that functional group is the highest? you mentioned how you had cooh on the first carbon and also the carbon before ketone is 1st i dont understand
sir for question 19, can you please tell me which topic i could learn about ammonia salt reacting with NaOH? I find really really hard to figure out what the products are when two compounds react together. Do i just have to memorise all these reactions?
hi sir! thank you for your clear explanation. In Q8 , where do you got those informations about the bond energy? will it provide in the exam? also in Q30, will the infra-red spectrum table provide in the real exam?
In Q.40 can't sulfuric acid oxidize an aldehyde? I know there aren't any direct reactions we have studied, but we know that sulfuric acid is an oxidizing agent, so can't it oxidize aldehyde to a carboxylic acid?
No we can't use only sulphuric acid. At higher levels you will come across aldehyde polymerisation reaction. e.g. Acetaldehyde polymerises in presence of mineral acids like HCl, H2SO4 and H3PO4. A cyclic trimer called paraldehyde (2,4,6- Trimethyl - 1,3,5 - trioxan) is formed.
Sir for Q 20, for the 3rd and 4th chiral centers, if you add a hydrogen, wouldn’t that make it 5 bonds to the carbon atom instead of 4, shouldn’t there only be 4 bonds, for example in the 4th chiral center, the bonds are c=c, c-ch3 and c-ch2, that’s 4 bonds right?, why would there be another c-H bond?
@@LucidMindChem ok great to see such innovative teachers in our country😊😊 .....I am just learning chemistry from your videos since the whole day today....just discovered you today
@@LucidMindChem you know what am just so interested to know bout you... 🙃 I mean.. things like your age.. city.. education... whether you did O/A level or sth else... en more stuff like that how bout you make a video on this🥺 plzzzzzzz plzzzzz plzzzzz am sooooo curious🥺🙏🏽🙏🏽 p.s. plz do tell, at least, whether or not you'll consider this request.. will b waiting😌 AND BTW WHY NOT???🥺🥺
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cant be happier to see this perfect explanation to the paper
Now I don't regret taking chemistry and all the credit goes to you, thank you sooo much for explaining everything in details❤️
I’ve got my exam in 3 hours and your videos are extremely helpful for revision
Thank you so much
How did you do?
Thank you so much Sir! You can’t imagine how grateful I am for your cie lectures!!
i must say, i learnt redox entirely from your videos. your explanations are spot on; cant donate but will certainly share your channel!
sir i seriously dont know how to thank you enough, you are a life saver god bless you 😭😭
thank you for the examples drawing in from relative topics for each question. really helps to build a context and understand the questions better.
Thanks for the amazing explanation!!
By the way will you upload Past Papers of A2 Chemistry in the near future?
You're an amazing teacher and I'd love to learn more from you!
My favourite chemistry channels, (organic chem tutor and Lucid Mind)
Perfectly explained!!! You cleared all my doubts, even I could understand the concepts that weren't clear to me !!!
I hope your channels gets a million subs one day the way u explain kudos
@LucidMindChem
Assalam o alaikum Sir,
in Q:10 calculation of Kp 21:00 you did not include the calculations of partial pressure, is it because the temperature is kept constant, kindly clarify..
Thank You so much sir
You are a gem teacher for me
Thanks for the so-clear solutions
Dis man iz juzt AMMMMAAAAZZZIIINNGGGGGG!!
LIFEEE SAVERRR!
We can't thenk ye enough 🤧😭
Aur samaj ma naiii aa raya k kiaa likhu mai😫😫
Thenkssss again😢🫂
Thank you so much for making these videos where you step by step solve them. Amazing video!
best explanations out there for a level chemistry
Thank you so much your explanations helped me understand in such great depth 🩷 please keep making more videos 🙏🏼
What a wonderful explanation of q20
In question 26, 57:00 doesn’t hex-1-ene and hex-2-ene have chain isomerism aswell ( for example 5-methylpent-1-ene) ? Why didn’t u count those?
SIR CAN U PLEASE MAKE A VIDEO EXPLAINING PAPER 13 OF 2021 MAY JUNE I HAVE MY EXAM THE DAY AFTER TOMORROW AND I JUST DONT UNDERSTAND SOME QUESTIONS
gl fam, i got it tmrw 😢
@@cosmiceraser omg good luck to you too!! Also thanks :)
Can you explain more on number 8 as in why are you adding? Why not the normal enthalpy change that is the products minus the reactants
Thank you sir, you are a gem.
Thanks a lot, it really helped alot.
Also can you please do may june 2021/13 variant.
