The Key to the Riemann Hypothesis - Numberphile

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  • Опубликовано: 26 дек 2024

Комментарии • 1,1 тыс.

  • @monkeseeaction21987
    @monkeseeaction21987 3 года назад +399

    Mathematicians: can't solve Riemann hypothesis
    Also mathematicians: *best we can do is to come up with infinitely many more unsolved Riemann hypotheses*

    • @py10playz82
      @py10playz82 3 года назад +3

      😂😂

    • @roiburshtein852
      @roiburshtein852 2 года назад +1

      Lol yeah

    • @vez3834
      @vez3834 2 года назад +40

      To explain why mathematicians do this: If you can engineer new Riemann hypotheses, you can study them as a whole. It's sort of like if we found life from beyond Earth, we would be able to study what "life" even is and how it can be. Now, if we can somehow solve one of these engineered ones, maybe we can use that solution to somehow solve the original one. At least we would have a framework for how it could be done.
      I do appreciate the joke though! I just thought it's valuable to understand exactly why this stuff is important. Mathematicians don't like to assume something is special, that too has to be proven :)

  • @DaviddeKloet
    @DaviddeKloet 8 лет назад +664

    Brady, always asking the right questions, invisibly making his videos awesome.

    • @NoriMori1992
      @NoriMori1992 8 лет назад +60

      +David de Kloet Brady acts as the audience surrogate, probably very deliberately. I'm sure many of the questions he asks are things he himself is wondering, but I'm sure he also asks questions he already knows the answer to, because he knows the viewers will have the same question. He's very good at this role. :)

    • @reggyreptinall9598
      @reggyreptinall9598 3 года назад +1

      I found it

  • @andrerenault
    @andrerenault 2 года назад +33

    This is probably the clearest video I’ve seen about the Riemann hypothesis. Most seem to focus on the setup and are kind of murky around the applications or the actual problem, but this one tackled the zeros very well.

  • @boenrobot
    @boenrobot 8 лет назад +1248

    7:16 - Only in math can you get infinitely many rare things.

    • @wayneosaur
      @wayneosaur 8 лет назад +61

      +boenrobot Yes. Things that are only "countably infinite" (like the integers) are rare compares to the reals (which are "uncountably infinite").

    • @PeterGeras
      @PeterGeras 8 лет назад +16

      +boenrobot It helps us come a little closer to appreciating the vastness of infinity. You can have numbers spread so far apart and yet still have an infinite number of them.
      Example: Set each number to be the size of a power tower. So
      n1 = 10
      n2 = 10^10 = 10 billion
      n3 = 10^10^10 = a number with 10 billion digits
      ...
      and we can fit in an infinite number of these n values...

    • @Hamatabo
      @Hamatabo 8 лет назад +21

      assuming an infinite universe there are infinitely many sets of infinitely many rare things

    • @rangedfighter
      @rangedfighter 8 лет назад +10

      +boenrobot Not really, if our universe is infinite, then life would still be rare and could aswell, be present on infinitly many planets.
      If throw a coin infinitly many times, I have infinitly many occasions of 1000 heads in a row, still they are rare.

    • @wayneosaur
      @wayneosaur 8 лет назад +7

      +Baron ultra paw Observable universe is finite and contains a finite number of particles (somewhere on the order of 10^80 particles and 9 photons per particle). About 10 billion galaxies with 100 billion stars per galaxy. Infinity is really only something that exists in mathematics.

  • @Antediluvian137
    @Antediluvian137 8 лет назад +305

    Brady - when I subscribed to Numberphile 4 years ago, I wished to learn more about concepts exactly such as this. And for 4 years I've been blown away. The service that you provide; your great contribution to spreading knowledge... it's absolutely awe-inspiring. Thank you SO MUCH for making these (seemingly) obscure and complicated topics accessible to such a wide audience. I've commented this before, but I'll say it again: you are a great asset to this world. Thank you, and please never stop!

  • @TheIcy001
    @TheIcy001 8 лет назад +48

    Awesome video! Numberphile has really come a long way! Just 4 years ago I wouldn't have even dreamed of anyone daring to bring an advanced graduate-level math topic such as this one to a broad audience while keeping the mathematics honest.

  • @alyoshakaramazov8469
    @alyoshakaramazov8469 7 лет назад +16

    This channel is the most fun a non-mathemetician can have with mathematics. Thank you!

  • @Mizziri
    @Mizziri 8 лет назад +69

    Yes! I'm always happy for more Riemann!
    I'm also very glad you're expanding to L-Functions. The thought of something that ties the Riemann Hypothesis to Fermat's Last Theorem is pretty crazy...

  • @Seth_M-T
    @Seth_M-T 8 лет назад +2967

    I've found a truly remarkable proof for this, but it's too long to fit inside one comment.

