Q1. Yes. The laws of reflection of sound are. 1. The incident angle is equal to the reflected angle. 2. The incident ray the reflected ray and the normal ray all lie on the same plane. Q2 Because the room is small. Q3. Distance=speed X time. First echo distance. 2d=340m/s X 0.3s 2d=102 d =51m Second echo distance 2d=340m/s X 0.5 2d=170 d=85m. Total distance=51m + 85m Total distance=136m
1 st question answer : Yes . Angle of incidence is equal to angle of reflection . 2 nd que answer : Because there are a few good absorbers in our room to absorb sound like , curtains . 3 rd que answer : 1 ; distance = speed * time 2d = 340 m/s * 0.3 2d = 102 m d = 102 / 2 = 51 m 2 ; 2d = 340 * 0.5 2d = 170 d = 170/2 d = 85 m So, 51 + 85 = 136 metres is the distance between the two hills .
1. Yes, it does. The laws are stated below 1st law: the incident angle of sound= reflected angle of sound. 2nd law: the incident sound, normal and the reflected sound lie on the same plane 2. Because of insufficient distance echoes can't be heard in small room. We can differenciate between two sound if the time interval between two sounds is 0.1 second. But in a small distance, the sound reflected takes time less than 0.1 sedond. For this we can't differenciate between two sound and can't hear echoes in a small room. 3. Here, for first hill, V= 340 m/s T= 0.3 seconds 2d= vt Or, 2d= 340× 0.3 Or, 2d= 102 Or, d= 102/ 2 Or, d= 51 Here, for second hill, V= 340 m/s T= 0.5 seconds 2d= vt Or, 2d= 340×0.5 Or, 2d= 170 Or, d= 170/ 2 Or, d= 85 Therefore, total= (85+51) = 136 [ Ans ]
Third question answer is 136 because The man standing between two heals and the man fire the bullet and the sound is reflected from both the hills then Distance traveled 2d at 0.3s Distance =speed * time 2d= 340 * 0.3=51 Distance =speed *time 2d=340*0.5=85 Add both distance 85+51=136🎉🎉
@@liibaanphysics8120 340 m/s is the standard speed of sound. If your weight is 50kg and you are taking it 47kg then your answer will come wrong. So 340
1. Yes, it does. The laws of reflection are: i. The incident ray is equal to the reflected ray. ii. The normal, incident ray, reflected ray drawn at the point of incidence lie on the same plane. 2. In small rooms, The distance between dource and reflecting surface is not 17m but smaller than that. Due to which echo is not heard in these small places. 3. 1st echo: T=0.3s D=2d S≈340m/s 340=2d×10/3 D=51 m 2nd echo, D=2d T=0.5s S≈340 m/s 340=2d×10/5 D=85 m Total distance =51+85 =136 m
1.yes! Why not sound also obey the law of reflection because sound also have same angle of incident and reflected sound having same angle and another on same plane. 2.we cannot hear sound in small room due to small distance between source and reflecting surface i.e less than 17m or may be curtains and dull surfaces which absorb sound energy. 3.As we know that. S=v∆t/2 By putting values we get . 343×3/2 =514m. Another we put 343×5/2 =814m Combined we get . 514+814 =1328m Ok sir
Hw answers: 1 i) angle of incidence is equal to the angle of reflection i= r ii) Incident ray, normal and reflected ray all lie in the same plane 2) we cannot hear echoes in a small room because the size of reflector must be large 3) distance between the two hills is 136m Lovely session ever seen 😍
1. Yes, sound obey the laws of reflection, they are - The incident ray angle is equal to the reflected ray angle The normal, ray of incidence and ray of reflection all lie on the same plane 2. Our ears need some delay before the sound echo can be heard again, that's why in small spaces, as the sound echoes too quickly, it cannot be heard by the ears 3. 1st echo - T = 0.3s D = 2d S = 340m/s 340 = 2×10/3 D = 51m 2nd echo - D = 85m Total distance = 51+85 = 136m
This sir was the best teacher, because he explains in English , but the other teachers and RUclips channels think they are the best teachers 🙄, but they can't even explain it in English. I kept so many comments in live chat but they are acting that they are not seen my comments 🙄🙄🙄. So you are my best teacher ❤️
i love physics thanks for making chapter so easy and another for your top 3 questions truly they are exam oriented and you are my most fav teacher thanks you sir ...
