Enroll to attend CSIR NET Life Science Classroom Coaching: ifasonline.com/life-science-classroom-coaching.jsp To Purchase CSIR NET Life Science Study Material: ifasonline.com/life-science-study-material.jsp To get CSIR NET Life Science Online Test Series: ifasonline.com/life-science-online-test-series-plan.jsp Free Practice Questions: ifasonline.com/free-online-test-series-for-life-science.jsp 📞 Call IFAS for detail Information: 8600734656/91722-66888
Kya baat hai sir bohot hi asan language mein samzaya apne sab. Koi chem teacher bhi na sikha paye. Kaash muze ye channel kuch saal pehle mil jata to aaj mein NET qualified ho jata. Fir se preparation karne ki soch raha hu video dekh kr
This lecture covers following topic 00:05:54 What is solution? 00:08:40 What are different types of solution? 00:24:42 what is mole? 00:43:12 How to prepare molar solution? 01:12:53 How to prepare normal solution? 01:23:52 How to go for dilution of solution?
Hello, 💐Greetings From IFAS! India's No.1 Institute For CSIR NET SET GATE! If You Want More Details For CSIR NET/ SET/ GATE/RPSC/UPHESC?? Contact For More details!👇🏻 Regards, IFAS @8600734656
Sir,aap jese padhate hai mereko lagta hai ki sare ke sare students...jo IFAS ONLINE LIFESCIENCE follow karte hai wo net qualify karjayenge..You are great sir.
Mole concept in such a easy way..... It's just impossible topic become possible for me.... thanks alot for such a wonderful lecture 🙏..... Blessed to be a part of Ur teaching
Sir please provide us more free lectures on RUclips...it's so helpful for our preparation and you teach so nicely..so please provide us more free classes. Thank you
Great work towards the future of our nation......towards the studentsand to those also who were not able to join paid classes online as well as offline . Really it is very very beneficial to students like us ....I hope in future u also provide some important topics like genetics and molecular biology....thanks a lot to whole team of ifas😍😍😍😍 desperately waiting for your next lectures....
wonderful explanation sir......best video on this topic....plz sir dont stop make videos...it wll be very beneficial for those student who cannot afford coaching....and i never understand biochemistry but your videos are like majic sir...plz sir complete biochem syllabus...and sir protein aur enzyme bohut tough lagta hai...plz sir if possible yeh bhi parha dijiye
Hello sir... your teaching pattern is extremely good and your lectures have been really helpful to clear the basics.... sir please make one video on reaction kinetics , thermodynamics and colligative properties... I'll be waiting for your reply sir... thank you
Nice lecture sir...... wonderful sir.....it is the best lecture on this topic in you tube .....hats off to your effort sir....plz sir protein aur enzyme bhi parha dijiye....bohut tough hai....it will beneficial for those students who cannot afford teaching sir.....you are the best sir in the world....
The Formula of oxalic acid is H2C2O4. 2H2O (hydrated form), not H2C2O4. Therefore, the equivalent weight of the acid is molecular weight (126 dalton) divided by acidity (valency=2) Therefore,126/2 = 63. thus the equivalent weight of oxalic acid is 63. For For 1 N 1000 mm you need 63 g For 0.5 N 1000 ml you need 63/2 g For 0.5 N 500 ml you need 63/4 g = 15.75 g
Given Molarity of acid = 3.60 M % of suphuric acid =29 you must know MW of sulphuric acid = 98 dalton Mass of H2SO4 present in 1 L (1000 mL) of 3.6 M acid = 3.6 x 98 g = 352.8 g Let 'D' be the density of the acid. Density = Mass/Volume Mass of 1000 mL of acid = (D x 1000) g Given the percentage of H2SO4 in acid = 29 352.9 x 100/1000 D = 29 352.9/10 D = 29 290 D = 352.9 D= 352.9/290 =1.22 Therefore density of H2SO4 = 1.22 g/mL
Nacl (MW=58.5) 15 % means 15 g in 100 ml 150 g in 1000 ml 58.5 g in 1000 ml = 1 M 1 g in 1000 ml = 1/58.5 M 150 g in 1000 ml = 150/58.5 M = 2.56 Molarity of 15% NaCl solution is 2.56
![L-4 Biochemistry for CSIR NET Life Science [Hydrophobic & Vanderwaals Interaction] | IFAS I GATE](http://i.ytimg.com/vi/2x5DF86opR8/mqdefault.jpg)
Enroll to attend CSIR NET Life Science Classroom Coaching: ifasonline.com/life-science-classroom-coaching.jsp
To Purchase CSIR NET Life Science Study Material: ifasonline.com/life-science-study-material.jsp
To get CSIR NET Life Science Online Test Series: ifasonline.com/life-science-online-test-series-plan.jsp
Free Practice Questions: ifasonline.com/free-online-test-series-for-life-science.jsp
📞 Call IFAS for detail Information: 8600734656/91722-66888
Kya baat hai sir bohot hi asan language mein samzaya apne sab. Koi chem teacher bhi na sikha paye.
