Is the eqn valid for lewis acid and base . For eg when NH3 and HcooH react it form hcooNH4. And there is no rexn b/w H+ and OH- to form H2O which is the reason for -13.7. so shouldn't the value differ? 20:23
@@cosmicdevil1746 but isn't h3po4 a weak acid thats why delta h ion of it was taken so why use the energy of strong acid amd strong base neutralization
when 1 mol of h3po4 neutralized with naoh delHneut is -150 (and 1 mol means no.of g.eq of h3po4=3) so when S.A and S.B is used energy liberated is -57.3 kcal/g.eq, and here for no.of g.eq=3 Heat liberated=3*57.3=171.9 therefor------> -150=delHion-171.9------> delHion=171.9-150=21.9 KJ/mol.
Sir ne bomb calorimeter wala formula use karke 0.2 moles ke liye q nikala aur fir no of moles se divide kar diya gram equivalent me convert karne ke liye.
@@boncoderz1430 12gm is the water equivalent of bomb calorimeter, whenever the heat is released in a reaction the calorimeter also gets heated up, so in order to calculate the total heat sir added all the masses (200 + 400 + 12) gm. If you have any further confusion then you can refer to lecture 1 of this series or else to the calorimeter part taught in physics under ‘heat transfer’ chapter.
9:48 how my parents describe my current life status to relatives
Broo 💀
9:57 as well
real
@@snow5064Bruhh 😂😂
akash se jee ke prep kaise chal rhi??@@Sky_infy
5:35 n factor of h3po3 should be 2
For complete neutralisation it is 1
@@spectacularcat1234 no that's 2
Ya but sir wrote about h3po4
@@amitsingh2782 sir said h3po4 but wrote h3po3 bruh
5:34 valency factor for H3PO3 is 2 instead of 3
It's 3 not 2
@@Aadish_Jain_ It is 2 not 3, 3 is of h3po4
AWESOME LECTURE THANKS🙏
24:40 why did sir add 200 and 400? formula is MS*deltaT right??? 200 and 400 are volume not mass , plss clarify
Volume *density= mass
Sir, NaA ka hydrolysis nhi hoga kya salt of weak acid and strong base so no hydrolysis ke lie bhi energy dena padega
Best quality lectures available on yt .thankyou sir
Why at 25:05 sir had taken temp in C even though Specific heat is given in K
sir ki marzi, who are you to questin sir's choices
because temp RISE is 4.4 deg celcius, so after converting and all, temp rise = same= 4.4 deg K
@@dhruvsharma6880 help nahi karni hoti to bakwas bhi mat hi kiya kar
change in temp in celsius and kelvin is same, hope it helps. For example, 100C-0C="100C" similarly 373K-273K="100K"
@@11thWasteHogyaYaarHeheeee......Hi....
Sir shouldnt it be 3(-57.3)-150 in the last question?
Is the eqn valid for lewis acid and base . For eg when NH3 and HcooH react it form hcooNH4. And there is no rexn b/w H+ and OH- to form H2O which is the reason for -13.7. so shouldn't the value differ? 20:23
Can anyone explain please that how we are taking at 28:10 57.3 please explain
HCl(1 gram eq ) + NaOH (1grm eq) gives 57.3 kcal energy
joule m convert ker rakha h
13.7 calories mai hai. Usko joule mai covert kiya 13.7 *4.18J
Did you qualify
@@D7XTE7 taking drop
Sir a small correction vf of H3PO3 is 2
depends on how u r dissociating it .
it can be 1,2 and 3
@@kartikjangir8127 but its the case of H3PO4 where(vf is 1, 2 or 3) but in H3PO3 vf is 1 or 2
Sir❤
Sir I have a doubt wouldn't it take some energy to break the salt of weak acid and weak base it is made up of of weak electrolytes.
wahi to. I am still confused about it.
all salts are strong electrolyte😀
Best lecture
Best sir
Coaching me Sala 10 minute me padha diya ....padhate itna h...par sawal bade bade puchte h😑
at 25:25 , Y did sir divide by 1000 can someone clarify pls
ml to litre
Why did sir take 0.2 mol of HCl and NaOH to solve 2nd last ques?
use mole concept, the volume and molarity is given so if you find the no. of moles using the formula, it will come out 0.2 mol
redox kia nhi hai mene, abh yeh nhi samaj ayega?
Please explain the q-2 explain in this lecture
Why in last question 53.7 was multiplied by 3
H3Po3 ka valency factor 3 hota hai and no of eq = no of moles x valency factor
@@cosmicdevil1746 but isn't h3po4 a weak acid thats why delta h ion of it was taken so why use the energy of strong acid amd strong base neutralization
Thanks sir
Yaha par deltaH ionization kyo use hua h
Kyoki ions ko todna padega us liye energy deni hogi
H3po3 ka 2
24:14 it should be millimoles ig something is wrong
can anyone explain last question 27:25??
when 1 mol of h3po4 neutralized with naoh delHneut is -150 (and 1 mol means no.of g.eq of h3po4=3) so when S.A and S.B is used energy liberated is -57.3 kcal/g.eq, and here for no.of g.eq=3 Heat liberated=3*57.3=171.9 therefor------> -150=delHion-171.9------> delHion=171.9-150=21.9 KJ/mol.
@@adithva4116 IG H3PO4 WILL BE weak acid as del H ion we have to find. overall correct solution
24:24 ye 0.2 kaha se aaya aap ne bola naho
No of moles= Molarity × Volume of solution/1000
Please koi2nd last question hai explain krdo yrrr😢😢😢😢😢
Sorry
Sir ne bomb calorimeter wala formula use karke 0.2 moles ke liye q nikala aur fir no of moles se divide kar diya gram equivalent me convert karne ke liye.
@@SiddharthSingh-id9fb but why add 12 I don't understand
@@boncoderz1430 12gm is the water equivalent of bomb calorimeter, whenever the heat is released in a reaction the calorimeter also gets heated up, so in order to calculate the total heat sir added all the masses (200 + 400 + 12) gm. If you have any further confusion then you can refer to lecture 1 of this series or else to the calorimeter part taught in physics under ‘heat transfer’ chapter.
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19:25 -10 energy nikalega correct it
Sir last q me heat 57.3 kaha se pta chla
13.7 calories mai hai. Usko joule mai covert kiya
Our sir previous lecture me bataaya tha
@@ln2470 hello .693
101 Done
14:3
5:20 this concept type question came in my JEE 2024
Edit: I am a neet student
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15:01 Sar aapane apni English Dikhai Di
Thank you sir