Good information. Thank you. I am also protection engineer. So I have a doubt, did you ever try to test the mutual compensation in distance rely p444 with realy test ki. If so, please share. Thank you.
Good Day sir, as an aspiring protection engineer can i ask you sir for any tips you can give to me that should i do from the start of learning. Thank you sir
(ratios are primary (line value) / secondary (transformed value for measuring)). Current transformer ratio is 800/1 (=800), and Potential transformer is 132/sqrt(3) kV (its kV!) and 110/sqrt(3) (=1200) .
very nice , informative
Nice explanation bro 👍
Thanks!
Nice explanation of the topic
I love Your explanation. Upload more videos with verious topics & also teach us relay configurations. 🙏🙏
Very good 🙏🙏🙏🙏🙏
Thankyou so much sir, today i understand how we do settings in this relay.
Need ur support, make video like this.
Thank for watching. There are three parts for calculating settings of distance relay. You may also go through other two parts also.
How we select the tripping time for 300 to 350ms we have any standard or it is in some practice.
Why we not consider transformer impedance in zone 2,as the first transformer at substation B comes in zone 2 area??
@@ImranKhan-nu6xw Zone -2 reach is considered to cover the impedance reach of far end busbar fault.
Good information. Thank you. I am also protection engineer. So I have a doubt, did you ever try to test the mutual compensation in distance rely p444 with realy test ki. If so, please share. Thank you.
Good Day sir, as an aspiring protection engineer can i ask you sir for any tips you can give to me that should i do from the start of learning. Thank you sir
wher did you get time (T)?
why not considered R0 ,X0 and Xm in calculation??
Calculation of R0 and X0 is mentioned for distance relay in part-2
If line length is less than 100 km then what should be percentage of z4?
20%
CT ratio/PT ratio
How did you get 800/1200
Please explain
(ratios are primary (line value) / secondary (transformed value for measuring)). Current transformer ratio is 800/1 (=800), and Potential transformer is 132/sqrt(3) kV (its kV!) and 110/sqrt(3) (=1200) .
Hindi m bol lo jayda like hoge....😂
Thank you for your comments. I will definitely make video in Hindi also.