    • @detectivejonesw
      @detectivejonesw 8 лет назад +67

      😂

    • @ZardoDhieldor
      @ZardoDhieldor 8 лет назад +390

      This joke has become less funny since RUclips removed the comment length restriction! Still worth it.

    • @mage1over137
      @mage1over137 8 лет назад +9

      +Seth M-T I was about to make the same joke.

    • @villanelo1987
      @villanelo1987 8 лет назад +39

      +Seth M-T
      I have seen entire chapters of the lord of the rings posted in a single comment, though. :p
      So... maybe in 2 or 3 you would have enough space?

    • @casperes0912
      @casperes0912 8 лет назад +91

      +Seth M-T Fermat would be proud

  • @phampton6781
    @phampton6781 8 лет назад +971

    A wild Ramanujan appears.

    • @josephcrespo7822
      @josephcrespo7822 5 лет назад +77

      Quick, capture him before he dies of tuberculosis!!!

    • @jacobr7729
      @jacobr7729 5 лет назад +19

      Joseph Crespo dude...uncool

    • @NoriMori1992
      @NoriMori1992 5 лет назад +8

      @@josephcrespo7822 Or possibly hepatic amoebiasis.

    • @gavinwoodard9178
      @gavinwoodard9178 5 лет назад +3

      Jacob R yeah i hadnt gotten that far, dude totally spoiled the ending for me!

    • @IronicHavoc
      @IronicHavoc 5 лет назад +1

      @Jozef Wicks-Sharp That's just the phrasing Pokemon uses

  • @jeshudastidar
    @jeshudastidar 8 лет назад +19

    "It's not likely, but it is possible." Thank you for the encouragement! :)

    • @tim40gabby25
      @tim40gabby25 4 года назад +3

      Possible in the sense of not being impossible. A small comfort.

  • @samsonmoses7747
    @samsonmoses7747 6 лет назад +9

    I don’t have one degree in any maths, but this is one of my favorite channels.

  • @singingblueberry
    @singingblueberry 8 лет назад +59

    I believe all those connections between the Riemann-Zeta-Function, Ramanujan and Fermats last theorem are the main reason I love mathematics...however, amazing video as always.

    • @harold3802
      @harold3802 4 года назад +1

      Same

    • @G8tr1522
      @G8tr1522 2 года назад +1

      RZH is truly the only reason I still care about pure math after college.

  • @georgemissailidis3160
    @georgemissailidis3160 4 года назад +17

    8:30 multiplying out powers of 24 like that is definitely _not_ something most people can do at home - by hand. Ramanujan, what a gun mate

  • @notThePiper
    @notThePiper 8 лет назад +35

    Brady, you are very good at asking questions

  • @NickRoman
    @NickRoman 8 лет назад +1028

    There are infinitely many, but they're rare. Ah, mathematics... lol

    • @theduckster01
      @theduckster01 8 лет назад +57

      I mean, throw a dart on a dartboard. The probability that the dart lands at exactly 0.00000...... cm from the center (aka exactly the center) is zero. Kind of wacky, but makes sense. Discrete numbers are an infinitesimally small infinite subset of the continuous spectrum of real/complex numbers.

    • @ImaginaryHuman072889
      @ImaginaryHuman072889 8 лет назад +65

      kinda like saying: there are infinitely many integers that are evenly divisible by the first 80 billion prime numbers. there's infinitely many because the integers never end, but they're rare because there are massive gaps of integers that don't satisfy this.

    • @legendarylightyagamiimmanu1821
      @legendarylightyagamiimmanu1821 8 лет назад +3

      Ok ok give me the proof that there are infinitely many.

    • @Qazdar6
      @Qazdar6 6 лет назад

      great guy!

    • @MartinWoad
      @MartinWoad 6 лет назад +12

      You don't need a proof. It's an axiom. We said there are infinitely many and so there are. Numbers are abstract.

  • @crazygamingeater1448
    @crazygamingeater1448 4 года назад +12

    8:31 Never before have I been so intimidated by the phrase "Just multiply this thing out"

  • @villanelo1987
    @villanelo1987 8 лет назад +172

    "There are infinite numbers of..."
    "BUT YOU SAID THEY WERE RARE!!"
    That genuinely made me laught. Brady sounds so betrayed. xD

    • @m3keita
      @m3keita 5 лет назад +8

      "rare" has to do with their distribution. "infinite" means there is another of after each one you'd pick. the two are not mathematically, speaking, mutually exclusive.

  • @bt7496
    @bt7496 8 лет назад +57

    Video correction: Darwin did not develop his theory of evolution then go to the Galapagos. His visit inspired his theory :)

    • @mickwilson99
      @mickwilson99 5 лет назад +10

      Thank you! A distinction mathematicians might, by the nature of their craft, be prone to miss. Darwin found a puzzle, sought a theorem, presented evidence, and stood prepared to be shown misguided. Maths developes by challenge-my-proof, and physical sciences develop by challenge-my-evidential-interpretation.