@@ManochaAcademy FFS a good day today I was just thinking about right for me to do it for you to be with you and I have to do it for me and I don't know if you want to go to the store to get a new one for me to do it for you to know if you don't have a good day today and I have to be there in Sir John Salmond is wrong
Ye 1:yes Laws of sound is Echoes and reverberation 2: To listen echones sound the area will be more then we listen .in small room we can't listen because its area will be less .. 3:Distance=speed*time 1st one =2d=340m/s*0.3s Then 2d=102 D=102/2 D=51m 2one =2d=340*0.5s Then 2d=170 D=170/2 D=85 Then1+2= 51+85 =136
Qn 01. YES it obey... Qn 02. For an echo to occur, it needs at least 17m from an obstacle to listener. Qn 03. The answer is 136 m, (I took velocity of sound in air as 340 m/s)
1. Yes... the angle of incidence is equal to the angle of reflection and the incident Ray, the normal and the reflected Ray at the same point of incidence all lie on the same plane. 2. We can't hear Echoes in a small room because sound doesn't reflect back. 3. d=51m d=85m. Thank you sir. Your explanation was superb 👌👏👏👍
1)Yes, sound obey the law of reflection That is angle of incidence=angle of reflection. 2)room is a small place. The minimum time gap to hear echoes (0.1s). And in room curtains, carpets,and other objects absorb the sound. 3)1st hill=56m 2nd hill=85m So, distance between two hills=136m Thank you a lot sir❤️❤️❤️
Sir your teaching is very interactive and you mainly show the daily life examples....by using different equipments,toys,models and many more ..... Sir thank u for ur effort for us .. 🙏🙏❤️❤️
Excellent video Answers are 1. Yes,Laws of reflection of sound are a. Angle of incident of sound is equal to angle of reflection of sound. b. Normal,angle of reflection of Sound and angle of incident of Sound lie on the same plane. 2.We cannot hear the echoes in a small room because the area of a room must be large for echoes to be produced
Q-1) Yes, the laws of reflection of sound are as follow Incident rays go ang coming ray is reflected ray. Q-2) We cannot hear echoes in a small room because we hear an echo in a distance of 17 metres or more from the reflecting surface / an area because equal distance in the forward reverse is direction. Q-3) Distance = speed × time Therefore, A) 1st D = 340m/s × 0.3s = 102m B) 2nd D = 340m/s × 0.5s = 170 m Total D = 272m
The total would be the total distance travelled by sound which is not the same as the distance between the two hills, that would be double. So you'd just have to divide it by 2.
1: yes it does , incident rays = reflected rays 2: beacuse large distance help hear echoes (minimum distance between speaker n reflector should be more than 17 metres ) 3: 1- 51 2- 85( 51 +85=136) Distance between the two hills is 136
Q1 Correct. But you have to give the 2 laws of reflection that light has. Q2 Right! Also mention minimum time is 0.1s to hear echo. Q3 Correct answer :)
8 years back If I would have got you like teacher, or these type of study material in my PUC I would have got distinction..... Although I worked hard I couldn't understand these silly topics.. but practically I understood everything now, although it may not help in my studies or career now... Thk u heartly teacher....
Thanks.. and great experience.. Recollecting all that I hv studied between 44 & 40 yrs ago.. The audio video facilities wld hv made a great difference in those days..and our generation wld hv been a different altogether.. We had only black & white stereotyped books..
Thanks a lot :) Great to hear that you liked the video!! Very true, the audio visual aids are greatly enhancing the learning experience and making it more visual for the students today!
