@RealityMarble It's just a "typo" when I rewrote the problem on the top of the next page. It was still in my calculator as 87/5 and then correctly yields 18 after the next pivot. Thanks for the catch!
@tsewell1984 Here's the first column before the row operations: 3, 2, -2 And after the 1/5 R1 --> R1 Operation would be 1/5 * 3 = 3/5 --> R1 3/5, 2, -2 And after -1 * R1 + R2 --> R2 operation would be -1*3/5 + 2 = -3/5 + 2 = -3/5 + 10/5 = 7/5 --> R2 3/5, 7/5, -2 Does that make sense? Am I missing something? Scott
There's an error.. In the second pivot operation the last two operations are supposed to be amended to: r1-(3/7)*r2 and r3+(1/7)*r2. That is the only way you can make the first columns #s (other than the pivot) zero. Correct me if I'm wrong.
can you plz help me out with these 2 problems 1. Max Z= 4x1+ 10x2 sub to 2x1+ x2 less than equal to 100, 2x1+ 5x2 less than equal to 200, 2x1+ 3x2 less than equal to 180 x1, x2 more than equal to 0 2. Min z=2x1+ 3x2 sub to 7x1+ x2 more than equal to 14, x1+ x2 more than equal to 6 x1, x2 more than equal to 0
Actually, I think I am correct. I don't think I said to divide 21/5 by 5/7. The process is to divide 21/5 by 7/5. To do that you multiply 21/5 by the reciprocal of 7/5, which is 5/7. So, 21/5 (5/7) = 3
@RealityMarble
It's just a "typo" when I rewrote the problem on the top of the next page. It was still in my calculator as 87/5 and then correctly yields 18 after the next pivot. Thanks for the catch!
Please upload more videos on the Two Phase Method ,etc. You are a good teacher !
seriously the only way I am going to pass my quiz tomorrow. Thanks so much!
Thanks a lot dude, you've put this extremely simply :)
Just a problem is in the second table RHS of Z row should be 87/5 instead 87/25
+Timur Keskinturk yeah I got 87/5 as well.
thank you man, that really helps all the way from the UK, thanks again
I LOVE YOU SO MUCH RIGHT NOW. THANKYOUU. YOU PRACTICALLY SAVED ME FOR MY FINALS.
what would be the dual optimal solution from this tableau?
great vid btw
thank you so much, you helped a lot!
Infinetly thanks to you, for uploading such a nice vedios.
that help me allot and i hope it ll b very useful for everyone.
@tsewell1984
Here's the first column before the row operations:
3, 2, -2
And after the 1/5 R1 --> R1
Operation would be 1/5 * 3 = 3/5 --> R1
3/5, 2, -2
And after -1 * R1 + R2 --> R2
operation would be -1*3/5 + 2 = -3/5 + 2 = -3/5 + 10/5 = 7/5 --> R2
3/5, 7/5, -2
Does that make sense? Am I missing something?
Scott
Can you do one that's without the dual and what are the criteria for standard and non standard minimisation? Also is there nonstandard maximisation?
There's an error.. In the second pivot operation the last two operations are supposed to be amended to: r1-(3/7)*r2 and r3+(1/7)*r2. That is the only way you can make the first columns #s (other than the pivot) zero. Correct me if I'm wrong.
what happens if i have a negative number in my row 3 and both ANS/x1 are negative?
sir i have a doubt...Cj-Zj of 2nd table should be [1/5 0 -3/5 0 1]?
can we write s1 and s2 instead y1 y2
sir please.........give an example for two phase simplex method plzzzzz
thanks a lot !
instead of 7/5 shouldn't it be 13/5.... bc -1 times -3/5 = positive 3/5 (not negative)
then add it to 2 which equals 13/5.....
can you plz help me out with these 2 problems
1. Max Z= 4x1+ 10x2
sub to 2x1+ x2 less than equal to 100, 2x1+ 5x2 less than equal to 200, 2x1+ 3x2 less than equal to 180
x1, x2 more than equal to 0
2. Min z=2x1+ 3x2
sub to 7x1+ x2 more than equal to 14, x1+ x2 more than equal to 6
x1, x2 more than equal to 0
Actually, I think I am correct. I don't think I said to divide 21/5 by 5/7. The process is to divide 21/5 by 7/5. To do that you multiply 21/5 by the reciprocal of 7/5, which is 5/7. So, 21/5 (5/7) = 3
The dual optimal solution for this problem is going to be x1=3,x2=4,z=18 and y1,y2=0
you made a mistake in your last pivot where you said 21/5 / 5/7 istead of 7/5!
Thank you so much man! your sound like Patrickjmt, i hate those videos of Pakistani and indian accents...
The answer is 18