In this video lecture only full wave rectifier is explained whose output is pulsating DC which contains ac component (ripples) also. In any rectifier We need to connect capacitor to remove ripple from the DC output. Hope you understood.... SUBSCRIBE and keep supporting EC Academy 👍
It depends on the question... If they ask you to mention then just write the formula... If they ask you to derive the expression then you have to do the derivation.... Hope this was helpful... Do SUBSCRIBE and keep supporting EC Academy ✌
No… as per our connection in the negative half cycle the current will be due to the conduction of diode D2. Hope this is helpful.... Do subscribe and keep supporting EC Academy ✌️
Depending upon ur application you can use any one of the transformers.... but usually for electronic devices “step down” transformer is used. For example 230V ac is step down to around 5V DC by your mobile charger. SUBSCRIBE and keep supporting EC Academy 👍
In practical diode we can not obtain 100% efficiency due to forward voltage drop across the PN junction. Hence it is having the efficiency of around 81%. 100% efficiency can be obtained if we use ideal diode... but ideal diode does not exist. Hope you understood.... SUBSCRIBE and keep supporting EC Academy 👍
Hello friends, due to technical issues and lost recording, I am uploading this video in black and white. Thank you for your support! 🙏🙏
😢😢😢
Love you your effort
Nice lecture easy and understandable.Thank you sir
Luv u sir for EC ACADEMY...❤️
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Tq so much for your clear explanation sir😊
So nice of you
Thank you for your feedback…
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In full wave rectifier model, . Is it necessary to connect a capacitor. . .?!??
In this video lecture only full wave rectifier is explained whose output is pulsating DC which contains ac component (ripples) also. In any rectifier We need to connect capacitor to remove ripple from the DC output.
Hope you understood.... SUBSCRIBE and keep supporting EC Academy 👍
It's realy helpfull to us sir thank you
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Sir in exam we can directly write the efficiency and ripple factor values...or..we must derive and than write
It depends on the question... If they ask you to mention then just write the formula... If they ask you to derive the expression then you have to do the derivation....
Hope this was helpful...
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from which information are you getting 81.2% efficiency??? and also the? ripple of 0.482???
There is a derivation for all these values, which I have not done in this video.
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Go through this #129 Efficiency of a Full wave rectifier || EC Academy in the playlist
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Your way of explaination is very nice but
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The ad is due to your recent search history 😃
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Excellent 🎉
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is this black and white your style..???
Due to some technical issues and lost recording, the video is uploaded in B&W
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Superb sir💥
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Simply superb sir❤️
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Excellent 👌👌 sir
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Nice
Superb explanation SIR !!
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Supersir
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Writing and the diagram must be shown in fast forward (only if there id no expailnstion for those)
If writing diagram and waveform is shown.... then it will be helpful to many students to know how to write them👍
Sir, during the negative half cycle will the current produced by diode 2 will flow through load resistor?
No… as per our connection in the negative half cycle the current will be due to the conduction of diode D2.
Hope this is helpful....
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So the current due to the conduction of D2will not flow through load resistor.. Am I right sir?
@@sonababu2416yes
Thank you so much sir
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Yes I will support always your channel
Superb sir🙏🙏🙏
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It is StepUp transformer or StepDown Transformer..
Depending upon ur application you can use any one of the transformers.... but usually for electronic devices “step down” transformer is used. For example 230V ac is step down to around 5V DC by your mobile charger.
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Tq so much sir
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Nice video
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Suprrb broo.... Nizz teaching 😊😊
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Superb 😎
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Super sir
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6the seem ena idhi
Acha h but explain thora kam kiya h but good job
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Tq sir❤️
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why efficiency is 81.2% why not 100%
In practical diode we can not obtain 100% efficiency due to forward voltage drop across the PN junction. Hence it is having the efficiency of around 81%. 100% efficiency can be obtained if we use ideal diode... but ideal diode does not exist.
Hope you understood.... SUBSCRIBE and keep supporting EC Academy 👍
super
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Tq
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Super
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Can we get full notes??
Nice
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