Sir, Greetings From India! Thank You So Much for the immense easiness and clarity in your videos. Thanks, Your Humble Subscriber and Liker! Thank You! I am obliged. By the way, I am studying for my Extensive Exam( Half-Yearly) in India, Class X. - Electricity/ NCERT Book. Once again, my humble thanks!
Thank you for such high quality videos, I was wondering if your diagrams of circuits can include resistance as a box instead of the zig zag since the ib recommends that.
can one also think of the example at 5:17 such that the equivalent resistance will be less than 10 ohms because since 10 ohms is the smallest resistance, most of the current will take that path but a small amount will take the 20 and 500 ohm paths?
I was just thinking, at around 4:30, shouldn't the equivalent resistance be a little more than 1 ohm? Because the other resistances are greater than 1 ohm, so how could the overall resistance be smaller? I understand the idea of more paths making current flow easier, but how do we know that this outweighs the increased resistance of that path?
these are such annoying problems but set us up for great success in advanced circuits! Thank you Mr. Doner :)
Sir, Greetings From India!
Thank You So Much for the immense easiness and clarity in your videos.
Thanks, Your Humble Subscriber and Liker!
Thank You!
I am obliged. By the way, I am studying for my Extensive Exam( Half-Yearly) in India, Class X. - Electricity/ NCERT Book.
Once again, my humble thanks!
how was the exam
Thank you for such high quality videos, I was wondering if your diagrams of circuits can include resistance as a box instead of the zig zag since the ib recommends that.
The IB uses boxes but also expects that you are able to work with underlying concepts so that you flexible in your use of symbols.
@@donerphysics thank you! Sir.
Thank you so much from Turkey
You are welcome!
can one also think of the example at 5:17 such that the equivalent resistance will be less than 10 ohms because since 10 ohms is the smallest resistance, most of the current will take that path but a small amount will take the 20 and 500 ohm paths?
That is right. It is a little different from the previous example since 20 ohms is comparable to 10 ohms, but the reasoning is the same.
Sorry but at 13:15, how did you get 3.91? didnt you do 18/5 = 3.6
1/R=1/18 + 1/5 gives R=3.91
Better to listen at 1.5 x speed.
...but then I sound like a chipmunk.
I was just thinking, at around 4:30, shouldn't the equivalent resistance be a little more than 1 ohm? Because the other resistances are greater than 1 ohm, so how could the overall resistance be smaller? I understand the idea of more paths making current flow easier, but how do we know that this outweighs the increased resistance of that path?
There is no increased resistance of the path...just more paths.
I believe that the last example turns out to have 128.798 so approximately 129 ohms
You are right. thank you.