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Homework📚📝
Allele frequencies:
a) R = 2×16+48/2×100
R= 32+48/200
R= 80/200
R= 0.4 and by using p+q =1 formula we can 𝚌𝚊𝚕𝚌𝚞𝚕𝚊𝚝𝚎
B) r = 1- 0.4= 0.6
P=0.4.
q=0.6
Heterozygous=2pq = 0.48
16+16+48/200×100=40 ,36+36+48/200×100=60
P=0.4and q=0.6
Hw p- 0.4 and q- 0.6
Thank you sir nice session🙏
A= 0.4 ,a= 0.6
A=.40
a=.60
f(AA)=0.4
f(aa)=0.6
R = 0.4, r = 0.6
DD =40, dd=60
Option nod
p=0.4
q=0.6
Sir hindi mein
HD- 0.4, hetero- 0.48 ,hr-.6
A= 0.4
a=0.6