What an amazing video! So well made: concise, clear, easy to follow and relevant! Probably the best video on this topic on RUclips and trust me I've been searching all day lol. Subscribed!
This explained the Lagrange error bound perfectly! Thank you for going down to a reasonable depth, it shows that you have had good teachers in your life...thank you for passing them onto us :) Keep up the great content!
This is 5 million times better than sitting in a class for an hour and a half listening to your teacher read meaningless equations off a note packet. It feels good to actually be taught something somewhat complex by someone who actually cares to explain it.
This video is amazing! I had a question on the calculator function that you showed at the end of the video. Which calculator do you use? And is that function necessary? Because I use a TI84, and I don't think it has that true/ false statement function.
Thanks! I use a TI-Nspire CX II CAS (long name...). The thing I did at the end is definitely not necessary. I was just showing how the inequality is true for that example.
You're looking for the maximum of 24(1+x)^(-3) on the interval from 0 to 0.2. Since 24/(1+x)^3 is a decreasing function, the maximum will occur at the left endpoint, which is x=0. So the maximum is 24/(1+0)^3 = 24. Hope this helps!
Well you have two options. First is to think it through: the numerator is constant while the denominator gets bigger so overall the fraction will decrease in size. The other option is to just find the derivative and you'll see that the derivative is always negative on that interval so its function is decreasing.
Just wanted to say that this is probably one of the best videos I've found on the Lagrange Error Bound. Thank you.
What an amazing video! So well made: concise, clear, easy to follow and relevant! Probably the best video on this topic on RUclips and trust me I've been searching all day lol. Subscribed!
thanks! good luck with your studies!
This explained the Lagrange error bound perfectly! Thank you for going down to a reasonable depth, it shows that you have had good teachers in your life...thank you for passing them onto us :) Keep up the great content!
This is 5 million times better than sitting in a class for an hour and a half listening to your teacher read meaningless equations off a note packet. It feels good to actually be taught something somewhat complex by someone who actually cares to explain it.
I appreciate the comment! Good luck with your studies!
By far the best explanation I have found on this topic, great work!
MY AP CALC BC EXAM IS TMR AND YOU SAVED ME THANK YOU
sooo real i’m doing last min review😭😭
This is REALLY HELPFUL. Thank you so much for doing this video.
that makes so much sense. clear, to the point, well stated
probably the neatest explanation I've seen, thank you!
this video was so helpful man. Thank you so much
Lets get this bread tomorrow 😤
Really helpful and detailed video. Thank you
based and redpilled
Well explained
This video is amazing! I had a question on the calculator function that you showed at the end of the video. Which calculator do you use? And is that function necessary? Because I use a TI84, and I don't think it has that true/ false statement function.
Thanks! I use a TI-Nspire CX II CAS (long name...). The thing I did at the end is definitely not necessary. I was just showing how the inequality is true for that example.
@@turksvids got it. Thanks!
THANK YOU
Thank you so much ❤
This is so great!
Thanks! Please share with anyone you think could benefit!
Great Video, thanks
How do you find M. I didn’t understand how you got 24 for M. Please help
You're looking for the maximum of 24(1+x)^(-3) on the interval from 0 to 0.2. Since 24/(1+x)^3 is a decreasing function, the maximum will occur at the left endpoint, which is x=0. So the maximum is 24/(1+0)^3 = 24. Hope this helps!
@@turksvids thanks. But how do I know if a function is decreasing or increasing just by looking at it?
Well you have two options. First is to think it through: the numerator is constant while the denominator gets bigger so overall the fraction will decrease in size. The other option is to just find the derivative and you'll see that the derivative is always negative on that interval so its function is decreasing.
bruhh you didn't explain why it works lol thats what i was looking for XD
sorry it wasn't the video you were hoping for!