Awesome.. The code suggested by you was like 100 % faster in leetcode. The solution i thought was using a 3d matrix and used DP. I really appreciate this video
Hi Tushar, Your tutorials are very helpful. If possible please cover these 2 questions - 1. All possible increasing subsequences of numbers in a linear array having gcd 1 of any length. 2. How to answer question when asked about searching/auto correction in a dictionary - As per I know Trie can be a way but that is a prefix based solution Or edit distance will take too much time to check with all the words available ?
Hello +Tushar Roy , Your tutorials are very helpful. Thanks for these amazing tutorials. I would like to request for a tutorial on Suffix Automaton. :)
Will u please write the output of your program in comment inside the code that you provide in GitHub. As I am a C++ programmer I can not test your java code nd I have to write my own code, I am left with a little confusion whether my output is write or wrong. if u start doing so, it will be better for us. thank you...
Hope you all get placed in your dream company: All the best guys
saw three videos trying to explain the problem, yours by far is superior. thanks.
Thanks Tushar, I totally understood this algorithm hopefully i can apply in any problems involving using matrix sum 2d array.
Omg , finally i understood the algo , best explanation . Never knew that it was so easy.
Tushar Roy , i must say "fabulous explanation!!"
Awesome.. The code suggested by you was like 100 % faster in leetcode. The solution i thought was using a 3d matrix and used DP. I really appreciate this video
You are too good at explaining Tushar. Keep it up :)
Thanks again Tushar. You made DP look so easy for me.
Thanks for the great explanation
No one can replace you....Who care about Attendance in NIT if Tushar Roy is here...!!!
#Placed in SAIL #Aapki Meharbaani
+Tushar Roy Qualified from Gate sir
+Tushar Roy thank you so much.....
way of teaching is the best
Hi Tushar,
Your tutorials are very helpful.
If possible please cover these 2 questions -
1. All possible increasing subsequences of numbers in a linear array having gcd 1 of any length.
2. How to answer question when asked about searching/auto correction in a dictionary -
As per I know Trie can be a way but that is a prefix based solution
Or edit distance will take too much time to check with all the words available ?
Amazing tutorials ....wish you best of luck for mission-peace :)
Thank you :D finally understood this algo
one of the best explanation thanks man..
Amazing, thanks Tushar!
Hello Tushar...Great video. I was curious about the case where the matrix is not immutable.
What's the logic behind calculating prefix sum for each cell? What's the intuition behind the formula you used?
Great explanation! Thank you.
my hero!! you are the best bro !! tks a lot
Hello +Tushar Roy , Your tutorials are very helpful. Thanks for these amazing tutorials. I would like to request for a tutorial on Suffix Automaton. :)
Thanks :)
Fantastic explanation!! Wow!!
Sir, your way of teaching is the best.. please suggest best site for coding?
leetcode
leetcode and codeforces,geeksforgeeks
one of the great tutorial...
great job!
Helps a lot!
What difficulty shall we face if we didn't allocate extra row and extra column in second matrix?
Then we can't directly use the terms T[i-1][j], T[i][j-1] and T[i][j] in case of the elements in first row and columns(2,0,-3,4,,,6,5,2).
Right?
big fam!!
Спасибо!
Awesome !
hello Tushar. can you please make some tutorials in fault tolerant systems?
why he isn't active anymore?
Thanks 😆
Is this a floyd-warshall algorithm?
Is there someone who can actually code this time efficient solution during an interview w/o having seen the problem before?
Quite hard actually. Hopefully interviewers help a lot
👏
Will u please write the output of your program in comment inside the code that you provide in GitHub. As I am a C++ programmer I can not test your java code nd I have to write my own code, I am left with a little confusion whether my output is write or wrong. if u start doing so, it will be better for us.
thank you...