  • @RSLT
    @RSLT 2 года назад +1

    The best key to Riemann Hypothesis. I highly recommend to which this video sever times.

  • @atrumluminarium
    @atrumluminarium 8 лет назад +281

    one way to figure it out: make them puzzles in a game and put it on steam. players will definitely figure it out to the point where they take complete advantage of it

    • @tatanpoker09
      @tatanpoker09 8 лет назад +27

      Or make a real life treasure hunt being the solution to this one of the steps, then post it on reddit and let it go viral

    • @royhe3154
      @royhe3154 8 лет назад +156

      tatanpoker09 or offer a one million dollar prize! Wait...

    • @atrumluminarium
      @atrumluminarium 8 лет назад +5

      LOL

    • @spacejunk2186
      @spacejunk2186 5 лет назад +3

      Post on 4chan

    • @jamirimaj6880
      @jamirimaj6880 4 года назад +5

      @@royhe3154 That seems abstract for some reason. Now put it on steam and offer LIFETIME FREE GAMES AND DOWNLOADS?!?!?! Trust me, the hypothesis would be solved in less than a month lol

  • @ZimoNitrome
    @ZimoNitrome 8 лет назад +440

    Riemann was so damn OG

  • @MatthijsvanDuin
    @MatthijsvanDuin 8 лет назад +31

    I think it should have received a mention that there's actually another class of such functions for which the Riemann hypothesis has actually been *proven* around 1940. (Search "local zeta functions" or "Riemann hypothesis for curves over finite fields")

  • @deldarel
    @deldarel 5 лет назад +62

    Ramanujan was the Mozart of mathematics in every single way. Such revolutionary people. Such a shame they died so young. They would have changed their respective fields to something we wouldn't recognise if they lived to a ripe old age.

    • @dhoyt902
      @dhoyt902 3 года назад +6

      I have to disagree. I think Euler was the Mozart. Ramanujan is John Lennon.

    • @ayooshiyer8621
      @ayooshiyer8621 3 года назад +5

      @@dhoyt902 this is tough but I would rate ramanujan slightly higher than Euler

    • @chriswebster24
      @chriswebster24 2 года назад +5

      Ramanujan wasn’t really all that smart, though, to be honest. He didn’t have any friends because he was such a nerd, and, because of that, he had all sorts of free time, so, sure, he figured out some obvious stuff while he was bored, but Euler was a true genius. He was doing calculations in the day time, and banging broads all night long. That’s why hardly anyone has ever even heard of Ramanijuana, and Euler is a hero and role model to literally everyone, everywhere. I mean, for reals, that ninja was such a legend, they even named an NFL team after him, called the Houston Eulers. Maybe when Ramanoodle gets a football team named after him he’ll be famous, too, but I wouldn’t hold my breath waiting for that to happen.

    • @VCT3333
      @VCT3333 2 года назад +6

      @@chriswebster24 😂 this is grade A trolling!!

    • @LeNoLi.
      @LeNoLi. 2 года назад +1

      @@chriswebster24 Clearly this noob hasn't heard of the LA Ramanujans aka LA Rams.

  • @youknowinhindsight
    @youknowinhindsight 8 лет назад +310

    What I would give for Galois and Ramanujan to have had average lifespans... *sigh*

    • @randomdude9135
      @randomdude9135 5 лет назад +38

      If it was possible, I'll happily give my remaining life to resurrect Ramanujan. I'm almost 19 btw.
      He and many more Mathematicians and Scientists who died young deserve more lifespan(atleast the average lifespan) than a normal person like me :)

    • @clarekuehn4372
      @clarekuehn4372 5 лет назад +2

      Lol!

    • @ericzeigler8669
      @ericzeigler8669 5 лет назад +34

      Don't forget Niels Abel. Only living to 26 because of tuberculosis, the mathematician Hermite said, " He's left us with more than 500 years worth of math to figure out."

    • @badam9656
      @badam9656 4 года назад +2

      @@ericzeigler8669 you mean 32

    • @ericzeigler8669
      @ericzeigler8669 4 года назад +3

      100 subs before quarantine ends You are correct. Thanks.

  • @TheHarboe
    @TheHarboe 8 лет назад +404

    1:49 - ζ(-1) = -1/12 = 1 + 2 + 3 + 4 + ...
    Brady, you're a sneaking fellow!

    • @rzezzy1
      @rzezzy1 8 лет назад +34

      +TheHarboe Thank you for pointing that out. Never would have noticed it!

    • @AdamW655
      @AdamW655 8 лет назад +1

      haha

    • @TheXiastro
      @TheXiastro 8 лет назад +3

      hahaha, that made my day :)

    • @adityakhanna113
      @adityakhanna113 8 лет назад +1

      More like Pete Mcpartlan did it.

