I am not the French guy, so I'll take his place this time around "ok cool": 1:14, 2:16 (pen scratches ASMR), 3:24, 6:16, 8:34 "terribly sorry (about that)": 0:03, 6:47
Hello, thanks for your attempt. You did a good job, you can be him while he's gone. I also enjoyed that you included ASMR pen scratch in the list. Overall, the experience was positive as I can now click any of the timestamps you provided and hear the author speak the phrase. I do not know what happened to French guy, but we can hope he is okay and safe. For now, I'm voting you to take his place.
Do a x=1/t sub on original integral that gives I = -I + (alpha-beta) int 0 to ∞ dx/1+x² so I = π(alpha-beta)/4 Thanks a lot for sharing new methods and manipulations . Each and every video of yours is a gem!
Hello , sorry for being annoying , may you complete your complex analysis explanation , it's very nice but I want more 🙂 . because I hope I can use counter intergals for solving so many things ...
I know this will get drowned out. But on mathstackexchange I say an integral I haven’t been able to solve easily. The integral from 0 to 1 of f(x)=(x^3)tan(x^2). I tried Feynmans, exponentiating it, by parts, and writing it using summation. Can you give me a solution, or better yet a step by step?
Hello , can we solve \int_{-\infty}^{+\infty}\frac{dx}{\left( e^x-x ight)^{n}+\pi^{n}} for any natural number n greater than or equal to 2 ? Can u make a video about that ? However, I solved this problem for n=2 by using residue theorem and rectangle contour with height of i2pi and lengh of 2R : beautiful result with 1/(W(1)+1) where W is the principal branch of W lambert function but i don't know how to approch this problem for any natural number n greater than or equal to 2... Can i have a help ? Thx
@@lotaniq4449 But doesn't leave that us with extra negative sign? Since a - θ evaluated at a is 0 and at 0 it's a, so the bounds are upside down now...
@@absol4844 the lower and upper limits will be interchanged if you do the substitution so to make the limits same you use the negative sign. This called the King property check it out :}
can already tell its gonna be a banger
Hi,
"ok, cool" : 1:14 , 2:16 , 3:25 , 4:25 , 6:17 ,
"terribly sorry about that" : 5:01 , 6:49 , 8:35 .
woah! he's here
I am not the French guy, so I'll take his place this time around
"ok cool": 1:14, 2:16 (pen scratches ASMR), 3:24, 6:16, 8:34
"terribly sorry (about that)": 0:03, 6:47
I do need a RUclips plugin to un-OKcool the video, could someone help? 🤣
Hello, thanks for your attempt. You did a good job, you can be him while he's gone. I also enjoyed that you included ASMR pen scratch in the list. Overall, the experience was positive as I can now click any of the timestamps you provided and hear the author speak the phrase. I do not know what happened to French guy, but we can hope he is okay and safe. For now, I'm voting you to take his place.
@@alphazero339 wait a minute 🤣
Waiting for the french guy to list the "ok cool" and "terribly sorry about that" (:
He must have retired
I might unsubscribe because of that🤣
Terribly sorry about that, I am back 🗼💈
@CM63_France okaay, cool
Do a x=1/t sub on original integral that gives I = -I + (alpha-beta) int 0 to ∞ dx/1+x² so I = π(alpha-beta)/4
Thanks a lot for sharing new methods and manipulations . Each and every video of yours is a gem!
Ya i also did that i am way too lasy . What to do . But the solution develepment in the video is kinda cool
awesome approach bhaiya
Wow, can it be that simple? I just checked it. Incredible, awesome! What a symmetry! 🎉
@@rishabhhappy rishabh bro 🌚🗿
Well it's an equivalent transformation since he did x to arctanx to π/2 - χ
Yep, you have a talent in choosing really elegant integrals.
@@trelosyiaellinika thanks mate
Very nice idea. Thank you
That was pretty awesome!
sub x-> 1/x gives you the answer on a single line
Yea
Great video i hope for more videos.
Expectation: Some combination of gamma, beta and zeta. Reality: A linear function with delusions of grandeur.
The expansion of tan is not necessary here
I remember that there is a similar question giving α=sqrt(2)
@Math 505 any tips on how to identify which substituition I should make to solve more difficult integrals?
X=tgθ..poi uso Feymann I(α)..I'(α)..I(β)..I'(β).2I'=π/2....I=(π/4)(α-β)
Hello , sorry for being annoying , may you complete your complex analysis explanation , it's very nice but I want more 🙂 .
because I hope I can use counter intergals for solving so many things ...
okay this is iis awesome
please make a video of how to do the leibniz rule by details please and when can we switch the operators
I know this will get drowned out. But on mathstackexchange I say an integral I haven’t been able to solve easily. The integral from 0 to 1 of f(x)=(x^3)tan(x^2). I tried Feynmans, exponentiating it, by parts, and writing it using summation. Can you give me a solution, or better yet a step by step?
@@charliecox13 I'll take a shot at it
Hello , can we solve \int_{-\infty}^{+\infty}\frac{dx}{\left( e^x-x
ight)^{n}+\pi^{n}} for any natural number n greater than or equal to 2 ? Can u make a video about that ?
However, I solved this problem for n=2 by using residue theorem and rectangle contour with height of i2pi and lengh of 2R : beautiful result with 1/(W(1)+1) where W is the principal branch of W lambert function but i don't know how to approch this problem for any natural number n greater than or equal to 2...
Can i have a help ?
Thx
when can theta be transformed to pi/2 - theta? (6:23)
If the limits are from (0 to a), you can always do a substitution theta’ = a - theta. Its just a substitution, easy to verify.
@@lotaniq4449 But doesn't leave that us with extra negative sign? Since a - θ evaluated at a is 0 and at 0 it's a, so the bounds are upside down now...
@@absol4844 yes but dtheta’=-dtheta, so that - cancels the other -
@@absol4844 the lower and upper limits will be interchanged if you do the substitution so to make the limits same you use the negative sign. This called the King property check it out :}
It's called the King property, it can be easily proved by substitution (lower limit + upper limit -t)
Day by day kamaal questions are getting juicy . ❤
kamaal can i be the zeta to your (s) ? (no diddy)
okayyy cool
Noice
👏👏👏❤♥🙏👍
Greetings and welcome back our kamaal😌✨🤌 my ears were eagerly waiting for your ohk cool and terribly sorry about that😭🤌✨💓