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Guys,We can solve it as follows:-
Taking the equation and squaring on bothe sides then
(x⁹⁹+1/x⁹⁹)²=169
Applying (a+b)²=(a-b)²+4ab we get
(x⁹⁹-1/x⁹⁹)²+4×x⁹⁹×1/x⁹⁹=169
(x⁹⁹-1/⁹⁹)²+4=169
By subtracting 4 from both sides we get
(x⁹⁹-1/x⁹⁹)²=165
By Rooting both sides we get
x⁹⁹-1/x⁹⁹=√165
So his method is right and we get 4 from applying all the identity
Wow
(a+b)^2 ka formula KB se (a-b)^2 + 4ab hogya
Great explanation 👌
❤❤
Itne time mai pura exam end ho jyega😊😊
(a-b)^2 = (a+b)^2 - 4ab
Sir -4 How will come.
Trick for this Q. Root n²-4
Those who cant understand
A+b whole squre is a2plus b2 plus 2ab thus substitute a2 plus b2 by a-b whole square thus we get to another 2ab add them you get 4ab and so on take a pen copy and solveit by yourselves you will get it
4 Kaha se Aaya pehle ye btao
√(K²-4) formula
Nice solution❤
Sir 4 kaisa aaya
Sir 4 kese aya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Take x^99 as any other variable say y,apne aap solve kr luge
Concept se krlo 2 min m ho jayenge trick ke piche mt bhago
how to 4 make a question ❓
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Lol.. ,consider x⁹⁹=a then (a+ 1/a)²= 169
a²+1/a²=169 -2
(a- 1/a)²=y²
169-2-2=y²
y=root under 165.........chilll
Option b
Bhai logic to batao.. kis logic k basis pe steps kia?
"Root n^2-4" is the formula for this type of question.
Underroot 13^2-4
How 4 came
13 ka square 169- hai+me hoga 169+2=171
-4 hoga bri
√169-4
Sir -4 kyun batado pls
√n^2-4
Ye 4 kese aya ?
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
√165
Minus 4 knyu kar rahe hnne
Bro cube root wale question me square root ka formula laga krr aspirants ko ullu MTT banao yrr😢
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
...Now solve it with cube root .
Please don't try to prove the right thing as wrong .
√169-4............-4 Kyun liya ??
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir Ye 4 kanha se aya sir please bataiyye sir 🙏🙏🙏
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
nice
4 kese aaya???
मैं भी youtube में maths के video डालता हूं, आप मेरे channel में जा के देखें, और अपना अनुभव comment करें, thanks 🙏🙏
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir 4 kahan se aya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir samjha me nhi - 4 kaha se karege
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4 ko hatane ka reason kya hai
Bridging concept hai. + seh - jane meh
4 kaise add karna ?
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir (a-b)^2 to a^2+b^2-2ab
Or
(a+b)^2 to a^2+b^2+2ab
Hota he to 4ab kese ho gaya aapka sir
Guess karna hoga
a-b whole square minus a+b whole square @@amitkumarsethi8760
Super sir
-4 kyu kya sir very confusing
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4 kha se aa gya yr to btao sir???????????????????????
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Agar plus ho tho ..plus 4 karni hai?
No minus
4 kahan se aya sir??
64
165 root under
165
Agar X ke power me even no. Hua tb bhi aise hi krenge? Jaise X^98
Yess.. Bs same no. Hona chahiye + aur - dono mei
Frm where 4 cm frm
Sane question 😊
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
x^99 = t
Phir 13-2/x^99
Batao 4 Kaha se aaya
B
Bridging formula
👍
4 kaise aaya
मैं भी youtube में maths के video डालता हूं, आप मेरे channel में जा के देखें, और अपना अनुभव comment करें, thanks 🙏🙏
WHY MUNIS 4
4 kaise aaye
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Those who don't know this problem could be done by Am greater or equal to Gm
What's this Am and GM ...?
@@Money-py5xq concept in algebra arithmetic mean is greater than and equal to geometric mean
4 khan se aaya
इसमें माइन्स चार कैसे आए
Bb
Yahan per 4 kyon ghata rahe hain sar ji
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
/165
_4 kiu
B dekhai hi bata diya
Bro why is it logic less thoda sa to explain kijiye
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
How 4 as came into the picture sir...13square - 4 how??? 😢That's why algebra= cobra 😂😂😂😂
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
मैं भी youtube में maths के video डालता हूं, आप मेरे channel में जा के देखें, और अपना अनुभव comment करें, thanks 🙏🙏
Root 165
4 kyu kahan se aaya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Kya karrrenge?
4 kaise join hua
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Me from 11th class done it with minute with proper method 🤗🤗🤗🤗🤗🤗
Very good
It's an 8th standard question.
@@dipankarbasak07🤦negativessss🙏
Hm kyo 4 minus krenge batao sr ji
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
@@TUMIJITBEaahhhh I'm gonna crazy 😂😂
I got 2 instead of 4 while solving
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
13
Bouncer
Why 4
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4kahase aya sir
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
The correct ans for this problem is √11
Why minus 4?
Sb kamal (a-b) *2 and (a+b) *2 ka hai 🙂🙂
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir yahan par 4 kaise aa gya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
165rootme
165 is right answer
-4 kyo karna hai
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4 kese hua
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Bro bringing 4 like nothing
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Sir Ji 4 He Kiu Subtract Kiye Aap 😊
Bridging concept
X ki power 1000 ho. Ar dusre bar me 5000 ho to
Yes, Same method
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
root of p2 -4
Slow down dude
_4 q kiye sir
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4 khha sa aya???
4 q aya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
j
-4kyu liya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
but 4kaise aaya😐
√165✓
Hm 4 minus kyon krege
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
4 hi kyu minus kiya jayega 🤔🤔🤔🙄🙄
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
😂😂
hm minus 4 kyu karenge aur ye kha se aa gya
(a+b)whole square=(a-b)^2+4ab
Now, (x^99+1/x^99)=13 (given)
(x^99+1/x^99)^2=13^2(squaring both side)
Or, (x^99-1/x^99)^2+4.x^99.1/x^99 = 169
Or, (x^99-1/x^99)^2+4 =169
Or, (x^99-1/x^99)^2=169-4
Or, (x^99-1/x^99)^2=165
Or, (x^99-1/x^99)=✓165.
Hamesha 4 hi hoga
Yes
Bakwas shorts ...
171 correct 💯
(a-b) *2=(a+b) *2 -4ab
√165
165
Bb