    • @loupiotable
      @loupiotable 8 лет назад +12

      but it's true :)

  • @larrycornell240
    @larrycornell240 7 лет назад +5

    I’ve posted in this thread before, and once again I have to say how endearing this humility is to me. It seems to me that if there are infinitely many L-functions all having Reimann type hypotheses, and among them are the much lauded modular forms, then Riemann Hypothesis is not the answer. Rather, it is the observation of a symptom, and the cause is perhaps a deeper, most likely, much simpler idea. Following that line of reasoning, there should also exist a simpler proof of Fermat’s Last Theorem. In time I think the elegance and simplicity of this underlying principal will become known, and usher in perhaps the last great advance in our understanding of the object we call mathematics.

  • @chrisliffrig5603
    @chrisliffrig5603 8 лет назад

    I lack the ability to comprehend what this man is talking about, but love and appreciate the questions Brady presented.

  • @adamaenosh6728
    @adamaenosh6728 3 года назад +5

    What a great video! Much more informative than most about the Riemann hypothesis

  • @Verschlungen
    @Verschlungen Год назад +1

    Incredible! One of the very best summaries of the RH that I've seen -- so succinct and helpful.

  • @machineworld9495
    @machineworld9495 5 лет назад +38

    As an engineer, I'm gonna give you a rough estimate and say it's true

    • @igorswies5913
      @igorswies5913 2 года назад +3

      And then a bridge collapses, killing 100 people
      But you're happy because you won 1 million dollars

  • @eastofthegreenline3324
    @eastofthegreenline3324 7 лет назад +3

    This is a pleasure to watch. Professor Keating's introduction is clear and informal. The graphics are also helpful, as are the series of questions and historical background.

  • @funny_monke6
    @funny_monke6 8 лет назад +8

    Really loved this video! Another great one for the Riemann Hypothesis.

  • @zamkam
    @zamkam 2 года назад +2

    11:59 "you probably need to know some mathematics to understand that" LOL a bit of an understatement eh?

  • @yishaqdavid2029
    @yishaqdavid2029 8 лет назад +185

    Srinivasa Ramanujan died way too young.

  • @josan14basket
    @josan14basket 8 лет назад +405

    Well, might as well Parker-Square it. right ?

    • @ullibao
      @ullibao 8 лет назад +1

      😂😂😂

    • @Agent29416
      @Agent29416 8 лет назад

      lol

    • @PassionPopsicle
      @PassionPopsicle 8 лет назад +11

      Parker square is now a verb! This made my day

    • @PassionPopsicle
      @PassionPopsicle 8 лет назад +6

      orochimarujes Groundbreaking result! Better keep it quiet so someone else doesn't publish it first...

    • @bignatec1000
      @bignatec1000 8 лет назад +3

      Does anyone think there are 3D functions like this, with symmetric fields and planar zeros? Maybe finding these could help understand the 2D functions.

  • @Riotlight
    @Riotlight 8 лет назад +61

    8:31 - "This is something you can do at home" ... Yeah.. I think im gonna pass on that thanks!

    • @EPICPACKOPENINGSXD
      @EPICPACKOPENINGSXD 8 лет назад +10

      What? You don't wanna have FUN with Mathematics!?

    • @Ethernet3
      @Ethernet3 8 лет назад +1

      +Riotlight EZ use a computer to do it for you
      x - 24 x^2 + 252 x^3 - 1472 x^4 + 4830 x^5 - 6048 x^6 - 16744 x^7 +
      84480 x^8 - 113643 x^9 - 115920 x^10 + 534612 x^11 - 370944 x^12 -
      577738 x^13 + 401856 x^14 + 1217160 x^15 + 987136 x^16 -
      6905934 x^17 + 2727432 x^18 + 10661420 x^19 - 7109760 x^20
      etc (You need a lot of terms to get it to work though)

    • @jeffrey8770
      @jeffrey8770 8 лет назад +3

      Em how are you going to expand that stuff to the 24th power? Especially when its infinite... that'll take a while lol unless theres something im not aware of

    • @Ethernet3
      @Ethernet3 8 лет назад +2

      If you take enough factors after some amount the coefficcients you get after expanding don't change anymore. For example, let's look at the product: x(1-x)(1-x^2)(1-x^3)... In every (1-x^n) the 1 basically states "Copy everything", and the x^n produces terms between x^(n+1) and x^(n+n-1), therefore if I would cut off the product at (1-x^3), I can be certain that all coefficients from terms upto x^3 in the final expansion are correct. The same goes for (1-x^n)^24, except that (1-x^n)^24 would produce terms between x^(n+1) and x^(24n+n-1).
      It takes like 10s to expand the first 200 factors, guaranteeing everything up to x^200 to be correct. (It yields a polynomial of 482 401 terms of which only 200 have the correct coefficients though Lol)

    • @hexa3389
      @hexa3389 5 лет назад

      Grade 8 distributive property.

