Advanced Functions 7.6 Solving Quadratic Trigonometric Equations

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  • Опубликовано: 11 янв 2025

Комментарии • 13

  • @diyonfernando5667
    @diyonfernando5667 2 года назад +8

    I cannot thank you enough for these videos! I also got my unit 7 test and got 100%. You are amazing!

  • @malik2xs
    @malik2xs Месяц назад

    thank you so much i have a test tomorrow and you taught me the whole unit in only a few days. You are the best teacher I've ever found! 🙏🏾🙏🏾

  • @shinypearls5959
    @shinypearls5959 5 лет назад +1

    Loved this video, helped me a lot, thank you 💕💕

  • @tanya4706
    @tanya4706 Год назад

    1:21 - doesn’t sin of 1/2 have a solution of pie - pie/6? from the 2nd quadrant

    • @mshavrot_math
      @mshavrot_math Год назад

      You need to check the domain. In this case it is between -pi and 0

    • @tanya4706
      @tanya4706 Год назад

      @@mshavrot_mathin the 2nd quadrant, wouldn’t you still be able to solve it by changing pie into the negative pie?

    • @mshavrot_math
      @mshavrot_math Год назад

      Definitely not. Look at the sketch that I drew to illustrate that there is no solution

  • @saims.2402
    @saims.2402 3 года назад +1

    When you were doing question 8c, you wrote one of the x values as around 0.096, when my calculator said around 0.96, is that correct, and to find the value of x in cos x = 1/ root 3, you take the inverse cos of 1/ root 3 right?

    • @mshavrot_math
      @mshavrot_math 3 года назад +1

      You are absolutely right about both.
      It should have been 0.9553 and then the second answer is 2pi minus 0.9553 which is correct in the solution. Thanks for your correction.

  • @metehanefealtug9210
    @metehanefealtug9210 Год назад +12

    I hate math