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Simple Golden Ratio problem: Divide numerator and denominator by √3 to obtain φ^6=[(√5-1)/2]^6 where φ is the positive root of φ^2=1-φ.Thus, φ^3=φ-φ^2=2φ-1 and φ^6=(2φ-1)^2=4φ^2-4φ+1=5-8φ, so [(√15-√3)/√12]^6=5-4(√5-1)=9-4√5
Great work ! Thank you so much !
Break it further to (_/5-2)^2
?????
Simple Golden Ratio problem: Divide numerator and denominator by √3 to obtain φ^6=[(√5-1)/2]^6 where φ is the positive root of φ^2=1-φ.
Thus, φ^3=φ-φ^2=2φ-1 and φ^6=(2φ-1)^2=4φ^2-4φ+1=5-8φ, so [(√15-√3)/√12]^6=5-4(√5-1)=9-4√5
Great work ! Thank you so much !
Break it further to (_/5-2)^2
?????