  • @foxyd2thegreat165
    @foxyd2thegreat165 2 года назад +1

    Hey everyone, I just figured out a wonderful proof for this... I'll leave it as an exercise for the reader. Show your work.

  • @niboe1312
    @niboe1312 8 лет назад +66

    Ramanujan is the king of the infinite series

    • @vae3716
      @vae3716 5 лет назад +4

      @Nikhil Mankar such a shame for you

  • @murrayeisenberg8072
    @murrayeisenberg8072 8 лет назад +1

    Like most "popular" expositions about the Riemann zeta function, this one has a HUGE gap almost from the very start: He begins with the definition of zeta(s) as the sum of a series, which converges only when the real part x of s = x + i y is greater than 1. Next, he states the property of symmetry across the line Real(s) = 1/2; but that makes utterly no sense unless and until one has defined what zeta(s) means when x < 0, and he has not done that.

  • @jonbaker77
    @jonbaker77 8 лет назад +5

    Why I like Numberphile: "There are infinitely many..." "But you said they were rare"

  • @levitheentity4000
    @levitheentity4000 4 года назад +5

    *youtube:* shows something I've never seen before
    *My Brain:* yes, let's go

  • @mighty8357
    @mighty8357 8 лет назад +49

    I have learned the hard way to leave the room whenever someone tries to explain anything Riemann related

    • @NoriMori1992
      @NoriMori1992 8 лет назад +2

      I have learned to leave the video. Except that for some reason I don't. XD

    • @PerthScienceClinic
      @PerthScienceClinic 5 лет назад

      And that's how your friends get you to leave parties.

  • @nakamakai5553
    @nakamakai5553 5 лет назад +1

    How can anyone understand this, and not just be completely blown away? Mind = blown. Awesome. I so love math. Maths.

  • @jeffirwin7862
    @jeffirwin7862 8 лет назад +10

    "This is something you can do at home, just multiply this thing out." [points at an infinite product]. Uhh, sure, just give me infinite time ...

  • @erikhalvorseth3950
    @erikhalvorseth3950 4 года назад +1

    Thanks for a very nice description of the Zeta-f.

  • @kokopelli314
    @kokopelli314 8 лет назад +4

    Thanks for this, in particular the Ramanujan example!

  • @СВЭП-и4ф
    @СВЭП-и4ф 4 года назад +6

    There is always a Ramanujan who came up with some crazy infinite series on any math topic

  • @ZoeTheCat
    @ZoeTheCat 8 лет назад +10

    I see Wiles quietly and secretly working on the Riemann Hypothesis in his study ever since he finally fixed his FLT proof. Twenty years and counting. Wake up. sit at desk. Go for walks. Talk to the wife/kids. Go to bed and dream about it. Wake up and do the same FOREVER!
    I'd like to think the average joe with a bit of math expertise might be able to crack it...but I don't think so. This is going to take a TRUE Mathematician with world-class skill.

    • @timh.6872
      @timh.6872 4 года назад +2

      I've been toying with it for about 5 years now, I got hooked on it after I bumped into the viral 1+2+3+4+... = -1/12 video. I'm a professional software engineer and a recreational mathematician. It's been a fun ride, mostly my "blow off" problem when I'm not dreaming up new ways to reinvent all of computer science with Homotopy Type Theory, Quantitative Type Theory, and a little something special I call Full Duality.
      I've tricked myself into thinking I've proved it about once a year. Usually a bit of exploration or redoing the algebra demonstrates my error. I've been stuck on a few lemmas this year, some nasty limits that really look like they should work but just refuse to behave when actually doing the algebra. Maybe I'll nail it down one of these days.
      Don't count us amateur mathematicians out, the crucial insight might come from not being exposed to the current methodologies.

    • @AtanasNenov
      @AtanasNenov 4 года назад

      Yep, my suspicion as well. He did the same thing for nearly a decade prior to his announcement that he solved FLT.

  • @JustinShaedo
    @JustinShaedo 8 лет назад

    I feel that this video is either going to be something already understood or beyond the current understanding of the viewers. I'd appreciate the host stepping in and explaining a little more.

  • @MrBloodyBat
    @MrBloodyBat 8 лет назад +11

    Fun fact: Darwin didn't go to the Galapagos Islands to find evidence for evolution. He was a geologist as well and wanted to study the unique geology. He noticed that there were very similar finches etc... he came back with a theory, which he then started to study. (This may not be entirely correct, I seem to have forgotten some details. e.g. he may not have been a geologist, I just remember that it had something to do with the soil or lava or something like that)

    • @michaelcooper3633
      @michaelcooper3633 7 лет назад +1

      He didn't have the theory yet until after he came back and started studying the specimens.

