Real Analysis | Precise definition of a limit.

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  • Опубликовано: 5 янв 2025

Комментарии • 105

  • @dukeofminecraft
    @dukeofminecraft 10 месяцев назад +1

    Finally a video on how to precisely write epsilon delta proofs. Thanks for this, most the videos aren’t nearly this structured and everyone has a different method.

  • @JaybeePenaflor
    @JaybeePenaflor 4 года назад +66

    Ah, the wonderful memories of when I first encountered the formal definition of the limit have returned after watching this video!

  • @alishams6479
    @alishams6479 Год назад +3

    This video shows a very clear explanation of the limit of the real functions for beginners who have hard time to grasp how this exact definition can be linked to the intuitive concept of the limits. However, it is very important to exclude x = a in the neighborhood of a. Therefore, the condition on x should be written as 0 < |x-a| < delta, which conveys the idea that the value of the function at x = a does not matter or x = a may not belong to the domain of the function.

  • @muwongeevanspaul9166
    @muwongeevanspaul9166 3 года назад +9

    I just love the humility you posses and the beautiful explanation u possess. U are a natural teacher. Thanks for your lovely lessons.

  • @elgourmetdotcom
    @elgourmetdotcom 4 года назад +76

    It would be great if you could do some more challenging examples using the definition such as for sin x / x or complicated functions since no examples of those are usually available in books, always the same basic ones.

    • @elgourmetdotcom
      @elgourmetdotcom 4 года назад +44

      Thanks guys but I’m not saying I need to solve that limit, I’m merely suggesting it would be interesting (given the type of problems Michael solves) to include some more challenging examples. That’s all.

    • @zhangkevin6748
      @zhangkevin6748 2 года назад +3

      @Λ when you learn about epsilon delta proof you can’t use limit laws, because they are not true to you. They are only true after you epsilon delta prove them. As for squeeze theorem the same logic applies, you need to be aware that the question specifies using epsilon delta definition.

    • @FredHandle1
      @FredHandle1 Год назад +2

      What I'm wondering about is that there should be an archive where the math society keeps record of all difficult proofs by subject. Does one exist? if you know pls advise.
      And yes if you are a student of math, one needs to work his hand & mind at proofs to get the feel & be creative.
      But in related fields such as fluid flow, pump design etc, it is often the case that an industrialist at short notice needs a ready solution without having to rediscover it.

  • @duskRenn
    @duskRenn 9 месяцев назад

    you're a REAL lifesaver, man. thank you so, so much for the clear and detailed steps

  • @hokou8766
    @hokou8766 4 года назад +4

    A very clear explanation, easy to understand for a beginner. Thanks for your sharing. It's a very nice video, especially for a freshman in maths.

  • @mikehughes6582
    @mikehughes6582 Год назад

    You explain it much better than the professor I had. Luckily, there was a smart guy in class that would explain it.

  • @YorangeJuice
    @YorangeJuice 3 года назад +1

    Thank you so much, explained better than anyone else I’ve watched cover this topic

  • @yoav613
    @yoav613 4 года назад +5

    in the last example you can also take delta to be equal to -4+sqrt(16+e) and you get(x-4)(x+4)isless than 16+e-16=e

  • @VeteranVandal
    @VeteranVandal 7 месяцев назад

    I think follow this with the definition for n dimensions is very helpful to make people understand that the delta(epsilon) might be hard to find, but if there's one, it's enough, otherwise the counter exemple tends to be easier.

  • @beginneratstuff
    @beginneratstuff Год назад +1

    11:30 I don't understand the logic behind replacing |x+4| with 9, because it was found that |x+4| < 9 not that |x+4| = 9. I thought about it for a while but I can't seem to figure out why it makes sense

    • @ali_aldur
      @ali_aldur Год назад +2

      This is one of the properties of the inequalities. you just have to divide the inequality by |x+4|

    • @beginneratstuff
      @beginneratstuff Год назад +1

      @@ali_aldur Thank you. I eventually figured it out. I didn't have enough experience working with inequalities to know why before but it makes sense now

  • @gametimewitharyan6665
    @gametimewitharyan6665 Год назад

    Wow this was such a good explanation, thanks a lot, I was struggling a bit to fully understand the epsilon delta definition

  • @juliapezant9768
    @juliapezant9768 3 года назад +1

    Such clarity. Thank you so much for doing this for us.

