Don't blindly apply, UNDERSTAND Bra Ket Notation with this! | Quantum Theory

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  • Опубликовано: 20 июл 2024
  • This is the fourth video in my Quantum Theory playlist. I give a detailed explanation of Bra Ket Notation (aka Dirac Notation) and highlight why it works due to the Riesz Representation Theorem.
    0:00 Introduction
    0:36 Inner Products vs Linear Functionals
    1:57 Dual Space vs Hilbert Space
    2:26 Riesz Representation Theorem explained
    3:36 Bra Ket Notation explained
    6:23 Example of the usefulness of Bra Ket Notation
    7:55 Conclusion
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    If you have any questions or suggestions for future videos, please leave a comment here or shoot me an email at abidebyreason@gmail.com.

Комментарии • 34

  • @BrianDLee
    @BrianDLee 3 месяца назад +3

    This is the clearest explanation anyone has ever given about anything. Made one of the most confusing things to me clear as water. Thank you sir!

    • @AbideByReason
      @AbideByReason  3 месяца назад +1

      you are welcome. Glad it cleared things up for you!

  • @celestial5279
    @celestial5279 6 месяцев назад +4

    This is phenomenal! I just finished a class in quantum information theory this past semester. The use and manipulation of bra-ket notation quickly became a necessary skill for the course. This video is definitely going to be my go-to recommendation for anyone I meet who is interested in getting into the subject.

    • @AbideByReason
      @AbideByReason  6 месяцев назад +1

      thank you for the kind note and recommendation!

  • @ribamarsantarosa4465
    @ribamarsantarosa4465 6 месяцев назад +7

    Me, as an engineer, just see bra as row vectors and and kets as column vectors, and the (double) bar as a sort of dot product: yields a matrix, |a>|b> (or

    • @AbideByReason
      @AbideByReason  6 месяцев назад +5

      yes, that's one way to look at it that can be useful in certain circumstances. I think you also meant the other way around, yields a number and |a>

    • @matteoserafini7704
      @matteoserafini7704 6 месяцев назад

      That's actually not exactly true: kets and bras are elements of an abstract Hilbert space and its dual space, respectively. Row and column vectors are merely their representations in the isomorphic space C^n

  • @pranayagrawal5744
    @pranayagrawal5744 5 месяцев назад +2

    I don't know why but this makes much more sense after having learnt tensors . I think the Riesz Representation theorem is similar to the correspondence between the vector space V and the dual space V* (covector space). Interestingly, again the corresponding covector to any vector u in the vector space V is the u._ operator. Lovely explanation by the way!

  • @davidrtx0
    @davidrtx0 6 месяцев назад +3

    I'm a math major in undergrad right now, and this video is so good, you have such great and clear presentation skills! I still haven't gotten to a formal class that's taught Hilbert and dual spaces, but I've seen the little hints towards it in my textbooks and in my own explorations. I've tried looking into it, but it hasn't felt as independently approachable compared to other subjects for me. I never had a deep understanding of the 'why' in the abstract algebra classes I've taken (probably bc I haven't taken a QM class it seems), but this video made something click in my head. Thank you for sharing!!

    • @AbideByReason
      @AbideByReason  6 месяцев назад

      Glad you were able to get something out of this video!
      In my experience, Hilbert Spaces were only briefly mentioned in one of my undergrad math classes (Real Analysis) but came up a bunch in QM. It seems most common to not really get into Hilbert Spaces (as a math student) until taking graduate level Functional Analysis. Dual Spaces are much more approachable independently though. Any good upper division Linear Algebra textbook should address them.
      Thank you so much for the kind note!

  • @lolmanthecat
    @lolmanthecat 6 месяцев назад +5

    6:00 "if you are trying to do rigorous math proofs this notation will probably only be cumbersome and sometimes even cause confusion" *proceeds to make a rigorous proof of the fact that the sum of tensor products of the element of a basis with their respective dual basis elements is the identity.*

    • @AbideByReason
      @AbideByReason  6 месяцев назад +1

      Thanks for the comment!
      This is actually a really good example of how attempting to make things rigorous in a way that would satisfy mathematicians actually DOES become cumbersome. Just 2 brief questions to address would be:
      1) Is the sum infinite or finite and does what I did in my "proof" still work if the sum is infinite?
      2) Also, how does one interpret what's in the sum as a tensor product? Since a tensor product like f tensor g would need to have 2 elements as an input like (a, b) where f tensor g (a, b) = f(a) g(b). But here there appears to be only 1 input element, |psi>.
      There are more things that need to be addressed. All of this works because of the rigorous math behind it, but I do think in general mathematicians would prefer to just stick with a more conventional notation. That of course doesn't mean that there aren't exceptions or that this notation isn't incredibly useful!

  • @rishabh01solanki
    @rishabh01solanki 6 месяцев назад +6

    Such a clear explanation! Excellent work. 🎉

  • @kgblankinship
    @kgblankinship 6 месяцев назад +1

    Very clearly put ! Going through the math itself, it's hard to get an appreciation of its significance.

  • @TheLokomente
    @TheLokomente 6 месяцев назад +3

    Let’s go 💯💯 great vid

  • @tobiassteindl7792
    @tobiassteindl7792 6 месяцев назад +1

    Such a great video! I love it because I have a background in mathematics and am now learning about Quantum Computing

  • @grawl69
    @grawl69 6 месяцев назад +1

    Excellent presentation, thank you.

  • @Dr.HarshTruth
    @Dr.HarshTruth 6 месяцев назад +1

    Great video!

  • @drdca8263
    @drdca8263 6 месяцев назад +1

    One thing which I think might be nice to elaborate on, is, how to write how linear operators act on these.
    Like, if one has a Hermitian operator H, then works, because =
    But what if I have some operators that aren’t self-adjoint, and I want to apply them to the two vectors?
    Do I write
    Or should I write ?
    If I think of

    • @AbideByReason
      @AbideByReason  6 месяцев назад +1

      thanks for the suggestion. I plan to make a video on operators in the near future, so stay tuned!

  • @garyknight8616
    @garyknight8616 6 месяцев назад +2

    Think my braincell has just blown a fuse. I will have to come back to this after a good night's sleep.

  • @omargaber3122
    @omargaber3122 6 месяцев назад +1

    Thanks❤

  • @ColbyFernandez
    @ColbyFernandez 6 месяцев назад +1

    Cant we only consider continuous linear functionals for the Riesz Rep theorem?

    • @AbideByReason
      @AbideByReason  6 месяцев назад

      yes you are correct, the dual space of bras will only be the linear functionals that are continuous.

  • @Student-js4qy
    @Student-js4qy 4 месяца назад

    bro what is all these spaces I only took linear algebra

    • @AbideByReason
      @AbideByReason  4 месяца назад

      This is applied linear algebra :)

  • @CosmicHase
    @CosmicHase 6 месяцев назад +1

    The name makes me highly uncomfortable.

    • @frank_calvert
      @frank_calvert 6 месяцев назад

      i love brasseire-ketamine notation :)

    • @CosmicHase
      @CosmicHase 6 месяцев назад

      @@frank_calvert ok that's better