Sir this video was really awesome and it was great fun watching it. Please sir do upload more scientific and interesting videos like this. The concept of sound is now super clear to me. Thanks a lot sir.
1.yes, angle of incidence is equal to angle of reflection and angle I,angle r and normal lie I'm the same plane 2.Because reflecting surface is smaller than the wavelength of sound wave 3.136 m
1)it obeys and laws of reflection is the reflection of light is equal to angle of incidence. 2)it should be nearly 17m wide room to hear the sound of echo. 3)
1) Sound does obey the laws of reflection. The laws of reflection for sound is 1. The angle of incidence is equal to the angle of reflection. 2. The incident sound, reflected sound and normal all lie on the same plane. 2) We can't hear echoes in a small room because echoes need a minimum distance of 17m to produce an echo and a room has a much smaller distance than 17 metres. 3) 34m
@Harshi Gowni, Very good!! Q1 and Q2 answers are correct :) Q3, answer should be 136 m. For this question, draw a rough diagram of a man standing between two hills. Let the distance of one hill from the man be 'a' and other hill from man is 'b'. So total distance between to hills is 'a + b'. As discussed in video, for echo since sound travels twice the distance, formula is: 2d = speed x time, where d is the distance. Since it's not given in the sum, you can take speed of sound in air as 340 m/s (or any standard value that you use). Now consider each hill separately: For first time t1 = 0.3 s, we can do 2a = 340 x 0.3. So a = 51 m For 2nd time t2 = 0.5 s, we can do 2b = 340 x 0.5. So b = 85 m So total distance = a + b = 136 m. Let me know if it is clear now!
00:05 This video is about the reflection of sound. 01:40 Sound reflection follows similar laws as light. 03:21 Reflection of sound leads to echo and reverberation. 05:01 Understanding sound reflection in large spaces 06:44 Hill absorbs sound energy resulting in softer second hello. 08:24 Reverberation is the persistence of sound caused by overlapping reflections. 10:04 Balance between sound absorption and reverberation in acoustic engineering 11:39 Absorbers reduce sound reflection in the house
Ans 1 Yes, it obeys the laws of reflection. Two laws of reflaction are a. Angle of incidence, reflaction and normal all lie in same plane. b. Angle of reflection is equal to angle of reflection i=r Àns2- we cannot hear the echo sound because of our lower sensitivity of ear and dur to less space. Ans 3- ....
A2: we cannot hear echoes in a small room because the room is so small and time taken by sound to get reflected and reach our ear is less than 0.1 seconds so our ears are not so sensitive to hear it
Please Sir, help me with the solution to the question below: The speed of sound in air is 330ms-1. How far from the centre of a storm is an observer who hears a thunder clap 2s after the lightning flash? (Neglect the time taken by light to travel to the observer)
The speed of sound in air is 330ms-1. This means that 1 second represents 330m. Now, in the question it says that it takes 2s for the sound to travel from the centre of the storm to the observer this means that the distance at which the oobserver is standing is 330m x 2s. Now here you can remove the units of those values to make it a little less complicated. Acoording to all this your answer I think should be 660m. Hope it helps! Goodluck!
You may assist me with these questions; 1. A girl stands 160m away from a high wall and claps her hands at a steady rate so that each clap coincides with the echo of the one before. If she makes 60 claps in one minute, calculate; A) the speed of sound. B) If she moves 40cm closer to the wall, she finds that the clapping rate has to be 80 per minute, calculate the speed of sound.
Q1. Yes.
The laws of reflection of sound are.
1. The incident angle is equal to the reflected angle.
2. The incident ray the reflected ray and the normal ray all lie on the same plane.
Q2
Because the room is small.
Q3.
Distance=speed X time.
First echo distance.
2d=340m/s X 0.3s
2d=102
d =51m
Second echo distance
2d=340m/s X 0.5
2d=170
d=85m.
Total distance=51m + 85m
Total distance=136m
i think second echo should be 4d becoz it is coming to us back going and coming back to us once again......Prove me wrong...
