Build a SIX LED Level Indicator CD40106BE

[@BadChizzle]

Cool circuit. This chip is often used for simple oscillators in DIY synth builds. LFO and or audio frequency usages. Thanks for the video!

[@AllAmericanFiveRadio]

Thanks

[@N4HAY]

Perhaps the forward turn on voltage on the different leds varies? Try current limiting each led.

[@AllAmericanFiveRadio]

Thanks

[@jj74qformerlyjailbreak3]

Thank you for your explanation of this oscillator
GodBless.

[@AllAmericanFiveRadio]

Thanks you, and your welcome.

[@rciancia]

THIS IS COOL. What would a practical application be for this circuit ?

[@AllAmericanFiveRadio]

voltage indicator

[@rciancia]

@@AllAmericanFiveRadio Very cool Rick, thank you

[@p_mouse8676]

I think something has to do with the impedance of your potentiometer.
I simulated the circuit with just a voltage source that ramps up, but don't have the same behavior.
Usually the 5th resistor (100k in this case) is also lower in value, like the other ones.

[@AllAmericanFiveRadio]

That could be. Thanks

[@skycarl]

I was just about to ask if you used a different chip when you said you did. hmm,, Either way Rick this is a cool little circuit that can be used in many ways. Thanks pal for sharing as always.

[@AllAmericanFiveRadio]

Thanks

[@MrWasim100100]

wow very useful circuit thanks for sharing

[@AllAmericanFiveRadio]

Thanks and your welcome.

[@W1RMD]

Great little project! Thank you for posting! I'm thinking that 6 comes on before five because it looks like this chip switches grounds only. Number 5 is at different ground potential than any of the others. I wonder if you replace the 100k with a 10k. Even if you had to replace the 200k with a 300k. Let me know what happens. I'm not familiar with how these chips work, but it's weird how 5&6 are swapped inside the chip. Thanks for the video!

[@AllAmericanFiveRadio]

Thanks for the information.

[@johnscoles660]

hmm how about parasitic capacitance of the breadboard giving you a bounce off '#5' that turns on '#6' first because of some sort of ringing, overshoot or undershoot?

[@AllAmericanFiveRadio]

That's a possibility.

[@hhhh3551]

good work

[@AllAmericanFiveRadio]

Thanks

[@grantnm1]

I just did a rough calculation and the input voltage at pin 11 would be lower than the input voltage at pin 13. I’m thinking the lower voltage will be the loser in this case causing output at 12 to come on first.

[@AllAmericanFiveRadio]

That would be a good start. Thanks