Sir EIdy/dx = M . de rkha hain book main aur apne EIdy/dx =-M liya hain to sir correct kya hain.. Kya minus la liya to question galat ho jaye ga plz reply sir.. It's urgent
E is a material constant depending on what material we're actually working with here, I varies based on cross sectional shape of the beam (I'd assume both of these values are constant throughout entire working length of beam at play considering he used a line FBD) For example if we were working with an A6 Steel beam at room temperature, young's modulus E would be approx 200(10^9)Ksi and if we were dealing with a rectangular cross section, I would be 1/12(CS length)(CS width)^3)
bhai yr apki ye video chl kyo nhi rhi har5:30 min ke baad se dikat arhi hai ..blki bet bhi bilkul shi hai wifi se chl rha phir bhi load hoti ja rhi video kya chakkar hai ye
Note: negative value iss lea consider nahi krte kyuki vo beam se bahar ki imaginary value hoti h.
Wery well explained bro thank you so much ❤
Most welcome 😊
Thank you Very Much Sir for Clearing Our 🙏❤️
🤗 welcome
Macaulay method and double integration method same hota hai kya?? mere book mai likha hai ki Double integration method (Macaulay method)
yes
The reactions RA should be postive at it would be a clockwise moment
Sir EIdy/dx = M . de rkha hain book main aur apne EIdy/dx =-M liya hain to sir correct kya hain.. Kya minus la liya to question galat ho jaye ga plz reply sir.. It's urgent
No
Agar maximum slope find out karna hai toh yahi x ki value eqn 1 me dalni hai na?
Thank you so much sir 🙏🙏🙏🙏
Welcome 😊
EId^2y/dx^2=M book me diya hai ....aapne equation me( - M ) likha hai ... please issko clear kar dijiye
Last m curvature negative aayega toh starting m hi negative lo toh positive ho jayega last m
Humko ye nahi pta ki last me curvature negative hoga toh hum M positive le ke chal sakte hain na ?
sahi hai yehi hoga M ayega moment mein
thank you sir . it helps last minute before exam start.
Always welcome brother 🙏🙏
Well explained sir💙
Thanks 🙏
Udl ko simply support m badal k solve kiya anser match kiya . To shi hoga n exam m sir
Is video m simply supposed se solve kiye ho . Vaise hi udl ko simply support m convert Kar k solve kiya to shi to hoga n. Anser match hua h
Zrur bhai
Thank you a lot sir, can you do bending schedule.
Welcome
8:27 in values ko 6 se divide kerne ke bad
Un sab values ke sum ko bhi 6 se divide kyu kiya ??
Fabulous explanation Brother ❤
Thanks 😊
M ki value positive kab lete hei
ruclips.net/video/AYKtlmdMkvs/видео.html
Udl problem ko bhi aise hi convert kr k solve kareange to galat to Ni hoga n
Nahi answer match kro book m.
@@TECHNICALCLASSES_TC anser match hua h Mera . Udl ko pale sovle kiya ra rb nikal k
Which pen do u use?
Colour pen 🖊️
where did you get the values of EI? was it given? Sorry I can't understand your language.
E is a material constant depending on what material we're actually working with here, I varies based on cross sectional shape of the beam (I'd assume both of these values are constant throughout entire working length of beam at play considering he used a line FBD)
For example if we were working with an A6 Steel beam at room temperature, young's modulus E would be approx 200(10^9)Ksi and if we were dealing with a rectangular cross section, I would be 1/12(CS length)(CS width)^3)
Hopefully that helps!
Thanks brother for explaining him
Thank you Sirji 👍👍
Welcome 🤗
Same pblm h book m but answer ye ny h ....BC PUNEMIA page no 446
Haan usme mistake hai
Equation ka solution glt hai uska
Mistake in calculation at 8:27
Thank You Sir
Welcome 🤗
bhai yr apki ye video chl kyo nhi rhi har5:30 min ke baad se dikat arhi hai ..blki bet bhi bilkul shi hai wifi se chl rha phir bhi load hoti ja rhi video kya chakkar hai ye
M try krta hu
Bhai chal rahi hai mn try kiya hai
Amazing....sir..❤️❤️❤️❤️
Thank you bhai
Thanks a lot sir
Always welcome brother
Plz mention the term singularity function. That was the main.
Sure
Thanks sir
Always welcome
Tnx
Welcome
Divide this problem my 10 steps
Thanks Sir🥰
Welcome brother
Thanks you so much sir 🙏🙏🙏
Always welcome