Hello , can you make a video for graph of a function like some radical function and then to find domain , y intercept x intercept, asymptotes , extremes , concavity and these kind of things ? But keep going great video !
if the original line was in term of log5, I would expect the answer to be with log5 I'll try myself y' = (x+1)/(xln(5)) = 1/x * ( lne^(x+1)/ln(5)) = 1/ln(5) * (ln( e^( (x+1)/x ) ) = log5( e^( (x+1)/x ) )
![Calculus of even and odd functions[Re-upload]](http://i.ytimg.com/vi/aDpM-W5txBw/mqdefault.jpg)
![Calculus of even and odd functions[Re-upload]](/img/tr.png)
Very detailed explanation, clearer than what my university professor gave,thanks!
From Taiwanese.
Glad it was helpful!
Please solve some questions on coordinate geometry
dy/dx [LOGa(B)] = 1/xlna
Using this fact and the chain rule we get
1/[(x)(e^x)(ln5)] × [e^x + xe^x]
Which simplifies to (x + 1)/(xln(5))
Great video!
Sir, Your teaching style is very attractive and amezing.😊😊.
Love from India .
Thanks and welcome
Great tutor
The very moment you smile, I hit the like button! I know the rest of the video will be a charm! You are the best passionate Maths teacher on web!
Not what I was expecting. I've seen a lot of Lambert W function videos lately... and my eye was instantly drawn to the "x *e^x" part. LOL
I was expecting this to work somehow:
5^y = x*e^x
Or u can simply tak log5 on both sides and use the differnetation of 5^y----5^y ln5 and later on put 5^y=xe^x
02:07 A normal person: Ignores 1/ln5 because it’s a constant
Me, an intellectual: QUOTIENT RULE
🤣🤣🤣🤣🤣
Great video as always!
Glad you enjoyed!
Hello , can you make a video for graph of a function like some radical function and then to find domain , y intercept x intercept, asymptotes , extremes , concavity and these kind of things ? But keep going great video !
I already have those videos. Search Curve sketching
Mans writes better on chalk than i do on a paper.
Why cant you just apply the chain rule??
Still waiting for your vedio on vector CALCULUS Sir 🙇@ prime newton
Coming soon
Why does the derivative of 1/ln5 not become as 0???
? Ur self what's the derivative of 2x , and watch it again, And u will get ur answer
Sorry, I made a careless mistake and thank you for rectify my mistake
bonsoir sire vous pouvez utiliser la méthode log5 directement
if the original line was in term of log5, I would expect the answer to be with log5
I'll try myself
y' = (x+1)/(xln(5))
= 1/x * ( lne^(x+1)/ln(5))
= 1/ln(5) * (ln( e^( (x+1)/x ) )
= log5( e^( (x+1)/x ) )
Nice!
My result (1+1/x)/log5
Do some epsilon / delta type proof problems. They always gave me trouble at uni when I was doing my degree
asnwer=1x isit