  • @newbie6036
    @newbie6036 2 года назад +2

    on 11:33, why do we use the |x+4| 7? If we want to replace the |x+4| in inequality |x-4|*|x+4| < \epsilon, shouldn't it be 7 * |x-4| < |x+4||x-4| < \epsilon. Therefore |x-4| < \epsilon/7?

  • @DumblyDorr
    @DumblyDorr 4 года назад +2

    This was 1st semester math, 3rd week real analysis I ... I'm like 99% sure around 99% of students at that point are *not* gonna type up their homework in LaTeX. :D
    ... I mean, I do - or I try to find the time. But this ain't my first rodeo. Even if you can write LaTeX well, writing well-formatted proofs with correctly justified multi-line steps - if possible in some proof calculus, or if you need to include some diagrams... that's really a lot more time-consuming than just writing it down by hand (/with pen on a tablet). Still - pays to learn to do it early.

  • @DarkMonolth
    @DarkMonolth 4 года назад +2

    My calc 1 professor introduced the formal definition with the idea of target shooting. Not sure why that’s stuck with me over 4 years later, but maybe it was repeating the definition over and over in my head about 700 times

  • @lailoelmuratova67
    @lailoelmuratova67 3 года назад

    this title used to be hard to understand but now I well understand it thank you for your interesting lesson

  • @leodijkstra6666
    @leodijkstra6666 4 года назад +4

    I can’t watch these kind of proofs without constantly hearing Tom Lehrer singing that there is a delta for every episilon :D

  • @Luffy_wastaken
    @Luffy_wastaken Год назад +6

    I literally understood the definition days ago and yet I am seeing as many videos for this as possible- I just don't get satisfied with my understanding 💀

  • @punditgi
    @punditgi 4 года назад +1

    Excellent starter examples!

  • @The1RandomFool
    @The1RandomFool 3 года назад +20

    Your shirt is inside-out!

  • @JonCurryIsolatedGuitarist
    @JonCurryIsolatedGuitarist 3 года назад

    I'm so impressed by this sir. The amount of vids I've watched on this are too numerous to recall. This is by far the absolute best presentation I've ever seen on this subject You know your shit, that's for sure. Well done man!!!!

  • @isaacfernandez2243
    @isaacfernandez2243 2 года назад

    Something it's very pleasant about him writing with chalk.

  • @minamishi
    @minamishi 7 месяцев назад

    So this is my informal paraphrase of the delta epsilon definition: "if the limit L exists at x = A, no matter how small epsilon is, there will exist a set of x values, which satisfies the condition |x - A| ≤ delta (where delta is a value we have to find but we know it exists) so that |f(x) - L| ≤ epsilon"....is that correct or close to correct?

  • @ZanderzMcCluer
    @ZanderzMcCluer 3 года назад +3

    Where does the |x+4|

    • @zatee6553
      @zatee6553 3 года назад +3

      x is at most 5 thus |x+4| is at most 9 (we are only interested in the upper bound)

    • @ellenancowitz1808
      @ellenancowitz1808 3 года назад

      @@zatee6553 thanks!

    • @NattyPi
      @NattyPi 2 года назад

      @@zatee6553 wow thanks for that explaination

  • @rcbuildmaster6192
    @rcbuildmaster6192 2 года назад

    Good explaination. Thank You very much Sir.

  • @stefanieblumenthal3105
    @stefanieblumenthal3105 Год назад

    Is it okay to introduce a domain where the function is not defined? If I have f(x)=1, for x an integer and f(x) undefined for other x. Eg, 1,1,1... Can I just still make delta as small as I like, say 1/2, in the undefined domain?

  • @MrWeb00
    @MrWeb00 4 года назад +13

    Excelente video as always, if you can (and want) make more proof for a little bit complicated functions, that would be nice :3. Greetings from Mexico :), I can't afford a math collage so this is really nice u3u. Thanks again :)

    • @TateVanPatten
      @TateVanPatten Год назад

      wonderful that you are learning for the joy of learning!

