Conservation laws AS Physics

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  • Опубликовано: 25 авг 2024
  • Brief description of conservation of baryon number, lepton number and charge.

Комментарии • 50

  • @sahal02201
    @sahal02201 8 лет назад +21

    you've taught me more in an hour than my physics teacher(s) have in 8 months thanks

  • @kk1200ts
    @kk1200ts 9 лет назад +6

    Excellent introduction, simple and short, no useless blah blah. Thanks.

  • @mathonline8787
    @mathonline8787 Год назад +1

    Beautifully explained💯💯

  • @pipertripp
    @pipertripp 7 лет назад

    This is a gem of a video. I'm just learning this stuff for fun so no text to provide a framework. This video laid a nice foundation for thinking about interactions. Looking forward to the rest od the series.

  • @anythingbutyou7221
    @anythingbutyou7221 5 лет назад +1

    you did it in 7:24 and it took weeks for me to understand from my teacher! Thank you so very much!

  • @kylecalbert8734
    @kylecalbert8734 9 лет назад +3

    YES YES YES!!!!!!! AWESOME TUTORIAL DUDE!!!.

  • @loutlier6649
    @loutlier6649 4 года назад +1

    THANK YOU FROM FRANCE

    • @k-9370
      @k-9370 3 года назад

      Bonjour!

  • @Spider-Cop99
    @Spider-Cop99 7 лет назад +1

    Brilliant Vid, Thanks a lot, Jack!!

  • @rubaiat-e-laila9905
    @rubaiat-e-laila9905 4 года назад

    Amazing,sir

  • @jalajarora2331
    @jalajarora2331 4 года назад +1

    Could we also look at Lepton electron and lepton muon numbers for interaction involving electrons and muons?

  • @ajaypun3540
    @ajaypun3540 3 года назад

    thank you !! very helpful, hope you will cover most of the as / a level topics.

  • @mohammedd2483
    @mohammedd2483 9 лет назад +4

    For the lepton number you should do the Le separate from the Lu

  • @ahanafnissan6284
    @ahanafnissan6284 7 лет назад

    thank u sir u saved me from lot of pain

  • @meharpalbasi4801
    @meharpalbasi4801 7 лет назад +2

    Why do you not split the Lepton numbers into le/lu?

    • @champion171299
      @champion171299 7 лет назад +1

      Meharpal Basi If there is only one of the two present, you do not need to consider both.

  • @jalajarora2331
    @jalajarora2331 4 года назад

    It's mentioned on the AQA spec

  • @maryroyc
    @maryroyc 5 лет назад

    Well explained.. Thank you!

  • @domr8796
    @domr8796 8 лет назад +1

    awesome cheers

  • @HassanKhan-hu7qm
    @HassanKhan-hu7qm 8 лет назад

    Thank you very much very clear now

  • @astolfo9377
    @astolfo9377 7 лет назад

    Love you

  • @omarshah7
    @omarshah7 10 лет назад

    I absolutely love u !!!!! Many thanks

  • @sonirana7943
    @sonirana7943 10 лет назад

    You're the best!

  • @taitywaity1836
    @taitywaity1836 9 лет назад +2

    for the last example how can you tell, without adding up electron number, that the missing particle is an electron neutrino and not a muon or tau neutrino?

    • @lifesnotstill5003
      @lifesnotstill5003 9 лет назад +1

      Since the product had an electron in it as well.

    • @pipertripp
      @pipertripp 7 лет назад

      taity waity if the charged let on had been an anti-muon or anti-tau the flavour of neutrino would have corresponded to that charged lepton. The generation of the charged lepton will determine the flavour of neitrino... that's my understanding anyways.

  • @GT-eg4vu
    @GT-eg4vu 7 лет назад

    thank you

  • @dggrossman7217
    @dggrossman7217 6 лет назад

    I thought the proton was stable. You show it decaying to a neutron, positron, and electron neutrino? Does that happen?

    • @jacksheldrake7712
      @jacksheldrake7712  6 лет назад

      Yes, well done, the proton is extremely stable. This decay is a part of the A-level course you must be aware of (positron decay)

  • @vincentndrws
    @vincentndrws 4 года назад

    Were is spin?

  • @Ryan-mg2uv
    @Ryan-mg2uv 7 лет назад

    I'm trying to find a particle, "x" but what do I choose if it has more than one option it could be

    • @champion171299
      @champion171299 7 лет назад

      yeyebsjw sjeudhene Just choose one, I think in the mark scheme it would allow both.

    • @champion171299
      @champion171299 7 лет назад

      yeyebsjw sjeudhene Just choose one, I think in the mark scheme it would allow both.

  • @angeliroz8267
    @angeliroz8267 7 лет назад

    how is the third example a weak interaction if all the particles are hadrons?

    • @champion171299
      @champion171299 7 лет назад

      Angeli Roz Alvarez Because strangeness is not conserved.

  • @adamhassan4875
    @adamhassan4875 10 лет назад

    great video :) I just wanted to know how do you tell the difference between a strong and weak interaction

    • @mohammadyahyachhapra1363
      @mohammadyahyachhapra1363 9 лет назад

      The strangeness must be conserved in order to be a strong interaction, if the strangeness doesn't balance out then that means that the equation leads to a weak interaction. Hope this helps.

    • @1qualitybacon
      @1qualitybacon Год назад

      @@mohammadyahyachhapra1363 so even tho its a neutral kaon it still has a strange quark?

  • @shaungray531
    @shaungray531 8 лет назад

    how do you tell if the particle is a lepton or a baryon?

    • @jacksheldrake7712
      @jacksheldrake7712  8 лет назад

      A lepton is an electron, muon or neutrino. There is another (Tau) which you don't need to know. The only baryons you need to know are protons and neutrons. You do aldo need to know that a particle made of 3 quarks is a baryon. These are facts you must know in order to understand anything about conservation laws. Hope that helps!

    • @shaungray531
      @shaungray531 8 лет назад

      thank you! I had my Physics paper 1 mock exam yesterday and I'm so grateful of your videos! There was a few questions which i knew due to these videos... Thank you!

    • @jacksheldrake7712
      @jacksheldrake7712  8 лет назад

      Absolute pleasure, glad it helped!

  • @RealImaginGaming
    @RealImaginGaming 8 лет назад

    Could Particle X also be a muon neutrino??

    • @jacksheldrake7712
      @jacksheldrake7712  8 лет назад +1

      No, there are no muons in the equation. This is why it is an electron neutrino. It is there because the electron is there. Hope that helps!

    • @RealImaginGaming
      @RealImaginGaming 8 лет назад

      Thanks so just for clarity when there's an electron in that equation X is an electron neutrino so when the electron is replaced by a negative muon X would be muon neutrino???

    • @jacksheldrake7712
      @jacksheldrake7712  8 лет назад

      Yes, you've got it!

    • @RealImaginGaming
      @RealImaginGaming 8 лет назад

      +jack sheldrake thanks lol I wish you were my teacher, just I suggestion I think you should monetize your videos cause your videos are quality

  • @GameHelperReviewers
    @GameHelperReviewers 9 лет назад

    Don't like it blad