@@BlastyaBihanno. They are 2 different echosm
1 st question answer : Yes .
Angle of incidence is equal to angle of reflection .
2 nd que answer : Because there are a few good absorbers in our room to absorb sound like , curtains .
3 rd que answer : 1 ; distance = speed * time
2d = 340 m/s * 0.3
2d = 102 m
d = 102 / 2
= 51 m
2 ; 2d = 340 * 0.5
2d = 170
d = 170/2
d = 85 m
So, 51 + 85 = 136 metres is the distance between the two hills .
One more law of light , they all are on the same plane .
Is the answers correct
@@ashishkalra9661 No , check or hear the video again !
@@mathangiaditya4289 Oh, I got it now. Thankyou!
@@ashishkalra9661 You're Welcome 😊
1. Yes, it does. The laws are stated below
1st law: the incident angle of sound= reflected angle of sound.
2nd law: the incident sound, normal and the reflected sound lie on the same plane
2. Because of insufficient distance echoes can't be heard in small room. We can differenciate between two sound if the time interval between two sounds is 0.1 second. But in a small distance, the sound reflected takes time less than 0.1 sedond. For this we can't differenciate between two sound and can't hear echoes in a small room.
3. Here, for first hill,
V= 340 m/s
T= 0.3 seconds
2d= vt
Or, 2d= 340× 0.3
Or, 2d= 102
Or, d= 102/ 2
Or, d= 51
Here, for second hill,
V= 340 m/s
T= 0.5 seconds
2d= vt
Or, 2d= 340×0.5
Or, 2d= 170
Or, d= 170/ 2
Or, d= 85
Therefore, total= (85+51) = 136 [ Ans ]
Third question answer is 136 because
The man standing between two heals and the man fire the bullet and the sound is reflected from both the hills then
Distance traveled 2d at 0.3s
Distance =speed * time
2d= 340 * 0.3=51
Distance =speed *time
2d=340*0.5=85
Add both distance
85+51=136🎉🎉
Why do you use the speed 340m/s ?
@@liibaanphysics8120 it is speed of sound
Why don't you use 330m/s as speed of sound.
@@liibaanphysics8120 340 m/s is the standard speed of sound. If your weight is 50kg and you are taking it 47kg then your answer will come wrong. So 340
1. Yes, it does.
The laws of reflection are:
i. The incident ray is equal to the reflected ray.
ii. The normal, incident ray, reflected ray drawn at the point of incidence lie on the same plane.
2. In small rooms,
The distance between dource and reflecting surface is not 17m but smaller than that. Due to which echo is not heard in these small places.
3. 1st echo:
T=0.3s
D=2d
S≈340m/s
340=2d×10/3
D=51 m
2nd echo,
D=2d
T=0.5s
S≈340 m/s
340=2d×10/5
D=85 m
Total distance =51+85
=136 m
Your answers are smart
@sourare8206 thanks mate
1.yes! Why not sound also obey the law of reflection because sound also have same angle of incident and reflected sound having same angle and another on same plane.
2.we cannot hear sound in small room due to small distance between source and reflecting surface i.e less than 17m or may be curtains and dull surfaces which absorb sound energy.
3.As we know that.
S=v∆t/2
By putting values we get .
343×3/2
=514m.
Another we put
343×5/2
=814m
Combined we get .
514+814
=1328m
Ok sir
Sir... U explain us all concerned topics of Sound in a very lucid way n lively ...really praiseworthy..
Thanx a lot..