Thank you Sir. Great clear explanation
the best chemistry tutor. sir i also had a question
in q22 ( 45:40 ) why was the nomenclature of cooh not taken as no.1? as the priority of that functional group is the highest?
you mentioned how you had cooh on the first carbon and also the carbon before ketone is 1st i dont understand
@45:56 Sir how did ye numbered compound Y??? *Carboxylic acid* got 1st en *ketone* got 2nd??? But how? 😭😫
this helps alottt. jazakAllah
Very well explained
Great explanation, thank you for the video!
21:26 why did you use moles, shouldn't we calculate the partical pressure?
thank you
this video is very use full
Don't actually have words to praise ur teaching style and explanation. So perfect.
.
.
.
p.s kindly tell why didn't u count wavenumber before 1500?
Below 1500 lies fingerprint region, Above 1500 to 4000 is functional group region.
Most of functional groups can be identified from 1500-4000.
@@LucidMindChem okay, thanks Sir.
sir for question 19, can you please tell me which topic i could learn about ammonia salt reacting with NaOH? I find really really hard to figure out what the products are when two compounds react together. Do i just have to memorise all these reactions?
You can find these reactions in NITROGEN AND SULFUR chapter in Roger Norris Book
느금마 ㅋㅋ
Best in the wholr world.
sir for question 10, arent we supposed to use partial pressure and not moles??
You re the best man
hi sir! thank you for your clear explanation. In Q8 , where do you got those informations about the bond energy? will it provide in the exam? also in Q30, will the infra-red spectrum table provide in the real exam?
Yes, information about values will be given in exams
Which app do you use
In Q 35 , al2o3 becomes a complex ion in water and H+ is released…so will it not decrease the ph and make it slightly acidic?????
No Al2O3 doesn't dissolve in water.
It is AlCl3 that dissolves to form complex and acidic solution.
legends few hours before paper
In Q.40 can't sulfuric acid oxidize an aldehyde? I know there aren't any direct reactions we have studied, but we know that sulfuric acid is an oxidizing agent, so can't it oxidize aldehyde to a carboxylic acid?
No we can't use only sulphuric acid. At higher levels you will come across aldehyde polymerisation reaction. e.g. Acetaldehyde polymerises in presence of mineral acids like HCl, H2SO4 and H3PO4. A cyclic trimer called paraldehyde (2,4,6- Trimethyl - 1,3,5 - trioxan) is formed.
sir, in qs 10 why r we using moles to calculate Kp and not partial pressures? plz help urgent
At constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.
Sir for Q 20, for the 3rd and 4th chiral centers, if you add a hydrogen, wouldn’t that make it 5 bonds to the carbon atom instead of 4, shouldn’t there only be 4 bonds, for example in the 4th chiral center, the bonds are c=c, c-ch3 and c-ch2, that’s 4 bonds right?, why would there be another c-H bond?
After addition of Hydrogen there will no longer be double bonds, All bonds will become single covalent.
I understand now sir, thank you so much
sir can u plz upload more solved solutions of mcqs please for As
in Q6 what is mean by " resistant to change shape" how can i konw it
Thank you🙏🏽
Thank you sir
Thank you!
Hi, thank you for the very useful video! May Allah bless you.
I have a question regarding question 23, why isn't H free radical an answer?
H free radical is never formed in free radical substitution of alkanes instead HBr is formed.
@@LucidMindChem homolytic fission would only happen with the halogen molecule is it?
Yes
@@LucidMindChem thank you for the reply 😁
Thank you soo much, could you please solve 13 variant of this as wel? I'd be so grateful!
ok i just took 9701 w21 paper 13 rn its so fuckijng hard, even after solving past paper questions p13 was so cancerous
can u pleasee upload 2021 summer paper 13 @Lucid Mind
Thank you so much
thank you
thank u soo much
Hello sir do u give tutions?
Yes i do
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are you from pakistan.....?
Yes, indeed.
@@LucidMindChem ok great to see such innovative teachers in our country😊😊 .....I am just learning chemistry from your videos since the whole day today....just discovered you today
@@LucidMindChem you know what am just so interested to know bout you... 🙃
I mean.. things like your age.. city.. education... whether you did O/A level or sth else... en more stuff like that
how bout you make a video on this🥺
plzzzzzzz plzzzzz plzzzzz
am sooooo curious🥺🙏🏽🙏🏽
p.s. plz do tell, at least, whether or not you'll consider this request.. will b waiting😌
AND BTW WHY NOT???🥺🥺
Please solve October November 17
Plz do 15 and 17 too
Captions remove
thanks sir
thank you
thank you