why is it that when the temp of the filament bulb increases, the resistance increases. but when the temp increases for the thermistor, the resistance decreases?
Thank this helped me alot I was so confused. Also Just to understand does that mean the diode needs to melt a bit in order to conduct electricity so that it’s ions can be free?
It's important to indicate the reference directions for current i and voltage v to interpret the i-v characteristic curves correctly, especially the asymmetrical diode characteristic.
But, isnt the Resistance R the slope? If it increases for the lamp then why does the slope of the graph decrease as it gets higher voltage? How do I calculate the resistance from the graph I/V for a lamp? When the function look like in your example.
Is the LDR usage for street lamp applicable? The street lamp would turn on when dark, but the graph shows that when there is more light, there is more current, and the lights will turn on. Am i missing something?
Yes; in real life the circuit would be more complicated than just simply having an LDR - it would require additional circuit components arranged a certain way so as to get the desired output. But that is way beyond GCSE level so I didn't include a full explanation. The main point was that an LDR could be used as part of a circuit to control a street lamp.
I thought all that would be required would be a filament lamp connected in parallel with an LDR. As night falls the resistance of the LDR increases so there is more P.D across it so the Lamp glows brighter
Yes because the temperature increases. An increase in temperature will increase the resistance (like in toasters, which are just very large resistors). So, the more current you have the higher the resistance would be. Hope this helps. (EDIT: a filament lamp emits thermal energy becuase the electrons transfer electrical energy into "wasted" thermal energy and "useful" photonic energy. Its like lighting a stick on fire and using it as a torch. LED (light emitting diodes) are much more efficient, as they don't emit much thermal enrgy, meaning that you can increase the brightness (by increasing the voltage) without making the component hot.)
I was looking for a graph of thyristor... Anyways, it was a very nice video, it made my concepts clearer... Would be of great help if you provide a graph of thyristor tooo...
I had no clue how these graphs work, now i know what they are and what they do, now my teacher wont scream at me. Thank you
I am watching this at home in 2020 and it has made my understanding of IV graphs better .thank you so much
It's Corona tiiiime
Hey from the futureee
@@allysiaasare1948 im from even further in the future
introducing the threshold term to the diode graph makes it more memorable. thank you very much
absolute hero, rescuing my gcse's. much love
Mine too
Mine too
Mine too
you are the best teacher . you helped me to understand this lesson before one day from my exam . I need your explanation in my academic career
Im in IB, and this helps a lot for the graphs. Thanks
Thank you so much this just brought even more clarity to physics that other sources don’t so grateful
I'm doing national 5 physics (Scottish equivalent) and this is a hell of a lot more easy to understand than any Scottish sources.
Thanks Evan, glad to help!
I have to do a graph of voltage vs current and am wondering what is a good mathematical function that can fit my data for a light bulb.
Cubic function?
Hi! Thank you for your video!
I've a question. What are the I-V graphs for LDR and thermistors? Are they ohmic?
In thermistor, how is will the temperature decrease resistance when in ur previous video u said more temperature means more resistance
why is it that when the temp of the filament bulb increases, the resistance increases. but when the temp increases for the thermistor, the resistance decreases?
Thank this helped me alot I was so confused. Also Just to understand does that mean the diode needs to melt a bit in order to conduct electricity so that it’s ions can be free?
Nice channel ! Really helps to understand
It's important to indicate the reference directions for current i and voltage v to interpret the i-v characteristic curves correctly, especially the asymmetrical diode characteristic.
But, isnt the Resistance R the slope? If it increases for the lamp then why does the slope of the graph decrease as it gets higher voltage?
How do I calculate the resistance from the graph I/V for a lamp? When the function look like in your example.
If you hand wave it and say R = dV/dI, then in I-V curves the slop is dI/dV = 1/R, the slope decreases means higher resistance.
This guy is sooo good X
Is the LDR usage for street lamp applicable? The street lamp would turn on when dark, but the graph shows that when there is more light, there is more current, and the lights will turn on. Am i missing something?
Yes; in real life the circuit would be more complicated than just simply having an LDR - it would require additional circuit components arranged a certain way so as to get the desired output. But that is way beyond GCSE level so I didn't include a full explanation. The main point was that an LDR could be used as part of a circuit to control a street lamp.
GetToKnowScience Oh okay thanks. i figured it would probably be something like that
GetToKnowScience Really helpful video by the way, saved me 1 - 2 marks on a test yesterday :))
No worries - I'm glad it helped!
I thought all that would be required would be a filament lamp connected in parallel with an LDR. As night falls the resistance of the LDR increases so there is more P.D across it so the Lamp glows brighter
So in the light bulb situation it means that doubling the current will always be higher than doubling the voltage?
Yes because the temperature increases.
An increase in temperature will increase the resistance (like in toasters, which are just very large resistors).
So, the more current you have the higher the resistance would be.
Hope this helps.
(EDIT: a filament lamp emits thermal energy becuase the electrons transfer electrical energy into "wasted" thermal energy and "useful" photonic energy. Its like lighting a stick on fire and using it as a torch. LED (light emitting diodes) are much more efficient, as they don't emit much thermal enrgy, meaning that you can increase the brightness (by increasing the voltage) without making the component hot.)
I was looking for a graph of thyristor...
Anyways, it was a very nice video, it made my concepts clearer...
Would be of great help if you provide a graph of thyristor tooo...
SOOOOOO HELPFUL MAN THANKS ALOT.👍
*A lot
tthank you tooooooooooooooo much
Massive thank you!
Thanks so much for this, I've been off for covid and my tea hers didn't send me any work eventhough they said they would lol
Who’s watching the night before the test? Any way thanks really helpful
Thank you so much sir
Very clear, Thanks!
Teacher threw a chair at my head because I got this wrong
I love youuuuu
not all heroes wear cape
so helpful! thank you
I should have skipped to the recap😭
he sounds so bored lol
Thanks bro
Huuuhhhh
hi
Yo drink some water 😂
Ur thermistor is upside down 😂
Fu😢ck