Kaash muze ye channel kuch saal pehle mil jata to aaj mein NET qualified ho jata.
Fir se preparation karne ki soch raha hu video dekh kr
This lecture covers following topic
00:05:54 What is solution?
00:08:40 What are different types of solution?
00:24:42 what is mole?
00:43:12 How to prepare molar solution?
01:12:53 How to prepare normal solution?
01:23:52 How to go for dilution of solution?
Hello,
💐Greetings From IFAS!
India's No.1 Institute For CSIR NET SET GATE!
If You Want More Details For CSIR NET/ SET/ GATE/RPSC/UPHESC??
Contact For More details!👇🏻
Regards,
IFAS @8600734656
First time I understood the biochemistry lecture very well... Good skill of teaching sir
Sir,aap jese padhate hai mereko lagta hai ki sare ke sare students...jo IFAS ONLINE LIFESCIENCE follow karte hai wo net qualify karjayenge..You are great sir.
Mole concept in such a easy way..... It's just impossible topic become possible for me.... thanks alot for such a wonderful lecture 🙏..... Blessed to be a part of Ur teaching
You are most welcome
Awsome teaching 👍 app jo smile karke paratey ho . It adds more ❤ to your lecture😊
Thanks!!!
Sir please provide us more free lectures on RUclips...it's so helpful for our preparation and you teach so nicely..so please provide us more free classes. Thank you
You are doing great work Sir, Salute you Sir🙏🙏🙏🙏
Thanks a lot
Thankyou Sir 🙏🙏🙏
Sir first tym I hv solved biochemistry questions very confidently..and correct
Before watching this video, ,,,"Muze Ye mere samaj ke bahar hai Aisa he lagta tha" but not now😅
Great work towards the future of our nation......towards the studentsand to those also who were not able to join paid classes online as well as offline . Really it is very very beneficial to students like us ....I hope in future u also provide some important topics like genetics and molecular biology....thanks a lot to whole team of ifas😍😍😍😍 desperately waiting for your next lectures....
We will try our best. Very happy to know that you liked content. Please keep sharing it with frinds and happy learning!!!
I need this video so much
Thanks a lot sir. Finally mujhe samjha me aya. Aaj real me biochemistry samjha me aya
Good One Thank you sir
Nice sir g
Thank u sir... Ur teaching style is so good.. Vry easy way to understand all dis
Thank you so much sir for your helpful lecture.👌👌.
Most welcome
Well done sir.. excellent
Many thanks
Awesome.never got an explanation like this before
Glad it helped!
wonderful explanation sir......best video on this topic....plz sir dont stop make videos...it wll be very beneficial for those student who cannot afford coaching....and i never understand biochemistry but your videos are like majic sir...plz sir complete biochem syllabus...and sir protein aur enzyme bohut tough lagta hai...plz sir if possible yeh bhi parha dijiye
I will try my best
Nice lectures Sir.
Love the way you teach
This video needs 1 mole likes 🔥🔥🔥🔥
Very useful and easy to understand sir .. Thanks a lot
Keep watching
thank you so much, sir, for your lecture, you are simple and best.
Hello sir... your teaching pattern is extremely good and your lectures have been really helpful to clear the basics.... sir please make one video on reaction kinetics , thermodynamics and colligative properties... I'll be waiting for your reply sir... thank you
Nice lecture sir...... wonderful sir.....it is the best lecture on this topic in you tube .....hats off to your effort sir....plz sir protein aur enzyme bhi parha dijiye....bohut tough hai....it will beneficial for those students who cannot afford teaching sir.....you are the best sir in the world....