  • @glennxhose7217
    @glennxhose7217 Год назад

    you make seem so easy🤛🤝

  • @beatoriche7301
    @beatoriche7301 4 года назад +1

    Minor question: Is it common in the US to practice ε-δ proofs using concrete examples? The analysis textbooks in my mother tongue start by directly proving limit properties from the definition, which makes these types of examples pretty trivial - for instance, for the second one, the claimed limit follows directly from the continuity of the identity function and the multiplicativity of limits. Obviously, both approaches are valid, and I'm not really sure which one I prefer - I just wanted to note this because I found it interesting and ask for the perspectives of other people. From a didactic standpoint, practicing with these types of specific examples might help acquaint students with estimations - which are obviously a very fundamental tool in analysis -, especially if the ε-δ definition of a limit is introduced early on in the course; however, analysis courses already feature a lot of those estimations early on, so it might be a good idea to move directly to proving theorems rather than getting hung up on calculations.

    • @xriccardo1831
      @xriccardo1831 4 года назад +1

      Both approaches are important.

    • @stephenbeck7222
      @stephenbeck7222 4 года назад +2

      It’s good practice to be able to use the original limit definition. Of course we quickly move on to bigger things.

    • @beatoriche7301
      @beatoriche7301 4 года назад +1

      @VeryEvilPettingZoo
      Here's the thing, though: you'll see a lot of ε-δ proofs in an analysis course either way. Going through the proofs of limit properties, not to mention proofs of theorems about continuous functions and other things you'll encounter later on in an analysis course, should yield enough structural understanding of ε-δ proofs to write one yourself. Not to mention that a lot of textbooks will leave the occasional ε-δ proof as an exercise, which means you'll get even more practice - in addition to ε-δ proofs you'll encounter in other courses. And if the analysis course introduces limits of sequences before ε-δ limits (which, in my experience, most of them do), there's really not much to learn because they're essentially the same on a structural level.
      It might be a different story with calculus courses (in my country, we don't have anything analogous to those - math majors generally take analysis as one of their first courses), but in analysis courses, I don't know if this type of practice is really useful.

  • @lueelee6063
    @lueelee6063 4 года назад +1

    i needed this

  • @roberttelarket4934
    @roberttelarket4934 4 года назад +5

    The delta-epsilon definition for the limit is the most important concept and event in the history of the world bringing precision and rigor; brought forth by Bolzano, Cauchy and its final form by Weierstrass.

    • @mendelovitch
      @mendelovitch 4 года назад

      What further developments did it enable?

    • @roberttelarket4934
      @roberttelarket4934 4 года назад +1

      @@mendelovitchPrior to the delta-epsilon definition the limit was used by faith not rigor that not only math was on shaky grounds but everything from physics and chemistry that relied on it was as well and the real results from the latter two that created the modern world. This is not to say that there would be guarantee that their theoretical creations implied that in fact is how the physical world works. Math just helps them produce various models and they choose if possible the one that best fits the observations. The specific developments you asked for are more than thousands that you can find and see in their discoveries for almost two centuries!

    • @karolakkolo123
      @karolakkolo123 3 года назад +1

      @@roberttelarket4934 yes but saying that's the most significant thing out of all formalizations is quite the claim

  • @katiehallett5885
    @katiehallett5885 2 месяца назад

    i think your shirt is inside out (great video btw!)

  • @ntvonline9480
    @ntvonline9480 4 года назад

    Thank you!