  • @zuhriddinnazarov5991
    @zuhriddinnazarov5991 2 года назад +2

    I love mathematics, every day i could time for it. i and i was economist. but i have been training with this subject since 2017. i have bachalor and masters degrre at the moment. i have 50 research works, two paper has been published in math journal. it is belong to probablity theory and number theory. i proofed Ferma`s theorem. it is very simple. half page is enough for it. I have a completely different conclusion about the Riemann Hypothesis. I will announce in the coming months. however, in s> 1 natural numbers, I collected the sums of the zeta functions. my name is Khodjaev Yorqin, this accaunt is belong to my friend. I can say for sure that only when the essence of all the theorems is studied, it is possible to feel their simplicity. in the future all sciences will unite again

  • @elizabethhogan1610
    @elizabethhogan1610 8 лет назад +154

    Could you please do videos about all the Millennium problems? You have videos about Poincare and Riemann, and there's a video on Computerphile that talks a bit about P vs. NP, but I think that's all you have.

  • @Moinsdeuxcat
    @Moinsdeuxcat 8 лет назад +1

    Numberphile evolves in the way it has to, I'm glad of this.
    Nice seeing some math being done and not only explanations, and nice seeing modern math (not only Fibonacci or stupid debates about pi vs tau)

  • @Naeuio
    @Naeuio 8 лет назад +19

    Mathematicians want to know the truth!
    They will accept the truth!
    This IS being humble to science.

  • @Anu_was_here
    @Anu_was_here 8 лет назад +1

    Amazing!! This the longest youtube video I couldn't understand a thing from. Well played.

    • @justinlasker6269
      @justinlasker6269 8 лет назад +1

      Ever heard of VSauce?

    • @sadrien
      @sadrien 8 лет назад

      Everything in his videos is simple... try string theory..........

  • @mkdspro64
    @mkdspro64 8 лет назад +4

    I dont understand anything, but i love this channel!

  • @jaimeafarah7445
    @jaimeafarah7445 4 года назад +1

    A proof by Andreas Speiser states that the Riemann Hypothesis is equivalent to the absence of non-trivial zeros of the derivative of the ζ(s) function in the strip 0 < Re(s) < ½
    That reduces the RH to half the critical strip. It means if one can find only one zero of the derivative of ζ(s) in the strip 0 < Re(s) < ½ , then this will be a contradiction if assuming the RH is true.

  • @mashmax98
    @mashmax98 7 лет назад +4

    i think it would be a great idea for a video to proof the euler formula for the zeta-function. It's not too complicated but really smart

  • @danielortega2441
    @danielortega2441 7 лет назад +1

    A great channel, a very special channel for the 21st century

  • @RedSkyHorizon
    @RedSkyHorizon 8 лет назад +4

    Why does Numberphile fascinate me considering that I don't even know my times tables and have never passed an exam in my life.

    • @ShinyRayquazza
      @ShinyRayquazza 8 лет назад +6

      +Tom Mulligan Because real math is much more than what you learn in school.

    • @RedSkyHorizon
      @RedSkyHorizon 8 лет назад +2

      +Shiny Rayquazza
      Its a world away from school. I wish I had the capacity to understand more. I don't know what schools are like these days but if I were a teacher I would incorporate these YT videos into my class.

  • @evalsoftserver
    @evalsoftserver 3 года назад +1

    A Solution for the RIEMANN ZETA FUNCTION is extremely valuable because It also point to Solutions for enhancing the HAMILTON GEOMETRZATION Poincare conjecture, Hodge Invariance conjecture as it relates to PRIME NUMBERS and Doing Arithmetic past ZERO or Singularity as it is called in Analytic Geometry , and Algebraic Geometry, and it Directly points to the Prime factorization Algorithm , the Division algorithm, and the QUADRIATIC FORMULA This Solves many DIMENSIONS and RANK IN THE COMPLEX FUNCTION PLANE for MANIFOLD like The Kahler MANIFOLD ,CALIBU YAU MANIFOLD simeoustanesly and Points to Soulutions to the entire Millennium Prize Problems proposed by The Early 20th Century Philospher and Mathematician David HILBERT , Including the YANG-MILL Mass GAP , and the NP COMPUTATION time space COMPLEXITY problem also know as the Traveling Salesman problem

  • @abraarmasud9194
    @abraarmasud9194 4 года назад +10

    Honestly, If I could, I would've traded some of my lifespan and given it to Ramanujan. I'm sure most will :)

    • @Bruno_Noobador
      @Bruno_Noobador 4 года назад +3

      Ramanujan would be imortal by then

  • @siddharthchavan1224
    @siddharthchavan1224 4 года назад +2

    Greatest mathematicians of all Riemann and Ramanujan what can you ask more for!!!

