At 7:52 (if the math up to that point was correct) the phase angles would subtract so that the angle would be 53.13 - -53.13=106.26, not zero. There is also an error at the very start. Since the voltage is given as a sine, we should convert to cosine prior to converting to a phasor. Using the identity sin(x)=cos(x-90) this would give us 28.28cos(wt+53.13-90) = 28.28cos(wt-36.87) which yields a phasor V=20 with an angle of -36.87. Then the final answer would be I=(20
At 7:52 (if the math up to that point was correct) the phase angles would subtract so that the angle would be 53.13 - -53.13=106.26, not zero.
There is also an error at the very start. Since the voltage is given as a sine, we should convert to cosine prior to converting to a phasor. Using the identity sin(x)=cos(x-90) this would give us 28.28cos(wt+53.13-90) = 28.28cos(wt-36.87) which yields a phasor V=20 with an angle of -36.87. Then the final answer would be I=(20
Nice bro
Sir please complete network analysis and synthesis as soon as possible. Thank you