  • @rogierbrussee3460
    @rogierbrussee3460 4 года назад +1

    Here is an alternative definition of limit that is also rigorous. Call a function $k:[0,\infty] \to [0,\infty]$ a control function if it is non decreasing (ie. if $ \delta_1 \le \delta_2$ , then $k(\delta_1) \le k(\delta_2)$, and
    $\inf_{\delta > 0} k(\delta) = 0$ (i.e. if $e \le k(\delta)$ for all $\delta > 0$ then $ e\le 0$.).
    We say that $\lim_{x \to a} f(x) = L$ if for all $x
    e a$ in the domain of $f$, we have
    $$
    |f(x) - L| \le k(|x -a|)
    $$
    for some control function $k$.
    Note that control functions may be infinite so this really is only a condition for $|x -a| 1/2$) is a control function showing $\lim_{x \to 0} \sin(x)/x = 1$.
    To make contact with the standard definition of limit in the video: using the above one sees that
    for all $\epsilon > 0$, and for $\delta = \sqrt{\epsilon/\sqrt{2}}$,
    we have
    for all $x$ with $0

  • @chancerowland5585
    @chancerowland5585 4 года назад +6

    Hey Mr.Penn your shirt is inside out ...

    • @roberttelarket4934
      @roberttelarket4934 4 года назад +5

      Well what do expect from an outstanding absent-minded mathematician? He cares about the subject matter not worldly things.
      You are very observant and for that reason you're probably a mathematician.

  • @mercykyalo2357
    @mercykyalo2357 3 года назад

    Nice one

  • @kimjiimnida9212
    @kimjiimnida9212 4 года назад +1

    how did it happen that absolute value of x+4 is less than 9? I am confused.

    • @rosasoiwerpuffgirls5806
      @rosasoiwerpuffgirls5806 4 года назад

      I am same

    • @emaesee4284
      @emaesee4284 3 года назад +2

      Yeah idk, -1

    • @FrostDirt
      @FrostDirt 3 года назад +4

      @@emaesee4284 since
      3 < x < 5, the maximum value of x is 5. Therefore, |x + 4| < 9.

    • @dnuma5852
      @dnuma5852 Год назад

      well think about it like this: suppose we have δ=1 and |x-4|

  • @doontz111
    @doontz111 4 года назад

    I loved RA 1. It was such a great class

  • @CharIie83
    @CharIie83 4 года назад +2

    I have a need to be handheld too much for this channel I think, yet anyway

    • @mendelovitch
      @mendelovitch 4 года назад

      I would mention that in my next date if I were you. Long moonlit walks on the beach, Italian food, and holding hands while watching Michael Penn videos.

  • @reemahmad8381
    @reemahmad8381 4 года назад

    thanx

  • @xaxuser5033
    @xaxuser5033 3 года назад

    but here in your definition u forced f to be continous at a which is not always the case

  • @padraighill4558
    @padraighill4558 Год назад +1

    the definition is missing two things. a must be a limit point of the domain (of course R contains all of its limit points but this is not always true). also, it is a DELETED delta neighbourhood about a. you say this in words but this is not in your definition.

  • @samirt1976
    @samirt1976 3 года назад

    very well explained…. 💯

  • @nuclo7586
    @nuclo7586 4 года назад +1

    14:20

  • @JesusHernandez-xv7lf
    @JesusHernandez-xv7lf 4 года назад +1

    For epsilon < 0

  • @AlessandroZir
    @AlessandroZir 3 года назад

    🔥🔥🔥🔥

  • @omriman123
    @omriman123 4 года назад +6

    Am I the only one noticed that he wore his T shirt reversed after 8 min into the video?

  • @anshumanagrawal346
    @anshumanagrawal346 2 года назад +1

    The definition is slightly wrong, you need 0

  • @ad2181
    @ad2181 4 года назад

    The limit definition needs to include a "for all" x qualifier.

  • @steves3948
    @steves3948 2 года назад

    Cool.

  • @thiagomilanezi1026
    @thiagomilanezi1026 4 года назад

    👏👏👏👏👏

  • @roberttelarket4934
    @roberttelarket4934 4 года назад +1

    It's very important in this definition with the wording. You must say for each "small" positive epsilon there is a CORRESPONDING delta... NOT for every epsilon there is a delta...

    • @calibratingform
      @calibratingform 3 года назад +1

      The definition of a limit only requires epsilon to be positive, not that it be "small." It begins: "For every epsilon > 0, there exists delta > 0 such that ....." But yes, it is equivalent to the apparently weaker statement that begins "For every 'small' epsilon > 0, there exists delta > 0 such that ...." essentially because if the statement holds for a given epsilon_1 > 0, then it also holds for any larger epsilon_2 > epsilon_1.
      But to make this latter phrasing completely rigorous, one needs to clarify the meaning of "small," which would require introducing yet another (Greek?) variable. This technical annoyance is probably why virtually every textbook uses the former phrasing (instead of the latter).

