Thanks. The question was to find the equation of angle bisector. Both the equations are provided. Yes, It can be taken as part 2 of the solution to find which is acute angle bisector. Appreciate your feedback. Thanks
Thanks for the question. Here is the link for the video to find obtuse angle bisector. You can get the acute angle condition also. Hope that helps.ruclips.net/video/MGM4CUPlTA0/видео.html
Sir why there is ± sign instead of a positive sign? I mean why the left side of the equation comes up to be positive and the right side has two signs(±)
If we follow steps of construction we can get a method for finding equation of angle bisectors 1. Solve the system of equations 3x+4y=5 12x+5y=7 to get coordinates of intersection point and call if point A Choose the point on the line 3x+4x=5 (f.e. B = (3,-1) ) Calculate distance from A to B Write equation of the circle with center at A and radius AB Solve the system of equations (x-xA)^2+(y-yA)^2=|AB|^2 12x+5y=7 to get two points Ck (k=1 and k=2) For each point Ck do the following Write equation for the line through the points Ck and B Write equation for the line perpendicular to the line CkB through the point A
Thanks but sir can you chech your first equation I hope it should be -3(7x-9y+10) instead
Yes, that is right. Thanks
Yes u are right
I dont why why this video seems sooo satisfying 😁😌
ASMR voice
what about, x+y-2=0 and 2x-3=0?
Kindly check the 3(7x-9y+30)=0 sir
thank you for this video, I understand it now.
Thanks for sharing and All the Best!
Thanks prof you are just a wonderful person
@@MathematicsTutor sir how to find acute and obtuse
Welcome
Thank you sir
how to know which line that divides the small angle and which line that divides the bigger angle?
Angle between the lines: ruclips.net/video/WKmWmq8Zd5E/видео.html
Thanks
🎉
sir you first eqn is wrong
The equation of the bisector of an angle between the lines x-y+2=0 , 7x+y+1=0
Sir I am not getting this problem can u please explain
Check this video: ruclips.net/video/MGM4CUPlTA0/видео.html
If you don't get let me know what you don't get. Then I will try to help. Thanks
For the 1st equation denominator is√2 and for 2nd equation denominator is √50
After I am not getting sir
sir why didnt u apply +- on L.H.S after opening the modulus??
Because you get the same equations . No matter you put +-, so one side is enough to get the equation
@@salukaranapura6031 are u still alive after 3 yrs?
1 Find the equation of bisector of line x+2y+3=0 and 2x+3y+5=0.
Follow the method described in the video to get the solution. Thanks
which is acute? you missed the most important point
Thanks. The question was to find the equation of angle bisector. Both the equations are provided.
Yes, It can be taken as part 2 of the solution to find which is acute angle bisector. Appreciate your feedback. Thanks
Sorry to bother you, i just found the other video. Thanks
Here is one for obtuse angle: ruclips.net/video/MGM4CUPlTA0/видео.html
Anil Kumar how do we know which one is for acute
Thanks for the question. Here is the link for the video to find obtuse angle bisector. You can get the acute angle condition also. Hope that helps.ruclips.net/video/MGM4CUPlTA0/видео.html
One of the final answers is incorrect.
The lines are:
- 7x - 9y + 10 = 0
- 99x + 77y - 100 = 0
Sir why there is ± sign instead of a positive sign?
I mean why the left side of the equation comes up to be positive and the right side has two signs(±)
|x| = |y| --> x = (+ or - )y
Because we don't know the about the signs of x and y
@@dhirajjadhav2022 thank you brother but, I don't understand.
What ballpen do you use?
❤️🔥🫶🏻
For any homogeneous curve of form ax²+2hxy+by², equation of pair of angle bisector is [(x² - y²)/(a-b)]=(xy)/h
If we follow steps of construction we can get a method for finding equation of angle bisectors
1. Solve the system of equations
3x+4y=5
12x+5y=7
to get coordinates of intersection point and call if point A
Choose the point on the line 3x+4x=5 (f.e. B = (3,-1) )
Calculate distance from A to B
Write equation of the circle with center at A and radius AB
Solve the system of equations
(x-xA)^2+(y-yA)^2=|AB|^2
12x+5y=7
to get two points Ck (k=1 and k=2)
For each point Ck do the following
Write equation for the line through the points Ck and B
Write equation for the line perpendicular to the line CkB through the point A
If we divide the first equation by negative 3, the answer will be 7x-9y+10=0.
I applied it to normal vector equations and it worked....Thanks alot!!
could you type out how you did that please?
You are good. God bless you
i loved it.........i was rushing to comment until i got pin comment
thanks alot that rly helped...
Strijder❤
Kya h yr ye kuch dik ni ra ache se
it is perfectly fine on my screen.
thanks
Thank u