Coaching *
It's my pleasure
Very well explained sir 👍
Thanks a lot
Happy Teacher's Day Sir 😊🙏🙏
Jakas sir ji
❤❤
Thnku sir
Good morning dear sir
Glad You Like It !
To get detailed free counselling session, you can fill the form 👉: bit.ly/3RwhepK
Need help? Call @ 9172266888
Thanks sir
Can u please provide details of online iit jam classes
Plz provide lectures on developmental biology also.
Yes will try to provide that.
Oh my god I discover this channel.
Thanks a lot sir 🙏
Most welcome
Thank u sir, for wonderful explanation
You are most welcome
Sir appka baki classess video kaha par hai?
Gd evening sir
Sir Buffer ke next vedio ka link provide kre plz. Bilkul show nahi ho pa raha.
Good evening
Same to you
Sir classes age continue kriyega sir
Good evening sir
🙏
👌👌
Thanks
Sir first question me 10 to the power 9 ka exsistance hi ni hua kuch... Sirf mind divert krne ke lia dia h
Sir aap next lectures classes kub se start krenge ..
Can anyone share the link of the next part of this video
ruclips.net/p/PLBUibmA0dbhvr-7qG8a-FjneureGb48R6
This playlist contain all videos. All the best.
Is video ka notes Kaha Pr Milega aap pe to kuch v free available nhi hai
Sir plzz unit 13 ko bhi start karwa dijiy 1st and 13 ka combination bhi banta h.... Tysm sir
We will try our best.
How to Calculate the quantity (grams) of oxalic acid (HOOC-COOH) that will be required to prepare its 500 mL of 0.5 N solution ...
Pls sir reply
The Formula of oxalic acid is H2C2O4. 2H2O (hydrated form), not H2C2O4. Therefore, the equivalent weight of the acid is molecular weight (126 dalton) divided by acidity (valency=2)
Therefore,126/2 = 63. thus the equivalent weight of oxalic acid is 63. For
For 1 N 1000 mm you need 63 g
For 0.5 N 1000 ml you need 63/2 g
For 0.5 N 500 ml you need 63/4 g = 15.75 g
Guru ji pura krba denge na biochemistry
Try our best.
sir 2n=48 chromosome hua toh 48/6x10^23=8x10^-23 hoga
very good
Sir 2 mg / ml = 2000mg /1000ml = 2g /1000 ml kse hua? Plz tell?
As to form molar sol....final volume shd b 1000 ml ...so in order to make final volume 1000 we had multiple by 1000 both sides
How to calculate density g/m
29% h2so4 solution have molarity 3.60
Given
Molarity of acid = 3.60 M
% of suphuric acid =29
you must know MW of sulphuric acid = 98 dalton
Mass of H2SO4 present in 1 L (1000 mL) of 3.6 M acid
= 3.6 x 98 g = 352.8 g
Let 'D' be the density of the acid.
Density = Mass/Volume
Mass of 1000 mL of acid = (D x 1000) g
Given the percentage of H2SO4 in acid = 29
352.9 x 100/1000 D = 29
352.9/10 D = 29
290 D = 352.9
D= 352.9/290 =1.22
Therefore density of H2SO4 = 1.22 g/mL
Answer c
how to participate in contest
Please register yourself free at ifasonline.com and start giving test.
Molarity 15% nacl solution
Is 0.389??
.386 M (100ml)
Nacl (MW=58.5)
15 % means 15 g in 100 ml
150 g in 1000 ml
58.5 g in 1000 ml = 1 M
1 g in 1000 ml = 1/58.5 M
150 g in 1000 ml = 150/58.5 M = 2.56
Molarity of 15% NaCl solution is 2.56
Thank you sir
What is amount of protein required to prepare 5ml of 1 uM sol? (MW of protein: 25kDa)
Can any one solve this problem? Then please solve
1gm in 100 ml of water
good
Yeh lifescience ka biochemistry part hai kya?....koi mujhey bataye ga kya plzzz
Yes!!!
@@ifasonline thanku...app biochemistry pura cmplt karawoo gay kya sir?
hi sir
How to participate in contest?
Register free at ifasonline.com and start giving contest test
❤❤
👌👌
🙏