Regards 🙏
Hw answers: 1 i) angle of incidence is equal to the angle of reflection i= r
ii) Incident ray, normal and reflected ray all lie in the same plane
2) we cannot hear echoes in a small room because the size of reflector must be large
3) distance between the two hills is 136m
Lovely session ever seen 😍
1. Yes, sound obey the laws of reflection, they are -
The incident ray angle is equal to the reflected ray angle
The normal, ray of incidence and ray of reflection all lie on the same plane
2. Our ears need some delay before the sound echo can be heard again, that's why in small spaces, as the sound echoes too quickly, it cannot be heard by the ears
3. 1st echo -
T = 0.3s
D = 2d
S = 340m/s
340 = 2×10/3
D = 51m
2nd echo -
D = 85m
Total distance = 51+85 = 136m
Best teacher ever
Thanks
Yah
Sir question 3 samag nahi aaraha
@@ManochaAcademy sir q no 3 samage me nahi aaraha hai
@@ManochaAcademy happy birthday manocha academy
Ur English is so simple And easy! Easy to understand and I remembered it well too! BEST TEACHER EVER! U teach really Good Man!
1 - Yes, sound obeys the laws of reflection. Following are the laws:
a -
Sir I'm glad to tell you that I pass my science exam with 78/80 and 79/80 in maths!! Just because of your constant efforts! Thank you sir!
Wow! Congratulations!! Excellent marks in Science and Maths :) Which class are you in?
6th ig 🤣
This sir was the best teacher, because he explains in English , but the other teachers and RUclips channels think they are the best teachers 🙄, but they can't even explain it in English. I kept so many comments in live chat but they are acting that they are not seen my comments 🙄🙄🙄. So you are my best teacher ❤️
You're right
You are the best teacher that l had ever seen.
The way you are teaching is perfect and easy to understand the concept
1.yes,
I'm doing sound engineering. Your videos are helping me a lot. Thank you sir ❤🙏
THANKS FOR YOUR EFFORT
Our pleasure!
What is sound
@@artwithshubhojit3816 tera baap bekar phadaha hai nubrd
@@ritikroy4859 Pls subscribe our channel 😁😎
i love physics thanks for making chapter so easy and another for your top 3 questions truly they are exam oriented and you are my most fav teacher thanks you sir ...
sir I have loved your teaching style and the vivid examples that you give in your videos
Thanks a lot :)
@@ManochaAcademy FFS a good day today I was just thinking about right for me to do it for you to be with you and I have to do it for me and I don't know if you want to go to the store to get a new one for me to do it for you to know if you don't have a good day today and I have to be there in Sir John Salmond is wrong
Ye
1:yes
Laws of sound is
Echoes and reverberation
2: To listen echones sound the area will be more then we listen .in small room we can't listen because its area will be less ..
3:Distance=speed*time
1st one =2d=340m/s*0.3s
Then
2d=102
D=102/2
D=51m
2one =2d=340*0.5s
Then
2d=170
D=170/2
D=85
Then1+2=
51+85
=136
Echoes and reverberation are not the laws of sound and Qno 2 u can directly answer that there is no time gap or very very less
Qn 01. YES it obey...
Qn 02. For an echo to occur, it needs at least 17m from an obstacle to listener.
Qn 03. The answer is 136 m, (I took velocity of sound in air as 340 m/s)
yee6
My best teacher,I'm corresponding student in South Africa and I rely on your videos to learn
1. Yes... the angle of incidence is equal to the angle of reflection and the incident Ray, the normal and the reflected Ray at the same point of incidence all lie on the same plane.
2. We can't hear Echoes in a small room because sound doesn't reflect back.
3. d=51m
d=85m.
Thank you sir. Your explanation was superb 👌👏👏👍
Then add up the distances=51+85=136m.😋🤗😇
1)Yes, sound obey the law of reflection
That is angle of incidence=angle of reflection.
2)room is a small place. The minimum time gap to hear echoes (0.1s). And in room curtains, carpets,and other objects absorb the sound.
3)1st hill=56m
2nd hill=85m
So, distance between two hills=136m
Thank you a lot sir❤️❤️❤️
56+85=141m
Sir you always teach in a proper and easy way.Thank you for this video.It helped me a lot.