    • @roberttelarket4934
      @roberttelarket4934 3 года назад

      @@calibratingform: True small is meaningless.
      Again the important point is that Mike and others use incorrectly the word for ALL epsilon there is a delta...This is vague and misleading. That is why you need to say for EACH epsilon chosen there is a CORRESPONDING delta....

    • @calibratingform
      @calibratingform 3 года назад +1

      @@roberttelarket4934 You're objecting to the use of the word "all" as opposed to "each"? Mathematically, "all" and "each" are synonyms. Is your concern that "for all epsilon, there exists a delta...." sounds too much like the very different (incorrect) statement "there exists a delta for all epsilon...."? I mean, maybe, but it's the word order that really matters here. I suppose adding the word "corresponding" is psychologically helpful, though, sure.

    • @roberttelarket4934
      @roberttelarket4934 3 года назад

      @@calibratingform: Yes I am objecting!
      In 1968 as an undergraduate and junior taking the advanced calculus on an exam we had to use the delta-epsilon method. I used the word "all" in my response and was penalized 15 points from that question with a comment from my professor! I at that time 19 years of age luckily understood the concept that young but admitted I made a serious mistake. Since then I've known better!
      We shouldn't go by the English or any other Ianguage imprecise use of all and each. Sorry I don't agree with you, they are different in math.
      If we say for all epsilon there is a delta that could be construed by a beginning student that for all epsilon there is only a = one delta which is not correct!

    • @calibratingform
      @calibratingform 3 года назад

      ​@@roberttelarket4934 I see :-) Well, in today's 2021 mathematics, the words "all" and "each" are universally accepted as mathematical synonyms. The distinction is in the word order: "For each epsilon there exists a delta..." is different from "There exists a delta for each epsilon..." It is the second phrasing that you're referencing when you describe the misconception that there exists a common delta that applies to each epsilon simultaneously.
      By the way, the articles "the" and "a" have accepted meanings, too: "the" means "only one," whereas "a" means "at least one." I agree that this is all very confusing for beginners, but this terminology is now completely standard among professional mathematicians.

  • @khalilmohammed2297
    @khalilmohammed2297 3 года назад

    but we know that a numbers in the neighborhood of a number is endless .

  • @arthurleywin1366
    @arthurleywin1366 4 года назад

    Where did that 9 come from?

    • @arthurleywin1366
      @arthurleywin1366 4 года назад

      Someone please answer because I'm pretty stupid but trying to learn because of my course

    • @anshumanagrawal346
      @anshumanagrawal346 2 года назад

      x is between 3 and 5, so x+4 is between 7 and 9, but that means it's absolute value is also between 7 and 9, which means it is less than 9

  • @martinhazard2025
    @martinhazard2025 3 года назад

    No

  • @rialtho_the_magnificent
    @rialtho_the_magnificent 4 года назад +1

    Midroll ads. Why?

  • @JB-ym4up
    @JB-ym4up 4 года назад

    If we take the limit of a function like f(x)=1 then delta will be 0 for all values of x and epsilon.

    • @JB-ym4up
      @JB-ym4up 4 года назад +1

      @VeryEvilPettingZoo ok it clicked. For the constant function delta can be arbitrarily small regardless of epsilon, but not actually be 0. Thanks 👍

  • @robertobarrosofernandez5019
    @robertobarrosofernandez5019 4 года назад

    First comment :)

  • @jimallysonnevado3973
    @jimallysonnevado3973 4 года назад

    I think this is too late to be placed in this series

    • @stephenbeck7222
      @stephenbeck7222 4 года назад +2

      He already did a bunch of limit/convergent proofs with series which is more important as a foundation for analysis in general. Now he’s starting to prove the big theorems of calculus which rely on the existence of convergent sequences in the reals to be rigorous, and so he picks up calculus with function limits.

  • @goodplacetostop2973
    @goodplacetostop2973 4 года назад +6

    14:20