  • @DAK4Blizzard
    @DAK4Blizzard 8 лет назад +13

    3:28 - It's interesting that it's known "at least 40%" of the zeros are on the symmetry line. How can we be so sure at least close to half of them are on the symmetry line? Is it because, though 10^36 is still well short of infinity, there is far less frequency of prime numbers at such large magnitudes?

    • @jevanstastic
      @jevanstastic 8 лет назад +2

      +DAK4Blizzard Yes, I did not understand this part. Did he misspeak? Or is the emphasis in the wrong place? The animation does not clear up this mystery either.

    • @NuclearCraftMod
      @NuclearCraftMod 8 лет назад +15

      +DAK4Blizzard It's possible that there has been a proof that at least 40% of them lie on the line - proving the Riemann hypothesis would be showing that 100% of them lie on the line, I guess.

    • @ElchiKing
      @ElchiKing 8 лет назад +13

      +DAK4Blizzard I don't think that this has anything to do with the numbers already checked. What I guess is that you can estimate an integral which gives the ratio of numbers on the line to be at least 0.4. But I don't know.

    • @jevanstastic
      @jevanstastic 8 лет назад +1

      +Elchi King (Maddemaddigger) Smart!

    • @brokenwave6125
      @brokenwave6125 8 лет назад

      "we"?

  • @josephmathmusic
    @josephmathmusic 2 года назад +1

    Pretty magical 24-th power... (I think it is the only non-zero exponent which gives a multiplicative function)

  • @StephanvanIngen
    @StephanvanIngen 8 лет назад +9

    Wow this Ramanujan was a boss

  • @KingHim00
    @KingHim00 3 года назад +1

    I solved Riemann's hypothesis that every zero does end up on the line and I have proof to show you in a way for you to check and see if every zero ends up on a critical line

  • @jesscarter6504
    @jesscarter6504 8 лет назад +9

    OMFG!!!! Why do I insist upon watching these videos when I HATE math...and I have absolutely NO idea about which they are speaking. Not even close!!!! Yet, I can't stay away..

  • @user-vg7zv5us5r
    @user-vg7zv5us5r 2 года назад +1

    3:40 Can you just end the discussion about whether that straight line is infinitely long by referring to the induction? If it works for n+1, then it's true 'till infinity.

  • @romanr9883
    @romanr9883 8 лет назад +37

    wait, let me get my calculator.

    • @l.3ok
      @l.3ok 4 года назад +3

      let me get my pen and notebook

    • @beri4138
      @beri4138 4 года назад +2

      Let me get my quantum computer

  • @ubeyondmad1
    @ubeyondmad1 8 лет назад +2

    At 4:08 I think he means von Neumann and not allen turing. The turing machine was an abstraction, while the von Neumann machine was the actual implementation of it.
    As a computer guy, I had to correct this

    • @timh.6872
      @timh.6872 4 года назад

      Turing helped build some of the first general purpose computers after using machines to help break the Engima encryption, as well as coming up with the hypothetical machine used in proofs. Von Neumann designed the basic components of the modern CPU architecture, yes, but Turing was also building real computers around the same time.

  • @AntonDaneyko
    @AntonDaneyko 4 года назад +3

    9:30 How did he got from the modular form to an L function?

  • @matthewgale6560
    @matthewgale6560 2 года назад +1

    I truly did enjoy your show
    Nice .🎶😁

  • @xyzct
    @xyzct 3 года назад +10

    2 is the _oddest_ prime

    • @EdbertWeisly
      @EdbertWeisly 6 месяцев назад +1

      2 is the evenest prime

  • @enlongchiou
    @enlongchiou 8 лет назад

    L-function equal to R.O.S.E(realization of sieve of Eratosthenes) which prove Riemann Hypothesis, by change L-function to Euler product of 1/(1+x(p)/p) at s=1, x(p)=p/(p-1) which equal to Euler product of (p-1)/p, in mod(x,p)/p for example : pi(2^2) = 4*(1/2)+0/2+1-1=2, pi(3^2) = 9*(1/3)+1/2-3/6+0/3+2-1=4

  • @chrismikeryan
    @chrismikeryan 6 лет назад +3

    Looking forward to your video on the recent proof claim!

  • @davida.yorkson3397
    @davida.yorkson3397 3 года назад +1

    That line at x=0.5, it almost feels like we need a third dimention to see how those points are distributed in said 3rd dimention.

  • @morethejamesx39
    @morethejamesx39 8 лет назад +32

    There's no i in team but there is in the square root of -1

    • @yosefmacgruber1920
      @yosefmacgruber1920 7 лет назад

      That just sounds a bit too communist. But there is an i in community. Also in society. Also in sociology. Hmm.
      And according to my TI89 graphing calculator √-1 ≠ i. (Well unless you first do the variable assignment of *_i_* --> i.) Actually, it is a funny italics looking version of *_i_* but it is actually a different character than i. So it would be √-1 = *_i_* .

