Germany | Can you solve this? | Math Olympiad

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[@ralphtrucksess7008]

with log(50) = log(10 x 5) you could be faster ;) (log(10) = 1)
x= 1 + 1/log(5)

[@СергейИванчиков-р8д]

При условии, что логарифм десятичный

[@AlexanderSemashkevich]

x=log50/log5≈1,7/0,7≈2,42857.
The absolute error is about 0,0021.

[@승수노-z3e]

125-25=100
125÷10=10
5^2.1=35
5^2.2=45
5^2.3=55
5^2.4=65
5^2.5=75
5^2.6=85
5^2.7=95
5^2.8=105
5^2.9=115
5^3=125
5^2.2~5^2.3=10
10÷10=1
5^2.25?

[@ilyashick3178]

5^x=50 >>>> Let 5^x=5^2*2 >>>> e ^x*ln 5=2*e^2*ln 5 >>>> ln 5* e ^x*ln 5 = ln 5 * 2*e^2*ln 5
ln 2*ln 5* e ^x*ln 5 = ln 2* ln 5 * 2*e^2*ln 5 >>>>> ln 2*ln 5* e ^x*ln 5 = ln 2* ln 5 * e^2*e^2*ln 5 >>>> ln 2*ln 5* e ^x*ln 5 = ln 2* ln 5 * e^2*ln 5 + ln 2
W[(x*ln 5) = 2*ln 5 + ln 2] >>>>> x*ln 5 = 2* ln 5 + ln 2 >>>> x = 2 + ln 2/ln 5 >>>>
Answer: x = 2+ log_5 2

[@ioannisimansola7115]

Olympiad stuff ? You are kidding 😃😃😃😃😃😃😃😃😃😃