Yes,1)
I am from Nigeria I love ur teaching sir
I wish I had a teacher like you here
Best teacher ever ☺️😊
Thanks
he is 😀
Best teacher in the universe. ....thanks a lot sir
Wow, thanks
Sir your teaching is very interactive and you mainly show the daily life examples....by using different equipments,toys,models and many more ..... Sir thank u for ur effort for us .. 🙏🙏❤️❤️
Excellent video
Answers are
1. Yes,Laws of reflection of sound are
a. Angle of incident of sound is equal to angle of reflection of sound.
b. Normal,angle of reflection of Sound and angle of incident of Sound lie on the same plane.
2.We cannot hear the echoes in a small room because the area of a room must be large for echoes to be produced
Q-1) Yes, the laws of reflection of sound are as follow
Incident rays go ang coming ray is reflected ray.
Q-2) We cannot hear echoes in a small room because we hear an echo in a distance of 17 metres or more from the reflecting surface / an area because equal distance in the forward reverse is direction.
Q-3) Distance = speed × time
Therefore,
A) 1st D = 340m/s × 0.3s = 102m
B) 2nd D = 340m/s × 0.5s = 170 m
Total D = 272m
The total would be the total distance travelled by sound which is not the same as the distance between the two hills, that would be double. So you'd just have to divide it by 2.
8:49 watch it looks real that sir goes there
I learn so many things from you...
And get many kinds of activities....
Teaching ideas ...thanks alot
You are genious & excellent teacher.your method of teaching practically is very nice & make the besic concept of each topic of science strong .
1: yes it does , incident rays = reflected rays
2: beacuse large distance help hear echoes (minimum distance between speaker n reflector should be more than 17 metres )
3: 1- 51
2- 85( 51 +85=136)
Distance between the two hills is 136
Q1 Correct. But you have to give the 2 laws of reflection that light has.
Q2 Right! Also mention minimum time is 0.1s to hear echo.
Q3 Correct answer :)
8 years back If I would have got you like teacher, or these type of study material in my PUC I would have got distinction..... Although I worked hard I couldn't understand these silly topics.. but practically I understood everything now, although it may not help in my studies or career now... Thk u heartly teacher....
Thanks.. and great experience.. Recollecting all that I hv studied between 44 & 40 yrs ago..
The audio video facilities wld hv made a great difference in those days..and our generation wld hv been a different altogether.. We had only black & white stereotyped books..
Thanks a lot :) Great to hear that you liked the video!!
Very true, the audio visual aids are greatly enhancing the learning experience and making it more visual for the students today!
Nicely explained. The concept of reflection of sound is completely clear to me now.
Sir your way of explanation was superb
Sir, you are a future maker.
Thank you so much sir I have tests this upcoming week and you helped with your videos... I have shared your channel with my friends :) thank you
Fantastic lesson. Strong explanations and examples that are easy to understand. My 8 year old was able to answer all of the
questions correctly!
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You teaches very well thanks for explaining such an interesting chapter…
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Sir this video was really awesome and it was great fun watching it. Please sir do upload more scientific and interesting videos like this. The concept of sound is now super clear to me. Thanks a lot sir.
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It's my pleasure
@@ManochaAcademy 🙏🙏🙏
1.yes, angle of incidence is equal to angle of reflection and angle I,angle r and normal lie I'm the same plane
2.Because reflecting surface is smaller than the wavelength of sound wave
3.136 m
For online classes this really helps , thank u so much
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1)it obeys and laws of reflection is the reflection of light is equal to angle of incidence.
2)it should be nearly 17m wide room to hear the sound of echo.
3)
Good explanation sir, thank you sir this helps me in doing online home works ..
You are welcome
Thank you for teaching the sound lesson sir
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U are good teacher I ever seen in my life 😢
Thanks for liking
Excellent presentation for difficult questions.
Sir you teach far better than any other teacher...,✨🤩
1) Sound does obey the laws of reflection. The laws of reflection for sound is
1. The angle of incidence is equal to the angle of reflection.
2. The incident sound, reflected sound and normal all lie on the same plane.
2) We can't hear echoes in a small room because echoes need a minimum distance of 17m to produce an echo and a room has a much smaller distance than 17 metres.