    • @PerthScienceClinic
      @PerthScienceClinic 5 лет назад +1

      There's an i in team if the team is complex...

  • @josephdays07
    @josephdays07 Год назад +1

    I have developed a new theory, I have called Partitions Trigonometric and I have discovered something amazing. I can do X Rays with these equations applied to Z Riemann.

  • @sorrowface9032
    @sorrowface9032 4 года назад +9

    Imagine Ramanujan living for at least to his fifties.

  • @RobertMStahl
    @RobertMStahl 2 года назад +1

    fine structure seems to apply. Check out the solution to the lepton known as the electron, The Grand Unified Theory of Classical Physics, hydrino being what, ultimately, took down 9-11, including bldg 6, I think.
    See Mental Boost 2's 3 videos on Judy Wood, chronologically.

  • @peppybocan
    @peppybocan 8 лет назад +11

    WHOOOAA... The L-functions. Numberphile is getting serious.

    • @umbreon8527
      @umbreon8527 8 лет назад +8

      +Peter Bočan From paperclips straight to L-functions and the Riemann Hypothesis XD.

  • @strengthman600
    @strengthman600 7 лет назад +2

    I wonder how many unsolved problems wouldn't be unsolved if ramanujan had lived a few years longer

  • @Pedropapt
    @Pedropapt 8 лет назад +3

    "There are infinite of them." "You said they were rare." Welcome to math.

  • @ishwar8119
    @ishwar8119 8 лет назад +3

    I wish Cliff was on every single Numberphile video!

  • @bensfons
    @bensfons 5 лет назад +4

    For me, the z function looks a lot like an sphere surface projected to a plane. What if we put a second imaginary axis there and see what comes out of it?

  • @artmyb
    @artmyb 6 лет назад

    if zeta(a+bi) = 0, the RH implies that a equals 1/2. But this statement does not necessarily imply that "if a is 1/2 then zeta is equal to 0"(as video suggests in 2:28)
    Am I wrong about te basic logic rules or is that implied by another feature of zeta function?

    • @Albkiller22
      @Albkiller22 6 лет назад +2

      If it would directly imply that if a is 1/2 then zeta is equal to zero you would have nothing to prove

  • @AgentSmith911
    @AgentSmith911 8 лет назад +7

    if i eat a loy of vegetables will i understand this stuff then?

  • @wernernoska4343
    @wernernoska4343 8 лет назад

    My favourite Numberphile video yet!

  • @2010RSHACKS
    @2010RSHACKS 8 лет назад +18

    Description has a rogue 'are' or missing 'to'

  • @desertpointshacks6299
    @desertpointshacks6299 2 года назад +1

    No way. I was jst thinking that guy looked quite familiar for some reason. Then when I looked it up I was actually taught by him at uni quite a few years ago. Pretty cool!

  • @danielbody6051
    @danielbody6051 8 лет назад +8

    Well this is well beyond my level..

  • @gurmeet0108
    @gurmeet0108 8 лет назад

    @Numberphile, at 1:42, riemann reflexion formula gives you the value of zeta(1-s) from zeta(s), so from zeta(2+2i) it gives you the value of zeta(-1-2i) not zeta(-1+2i)

  • @Swimmer7596
    @Swimmer7596 8 лет назад +7

    Does proving the hypothesis on any of the other L-functions also prove the the Riemann hypothesis?

    • @AM-uk3vm
      @AM-uk3vm 4 года назад +2

      Its unsolved for a reason

    • @VCT3333
      @VCT3333 2 года назад

      i am guessing that whatever proof of the L functions will employ, can be used to prove the zeta function. I mean the Zeta function itself is a generalization of the Euler function involving only real numbers, extended to the complex plane.

  • @autodidactusplaysjrpgs7614
    @autodidactusplaysjrpgs7614 7 лет назад +1

    I assure you. After years of research, this question remains unresolved.

  • @AllHailZeppelin
    @AllHailZeppelin 8 лет назад +4

    He probably should've clarified that he was talking about all the NON-TRIVIAL zeroes (ignoring -2, -4, -6, etc)

  • @rosiefay7283
    @rosiefay7283 2 года назад +1

    7:09 Does this still work if we retain the $p=2$ term in the product, thus having terms for even n as well as odd n in the sum, the sign of the "n" term in the sum being determined from the largest odd factor of n?
    (When I watched this video the first time, I thought you were leaving the 2 term *alone* rather than leaving it *out.)*

  • @simoncarlile5190
    @simoncarlile5190 8 лет назад +11

    I've spent years trying to wrap my head around what a proof of the Riemann Hypothesis would even look like, or how long it would have to be. One day...

  • @covalencedust2603
    @covalencedust2603 8 лет назад

    That mathematical statement at 0:30 is so underrated. If we would understand why exactly that statement is correct, we would understand prime numbers.