11th Physics| L-1 | Newton's Law of Gravitation | गुरुत्वाकर्षण (Gravitation) | Half Yearly Mid

[@VivekVivekkumar-ht8fm]

Fnet.=2√3Gm^2/a^2......today's class wonderful thank you sir ji....🎉🎉🎉❤

[@surajmaurya4299]

2√3 Gm^2/a^2 Newton ❤❤❤ 🎉🎉
Thanks so much sir
All is perfect 💯💯💯
Zidd_kar
Makkahan

[@Sonalisharma_yj1ms]

Fnet=2√3 gm²/a²..... Aaj ki class bahut hi shandaar thi sir ji 🙏🙏🙏🙏🙏🎉🎉🎉🎉🎉

[@Anshukumari-kx4rx]

Thank you sir very good class ❤❤❤

[@VandanaKumariVandanaKuma-fw5qi]

Answer (Fnet= √3G2m²/a²)
Class jabardast sir 😊😊😊😊😊

[@Tanishq_without_batch]

Fnet= √3 G2m²/a²
Bahut achi lagi sir class
Clear hai sir ji ❤
Sir aap bhut aacha padhate hai

[@PriyasinghPriyasingh-v5u]

√3 G2m2 by a2 N ...class sandar thi guru ji❤❤❤😊😊😊

[@logicalgirl-u1g]

Question ka answer ---
G 2m²/a² √3
Dhanyawad Guru jii
Aap bahut acche se cheejo ko explain karke padhate hai,
Bahut bahut dhanyawad aap ka . 🙏🙏🙏

[@KimatiKumari-vk5ni]

√3G2m२/a२
Aaj class bahut aachhi thi sir thank you sir so😊😊😊😊😊

[@Shardasinghrathore]

Nice class sir ji 👍

[@Kishansingh-ksr]

Class bahut hi jyada shandaar thi guru dev ❤❤
Answer=√3G2m²/a² thank you guru ji ❤❤

[@AkhileshPal-je6mw]

G2m^2/a^2 . √3

[@AnshukumariAnshukumari-c8j]

Fnet = √3G2m²/a² N is right answer guruji 🙏🙏👍

[@siddiquizeenatshahid]

√3.G.m²/a² thankyou so much sirrr...class bht achhi thi 😊

[@pappulaljatoliya4295]

Aaj ki class bahut hi badhiya thi 😊😊 or sir thoda sa Kam samjme aaya....😊😊 Sir please kal Ek baar repeat jarur karwana...... and thode or questions prectice karwana sir 🙏🙏🙏

[@pravinspap]

Bahut acchi class rhi sir

[@AnshikaYadav-fz2vg]

Gravitation ke dvara

[@KrishnaPatel-u7x]

थैंक्स यू सर जी हम आपके बहुत बहुत आभार vakat करते है ❤❤❤❤❤ सर आप बहुत ही अच्छा पढ़ाते हैं आप बहुत आगे जायेंगे सर
.... सर आप भी हार्ड वर्क करिये और हम भी कर रहे है😢😢😢😢😢😢😢❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤समहत् हो तो like करो .........

[@ahmadjafri4868]

√3G2m^2/a^2 class bhutai achha tha guru ji 🤭

[@UpenderKumar-uq3by]

Root3g2m2/a2 hoga sir
Class mughe bahut bahut accha laga😊😊

[@Piyush_sejwaniAslianmomentum_4]

Answer=2√3Gm²/a².

[@KartikePatel-e1r]

🎉🎉

[@SampradaSampradapatidar]

root 3GM2m / aka varg

[@AnshuKumari-h1e7f]

❤❤❤😊😊😊

[@SonuKumar-ms2uy]

Fnet=√3G2m²/a² N is right answer 😊

[@KartikePatel-e1r]

Fnet= 2√3Gm^2/a^2 ANSWER🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@Mathematics_master_2.O]

Fnett at the point B
Is = √3G2m2/a2

[@satyamtiwari8454]

2√3Gm²/a²

[@SatanandKushwaha-ko3wu]

√3 G2m²/a² N

[@Anamika95063]

❤3Gm

[@ShinkooGautam]

Questions
Answer :-√3G2m^2\a^2

[@pappulaljatoliya4295]

Fnet = 2√3Gm2 /a2

[@vijayajit5613]

Newton

[@Aslian_deepak_007]

Fnet=2root of 3 Gm²/a²

[@AslianNiTiNaShA2026]

Fnet=G2m²root3/a² newton

[@RadheGovind-n3p]

Radhe radhe

[@RambhaGupta-ox2hd]

F net is equal to
G2msq square√3 upon a ka square

[@SankitKumar-w4u]

Answer=2 root 3 Gm2/a2 ..😊

[@ShivamKushwaha-p3r]

F net=G2m²/a²root3

[@JITENDRAKUMAR-fs8xe]

FC(net)= 2√3Gm²/a²N

[@SushmitaYadav-t3t]

√3 GM२/a२ answer

[@AnshukumariAnshukumari-c8j]

आज की क्लास बहुत अच्छा लगा सर जी 🙏☺️☺️☺️👍 सर जी आपने कैपलर का नियम क्यू नहीं बताए 😔😔😫

[@ShekhawatSirPhysics87]

Next class🎉

[@AnshukumariAnshukumari-c8j]

@@ShekhawatSirPhysics87 okay guruji

[@AshwaniBind-h7t]

(2Gm*2/a*2)×root3

[@AshwaniBind-h7t]

Newton😊

[@shekharsingh9508]

2root3Gm²/a²

[@AnshukumariAnshukumari-c8j]

Aapka answer galat hai

[@SampradaSampradapatidar]

Kevendis

[@EinarWest]

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[@Hemantsharma5950]

Fnet= G2m²/a² hai

[@GoluKumar-by5hy]

कौन कौन ASHA 5.O बैच ले लिया है। प्लीज बताना। ❤❤

[@SankitKumar-w4u]

Bhai batch ye kab aaya Asha 5.0

[@GoluKumar-by5hy]

@@SankitKumar-w4u 25 octo को लाँच किया।

[@motivationaladda670]

Hm Liya Hu Bhai

[@Yogesh_choudhary78]

Haa mene liya asha 5.0 batch okay

[@माँशारदाटेन्ट]

Hum bhi leya hu

[@Anshikayadav-f5y]

Sar kya sansar mein jitne bhi Bal Hain sabhi Kendra se lagte Hain ????????????????
please sar is question ka answer dijiye usse siddh karke bataiye

[@VijayKumar-r9j5d]

Answer 2√3Gm2/a2 aaya hai sir dekh kar bataye ❤😂🎉😢😮😅😊

[@rakeshkumawat2516]

√3G2M squire /a squire

[@Krishna_Gautam_]

√3Gm²/a²

[@nishadchannel]

Fnet= 2√3 Gm^2/a^2

[@rajvarma635]

Fnet=√3G2m^2/a^2

[@Ankurverma-c8w]

2√3Gm²/a²

[@Ruchi-en8wx]

Fnet=root3G.2m²/a²