Thank you for the video! I've encountered a practice question that confused me. I reached same answer as walkthrough, but the process was different. I hope you could take a look at this: Mr. Green makes salads. The standard plate of salad has 30 g of lettuce (L), 50 g of peppers (P) and 80 g of beetroot (B). The standard prices of the three ingredients are $0.2/kg, 0.4/kg and 0.8/kg respectively. Mr. Green has been experimenting and so in July he changed the mix of vegetables on the plate thus: 1,500 plates contained 62,000 grams of lettuce, 81,000 grams of peppers and 102,000 grams of beetroot. What is the total material yield variance? ------------------------- My work was: Wtd Avg Std Price (in grams) = (30*0.0002+50*0.0004+80*0.0008)/(30+50+80)= 0.000562 per g Standard mat used per plate = 30+50+80 = 160 g 1500 (actual) plates should have used 1500*160 = 240,000 g 1500 plates actually used = 62000+81000+102000 = 245,000 g Variance in unit = 245000-240000 = 5000g Adverse Yield Variance in $ = 5000*0.000562= $2.81 -------------------------- Walkthrough was: Actual yield 1,500.00 Standard yield 1,531.25 Difference 31.25 Standard cost of a plate 0.09 Yield variance = 31.25 × 0.09 = 2.8125 A ----------------------------- It might not matter since both ways reached the same answer, but I want to understand all the elements for more options to solve the questions. I realize that I reach 5000g by multiplying 160 to 31.25, and 0.000562 by dividing 0.09 by 160. could you elaborate the logic used in the walkthrough answer?
You have done the input method and the text has followed the output method. Both are accepted methods for solving the problems.... Input method finds the variance of the actual and std raw materials while output method finds the variance of the actual and std finished goods
Thank you for the video! I've encountered a practice question that confused me. I reached same answer as walkthrough, but the process was different.
I hope you could take a look at this:
Mr. Green makes salads. The standard plate of salad has 30 g of lettuce (L), 50 g of peppers (P) and 80 g of beetroot (B).
The standard prices of the three ingredients are $0.2/kg, 0.4/kg and 0.8/kg respectively.
Mr. Green has been experimenting and so in July he changed the mix of vegetables on the
plate thus: 1,500 plates contained 62,000 grams of lettuce, 81,000 grams of peppers and
102,000 grams of beetroot.
What is the total material yield variance?
-------------------------
My work was:
Wtd Avg Std Price (in grams) = (30*0.0002+50*0.0004+80*0.0008)/(30+50+80)= 0.000562 per g
Standard mat used per plate = 30+50+80 = 160 g
1500 (actual) plates should have used 1500*160 = 240,000 g
1500 plates actually used = 62000+81000+102000 = 245,000 g
Variance in unit = 245000-240000 = 5000g Adverse
Yield Variance in $ = 5000*0.000562= $2.81
--------------------------
Walkthrough was:
Actual yield 1,500.00
Standard yield 1,531.25
Difference 31.25
Standard cost of a plate 0.09
Yield variance = 31.25 × 0.09 = 2.8125 A
-----------------------------
It might not matter since both ways reached the same answer, but I want to understand all the elements for more options to solve the questions.
I realize that I reach 5000g by multiplying 160 to 31.25, and 0.000562 by dividing 0.09 by 160.
could you elaborate the logic used in the walkthrough answer?
You have done the input method and the text has followed the output method. Both are accepted methods for solving the problems.... Input method finds the variance of the actual and std raw materials while output method finds the variance of the actual and std finished goods
Thank you so much mam!!!
I have been watching your videos for upcoming exam.
Grt to know... Good luck for ur exams!!
thank you mam
Glad to know that this was helpful!!!
This method is tough
Thanks Alot Mam :)
Appreciate your feedback. Good luck for your exams 👍
Nice
Thank you!