If V(0)=0 the that means V(0)=c1cos(0)+c2sin(0)=0. as sin(0)=0 and cos(0)=1 this reduces to V(0)=c1*1=0 hence c1=0 Then you're left with V(x)=c2sin(Bx) as a function, putting in the other boundary condition V(L)=0 you get V(L)=c2sin(BL)=0
Derive the wave equation governing transvene vibrations of tightly stretched elastic string.👉 Also find the natural frequency equation for the string fixed at both ends👈this is the complete questions can i write this video for the same plz plz plz tell!!!
I can't understand the steps, why if v0=0 c1 equal zero then c2sinbl =0
If V(0)=0 the that means V(0)=c1cos(0)+c2sin(0)=0. as sin(0)=0 and cos(0)=1 this reduces to V(0)=c1*1=0 hence c1=0
Then you're left with V(x)=c2sin(Bx) as a function, putting in the other boundary condition
V(L)=0 you get V(L)=c2sin(BL)=0
Derive the wave equation governing transvene vibrations of tightly stretched elastic string.👉 Also find the natural frequency equation for the string fixed at both ends👈this is the complete questions can i write this video for the same plz plz plz tell!!!
Sir can we write it for..... natural frequency equation for string fixed at both ends......???
No enough explanation, only copy paste from textbook