Consider two reflectors between two layers. In the first case, the velocity of the upper layer is 2.75 km/s and the velocity of the lower layer is 5.5 km/s. In the second case, the velocity of the upper layer is 3.50 km/s, while that of the lower layer is 4.85 km/s. If a ray travels downward through the top layer at an angle of incidence of 25o in each case, which of the scenarios will result in a larger angle of refraction?
Hello Jeremy, first of all thanks for sharing these videos, they are really useful!!! I hope you see my question, maybe it is obvious but I'm kind of new with these topics, why the refracted wave goes back to the surface at one point? what defines that point in which the refracted wave will come back to the surface? Thank you very much
Hi, thanks for the question! so the wave gets refracted back up to the surface at every point along the refractor, but we typically draw it as a single arrow just for visualization purposes. In reality, the critically-refracted wave is emanating along the whole length of the layer interface after encountering it. The ray we use to trace out the path represents one point of that whole wavefield.
Consider two reflectors between two layers. In the first case, the velocity of the upper layer is 2.75 km/s and the velocity of the lower layer is 5.5 km/s. In the second case, the velocity of the upper layer is 3.50 km/s, while that of the lower layer is 4.85 km/s. If a ray travels downward through the top layer at an angle of incidence of 25o in each case, which of the scenarios will result in a larger angle of refraction?
Thank Dr. sir your tutorial class would have been so wonderful but you were not audible enough.
God bless you sir!!😊
Hi Jeremy thanks for sharing this knowledge of two layers problem however the two last steps please could you help me understand them?thanks
Consider two reflectors between two layers. In the first case, the velocity of the upper
layer is 2.75 km/s and the velocity of the lower layer is 5.5 km/s. In the second case, the
velocity of the upper layer is 3.50 km/s, while that of the lower layer is 4.85 km/s. If a ray
travels downward through the top layer at an angle of incidence of 25o
in each case,
which of the scenarios will result in a larger angle of refraction?
Hello Jeremy, first of all thanks for sharing these videos, they are really useful!!! I hope you see my question, maybe it is obvious but I'm kind of new with these topics, why the refracted wave goes back to the surface at one point? what defines that point in which the refracted wave will come back to the surface? Thank you very much
Hi, thanks for the question! so the wave gets refracted back up to the surface at every point along the refractor, but we typically draw it as a single arrow just for visualization purposes. In reality, the critically-refracted wave is emanating along the whole length of the layer interface after encountering it. The ray we use to trace out the path represents one point of that whole wavefield.
Thank you very sir
Thank you sir
Consider two reflectors between two layers. In the first case, the velocity of the upper
layer is 2.75 km/s and the velocity of the lower layer is 5.5 km/s. In the second case, the
velocity of the upper layer is 3.50 km/s, while that of the lower layer is 4.85 km/s. If a ray
travels downward through the top layer at an angle of incidence of 25o
in each case,
which of the scenarios will result in a larger angle of refraction?