Probabilistic ML - Lecture 1 - Introduction

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  • Опубликовано: 19 дек 2024

Комментарии • 27

  • @seanranieri3816
    @seanranieri3816 8 месяцев назад +2

    27:20 Really impressive, especially the pronunciation of Kolmogorov's name.

  • @lex494
    @lex494 22 дня назад

    Great lecture and great lecturer. Thank you for making this available to public for free.

  • @kleemc
    @kleemc Год назад +4

    👏👏👏👏 well done. Great explanation of the big picture and the relationship among statistical learning, probabilistic learning and the modern machine learning.

  • @bhavitsharma
    @bhavitsharma Год назад +2

    These are great lectures, thank you so much. Are the latest lectures for Statistical Learning Theory also available on RUclips?

    • @rosmf
      @rosmf Год назад

      I am also quite interested on that ... I only found the 2020 version ruclips.net/p/PL05umP7R6ij2XCvrRzLokX6EoHWaGA2cC

  • @iamkzntsv
    @iamkzntsv Год назад +1

    Shouldn't it say "false positive rate" in the Covid19 task specification at 18:30?

    • @Kandyfrom1986
      @Kandyfrom1986 Год назад

      No. False positive means wrongly saying a patient has covid when he/she is not. Where as false negative means wrongly saying a patient does not have covid when he/she has.

    • @iamkzntsv
      @iamkzntsv Год назад +1

      @@Kandyfrom1986 Exactly. However, there seems to be a discrepancy with mathematical notation. TPR = P(T|C) and FNR = P(¬T|C) should add up to 1 (if a person has covid, then the test is either negative or positive), so given a TPR of 0.938, FNR should be 1 - 0.938 = 0.062. Similarly, TNR and FPR should add up to 1. Since here TNR = P(¬T|¬C) = 0.96, we can deduce that FPR should be 0.04. Thus, the task should say a "false positive rate". Please correct me if I'm wrong.

    • @Kandyfrom1986
      @Kandyfrom1986 Год назад +2

      @@iamkzntsvMy bad. You are right. Thanks for the correction

    • @heyjianjing
      @heyjianjing 11 месяцев назад

      yep, should be "false positive rate" of 4%

  • @zeyadomar200
    @zeyadomar200 Год назад +6

    Given the card has one red face means we now have 2 possibilities
    So the probability that the other side is red should be 1/2
    Please correct me if I am wrong.

    • @amesoeurs
      @amesoeurs Год назад

      you are wrong, and you were corrected in the lecture if you were actually listening to it.

    • @SiaHranova
      @SiaHranova Год назад +10

      That is incorrect, because you could have drawn card 1 on either side, so there is actually 3 possibilities. You have three cards and six sides:
      1 2 3
      top side R W W
      bottom side R R W
      When you drew a card with a red side you know that card 3 no longer plays a role in the probabilities. So there is three possibilities left:
      Ýou drew either :
      - the bottom side of card 1 in which case the other side is red.
      - the top side of card 1 in which case the other side is again red.
      - the bottom side of card 2 in which case the other side is white.
      This gives you a probability of 2/3 for the other side being red.

    • @audionmusic2787
      @audionmusic2787 Месяц назад

      I’m thinking he is right. With one card already removed, two cards remain. One would be red and the other is white. That’s 50% because only two choices remain. However you want to talk around or over this doesn’t change a thing. The prof is wrong.
      There are not 3 possibilities. The red card is red on both sides. The white is white on both sides. If you want to be ridiculous you can say since there are 4 possible sides which can emerge next, and 2 are red and 2 are white, making 2/4 fraction and it’s 50% again.
      Once one card is first pulled there are no longer 3 choices.

  • @dhruvnanosoft
    @dhruvnanosoft Год назад +1

    I read somewhere there are JAX assignments for this course. Are they available to the public? Without solution is fine. These would help us reinforce the lecture material.

  • @sakcee
    @sakcee 8 месяцев назад

    can we have the homeward or exercises of this course?

  • @nishantluitel1198
    @nishantluitel1198 Год назад

    Would it be possible to also upload the codes from the lecture?
    I only saw the applet code but not the jupyter notebook codes. It would really help if the codes are uploaded too.

  • @sumankhatri2679
    @sumankhatri2679 8 месяцев назад

    Can we get course website

  • @sumankhatri2679
    @sumankhatri2679 8 месяцев назад

    Hi , Please provide code and excercise of this very nice code.

  • @lbognini
    @lbognini Год назад

    It would've been good not to say "upper side" and stress on the fact that no distinction can be made between faces. Cause if the sides can be distinguished, then the answer is 1/2.

    • @cyrkielwspin
      @cyrkielwspin Год назад +1

      If the sides are distinguishable, then 1/3 of the time you will be certain that you've got red-red card (since red-white card has this side white), and the remaining 2/3 of the time you will have indeed 1/2 probability you've got red-red card. Thus the final probability is: 1/3*1 + 2/3*1/2, which, funny enough, equals 2/3 :)

  • @vyompatel4517
    @vyompatel4517 Год назад

    Are there plans to upload these slides? The previous ones are from 2020.

    •  Год назад +7

      The material is now avaiable at github.com/philipphennig/Probabilistic_ML

    • @jbj926
      @jbj926 Год назад +3

      @​​⁠ Is the Statistical Learning Theory lectures and slides going to be uploaded as well?

  • @jasperbutcher459
    @jasperbutcher459 Год назад

    So sick

  • @TummalaPavan
    @TummalaPavan 10 месяцев назад

    At 44:00 why does the professor say this works for any non zero probability set? I feel P(A ∪ Φ) = P(A) + P(Φ) and thus P(A) = P(A) + P(Φ) and so P(Φ) = 0 for any P(A)

  • @farshidshateri_wp
    @farshidshateri_wp 3 месяца назад

    man's mind ❌ Human mind ✅