3) 34m
U r done a good job 3question explanation
Time gap diff is 0.2 sec
@Harshi Gowni, Very good!! Q1 and Q2 answers are correct :)
Q3, answer should be 136 m.
For this question, draw a rough diagram of a man standing between two hills. Let the distance of one hill from the man be 'a' and other hill from man is 'b'. So total distance between to hills is 'a + b'.
As discussed in video, for echo since sound travels twice the distance, formula is: 2d = speed x time, where d is the distance.
Since it's not given in the sum, you can take speed of sound in air as 340 m/s (or any standard value that you use).
Now consider each hill separately:
For first time t1 = 0.3 s, we can do 2a = 340 x 0.3. So a = 51 m
For 2nd time t2 = 0.5 s, we can do 2b = 340 x 0.5. So b = 85 m
So total distance = a + b = 136 m.
Let me know if it is clear now!
@@ManochaAcademy thanks so much you're videos are so good
Thank you :) Do share our videos with your friends and family!
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You are most welcome
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Yes Same!
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00:05 This video is about the reflection of sound.
01:40 Sound reflection follows similar laws as light.
03:21 Reflection of sound leads to echo and reverberation.
05:01 Understanding sound reflection in large spaces
06:44 Hill absorbs sound energy resulting in softer second hello.
08:24 Reverberation is the persistence of sound caused by overlapping reflections.
10:04 Balance between sound absorption and reverberation in acoustic engineering
11:39 Absorbers reduce sound reflection in the house
Good teaching method .adorable .nice
Many many thanks
U r a great teacher
Good video sir, i understand everything easily. No wonder my teacher picked this video for us :D
Your a good scientifically RUclipsr I really understand from you
thank u so much sir
for the well explanation u gave
You are most welcome
Ans 1
Yes, it obeys the laws of reflection. Two laws of reflaction are
a. Angle of incidence, reflaction and normal all lie in same plane.
b. Angle of reflection is equal to angle of reflection i=r
Àns2- we cannot hear the echo sound because of our lower sensitivity of ear and dur to less space.
Ans 3- ....
i had liked your video and get inspired by you sir by teachings and explanation
Glad to hear that
Ur explaining is super it is easily to understand
A2: we cannot hear echoes in a small room because the room is so small and time taken by sound to get reflected and reach our ear is less than 0.1 seconds so our ears are not so sensitive to hear it
Hello sir. I don't lyk physics that much before watching your video. Thank you sir
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The explanation was so nice i liked the video so much and i learned this without any doubt
From Taanvi Desai
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hi !
iam from srilanka
very,very
your explanation is very good
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1.yes..it obeys the law of reflection...
Pls solve no 3
Sir I have a doubt when I shout in my balcony there is a echo outside but there are walls near me to. How is that?
So it means that the source which is reflecting your sound is far away from you. It is not necessary that only walls absorb all the energy
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Love this video alot thank u so much sir 💝😍
Most welcome 😊
Please Sir, help me with the solution to the question below:
The speed of sound in air is 330ms-1. How far from the centre of a storm is an observer who hears a thunder clap 2s after the lightning flash? (Neglect the time taken by light to travel to the observer)
The speed of sound in air is 330ms-1. This means that 1 second represents 330m. Now, in the question it says that it takes 2s for the sound to travel from the centre of the storm to the observer this means that the distance at which the oobserver is standing is 330m x 2s. Now here you can remove the units of those values to make it a little less complicated. Acoording to all this your answer I think should be 660m.
Hope it helps! Goodluck!
the legend summarized 30 pages of impossible-to-understand concepts within a few minutes with cristal clear clarity.
You may assist me with these questions;
1. A girl stands 160m away from a high wall and claps her hands at a steady rate so that each clap coincides with the echo of the one before. If she makes 60 claps in one minute, calculate;
A) the speed of sound.
B) If she moves 40cm closer to the wall, she finds that the clapping rate has to be 80 per minute, calculate the speed of sound.