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log6=8^(3*x^-1)*log(6^3) , log6=8^(3*x^-1)*3*log6 , 1/3=8^(3*x^-1) , -log3=3*(x^-1)log(2^3) , -log3/log2=9*x^-1 , x^-1=-log3/(9*log2) , x= -9*log2/log3 ,
6=216^a, a=1/31/3=8^bb=3x^-1=3/x1/3=8^(3/x)=2^(9/x)9/x=-log3/log2x(-log3)=9log2x=-9log2/log3
The solution is wrong. You can't treat 216^8^3x^(-1) as 216^(8^3x^(-1)) as you did, the priority of operations is wrong.
It's not wrong!!! Rule of operations is that you start from Left to Right!
log6=8^(3*x^-1)*log(6^3) , log6=8^(3*x^-1)*3*log6 , 1/3=8^(3*x^-1) , -log3=3*(x^-1)log(2^3) , -log3/log2=9*x^-1 ,
x^-1=-log3/(9*log2) , x= -9*log2/log3 ,
6=216^a, a=1/3
1/3=8^b
b=3x^-1=3/x
1/3=8^(3/x)=2^(9/x)
9/x=-log3/log2
x(-log3)=9log2
x=-9log2/log3
The solution is wrong. You can't treat 216^8^3x^(-1) as 216^(8^3x^(-1)) as you did, the priority of operations is wrong.
It's not wrong!!! Rule of operations is that you start from Left to Right!