derive the expression for temperature distribution in a body at time t during a Newtonian heating or cooling is given by T-Ta / Ti-T = e^-BiFo. What is answer for this sir ? Same ansr in your video ?? Please reply sir
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at 11:13 you have done a mistake, when we take a term on the other side of equal sign it becomes either positive or negative, and in case of multiplication it goes into divide. how had you taken the ln term to divide?
Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
@psharma5507 Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
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Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
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the clearest step by step derivations that a regular chem eng understands thanks a ton
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He made mistake brother 10:48
Good explanation sir thank you sir please continue more heat transfer topics ❤❤
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Excellent concept explanation sir . Thanks
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Sir...can u plz put video on heat transfer in semi infinite and infinite solids...
Yes, I will do.
Great explanation sir
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derive the expression for temperature distribution in a body at time t during a Newtonian heating or cooling is given by T-Ta / Ti-T = e^-BiFo. What is answer for this sir ? Same ansr in your video ?? Please reply sir
Please reply sir. This question asked in engineering heat transfer exam . Yesterday
Previous video and this one is very helpful sir
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Are you mechanical engineer
Yes
at 11:13 you have done a mistake, when we take a term on the other side of equal sign it becomes either positive or negative, and in case of multiplication it goes into divide. how had you taken the ln term to divide?
Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms.
The step is correct.
10:48 you have made a mistake brother fix it
@psharma5507 Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms.
The step is correct.
lnA - lnB = ln (A/B) it's correct.
But
lnA -lnB =lnA /ln B it's incorrect
That's the mistake you made brother.
@@psharma5507yes brother u r right. And sir I think u should also accept this.
very nice explain thank you sir
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Tomorrow is my paper 🥺🥺
Tomorrow is mine 🤣
now tomorrow is mine
Also mine
HMT
super sir 😘😘😘
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nmt ln becomes minus not divide at 11:11
Thank you sir
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nice
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Where is previous video
Previous videio-👇👇
ruclips.net/video/EYCp-sQoBFY/видео.html
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super sir
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Sir boundary layer concept
It can T infinity fluid temperature
Thankyou sir.
At video 10:35 how is possible the term ln(ti - ta) is positive when it will go to LHS then it will negative then how you place it to denominator
Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms.
The step is correct.
Tnq
Thank you sir 😌
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You have done mistake in log it will be difference.
Dear,
Complete derivation is correct. Log difference can be written as ratio. For example logX- logY can be written as log(X/Y).
Pls check.
@@SampurnaEngg it can be written as log(X/Y) but not logX/logY as you have done in 10:45, kindly look into this!
Seems like sir also bunked imp classes like us
You made mistake in log
Thankyou sir.
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