The Truth About the Most Controversial "Number"

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  • Опубликовано: 10 фев 2025
  • For centuries, humans have argued about whether 0.999 (repeating) = 1, and there are still many misconceptions on BOTH sides of that debate. In this extra-long episode, I’ll take you on a journey through infinite decimals to help clear some things up
    Most of this episode is mathematical demonstrations, but there is also a philosophical edge to this topic, so leave a comment letting me know your personal opinions/beliefs about this "number" (hopefully after watching this whole episode to see all of the misconceptions I cover). And/or leave a comment if you can count how many squirrels appear in this episode haha.
    A few clarifications:
    -- For the definition of the Archimedean property, I accidentally spelled it Archimedian, and also I should have clarified that the numbers should be positive and that n should be an integer.
    -- I mentioned the commutative and associative properties just as recognizable examples of properties that humans take for granted about the real numbers, which can sometimes be lost when switching systems. They are not specifically the properties that are lost by the hyperreal or surreal systems I mentioned (if/when I make an episode about those systems in the future, I’ll clarify more about which properties become more difficult in those).
    -- When I said that every terminating decimal has two representations, I should have added "non-zero" since zero is technically terminating but doesn't have the same type of alternate form.
    -- Some comments thought that I shouldn't have used "controversial" as a description and claimed that nobody disagrees about this topic nowadays. Let's appreciate the irony of people arguing that nobody is arguing haha. If you look at the comments of this video, you can see that it's clearly still a topic many people disagree/debate about.
    Make sure you're also tuned in to my ‪@Domotro‬ channel for my livestreams, shorts, and other bonus content!
    This episode was filmed by Carlo Trappenberg, and was directed / edited / soundtracked by me (Domotro).
    Special thanks to Evan Clark and to all of my Patreon supporters:
    Max, George Carozzi, Peter Offutt, Tybie Fitzhugh, Henry Spencer, Mitch Harding, YbabFlow, Joseph Rissler, Plenty W, Quinn Moyer, Julius 420, Philip Rogers, Ilmori Fajt, Brandon, August Taub, Ira Sanborn, Matthew Chudleigh, Cornelis Van Der Bent, Craig Butz, Mark S, Thorbjorn M H, Mathias Ermatinger, Edward Clarke, and Christopher Masto, Joshua S, Joost Doesberg, Adam, Chris Reisenbichler, Stan Seibert, Izeck, Beugul, OmegaRogue, Florian, William Hawkes, Michael Friemann, Claudio Fanelli, The Green Way, Julian Zassenhaus, Bailey Douglass, Jan Bosenberg, Brooks Boutwell, David Irvine, qe, George Sharabidze, Jack Dwyer, Fredrik, and Dave Brondsema!
    Check out the Combo Class Patreon at / comboclass
    If you want to mail me anything (such as any clocks/dice/etc. that you'd like to see in the background of Grade -2), here's my private mailbox address (not my home address). If you're going to send anything, please watch this short video first: • Video
    Domotro
    1442 A Walnut Street, Box # 401
    Berkeley, CA 94709
    Come chat with other combo lords on the Discord server here: / discord
    and there is a subreddit here: / comboclass
    If you want to try to help with Combo Class in some way, or collaborate in some form, reach out at combouniversity(at)gmail(dot)com
    In case anybody searches any of these terms, some topics mentioned in this episode include: 0.9999999 (0.9 repeating / zero point infinite nines) and whether that = 1, repeating decimals, patterns in different numeral bases, what consists of a proof vs. a demonstration, properties of the real numbers such as the commutative and associative properties, the hyperreal and surreal numbers, infinitesimal numbers represented by epsilon, the philosophy of why numbers are useful, fractions vs. decimals, irrational numbers like pi, multiple representations of numbers in bases, and more...
    Disclaimer: Do NOT copy any dangerous-seeming actions (which were actually performed in a careful way) involving fire, tools, or other chaotic activities you may see in Combo Class episodes. This is for education and entertainment.

Комментарии • 1,1 тыс.

  • @ComboClass
    @ComboClass  Год назад +100

    This extra-long episode is my presentation about if/when/how 0.999 (repeating) equals 1. Most of this episode is mathematical demonstrations, but there is also a philosophical edge to this topic, so leave a comment letting me know your personal opinions/beliefs about this "number" (hopefully after watching this whole episode to see all of the misconceptions I cover). And/or leave a comment if you can count how many squirrels appear in this episode haha.

    • @donaverboxwood
      @donaverboxwood Год назад +3

      Pardon if this is a stupid question, but in regards to infinite strings of digits in decimals, would it be fair to say they are a different kind of string than finite strings? (I mean, obviously yes, but let me explain) What I mean is, it would be completely incorrect to have a number like 0.000...(infinite 0s)...0001, where the infinite string of digits is not the last string overall, right? So there has to be a difference between what a finite string is and what an infinite string is, despite being made of the same thing (digits). I guess what I'm asking is, would it be more accurate to say that decimals can have infinite strings of digits only if the infinite component is the smallest (rightmost when written out) component? Again, sorry if this is complete nonsense I'm saying. I am by no means "good at math".

    • @TaleTN
      @TaleTN Год назад +12

      I counted 4.999999999... squirrel appearances.

    • @diribigal
      @diribigal Год назад +3

      @@donaverboxwood when you're talking about real numbers in their standard decimal forms or "strings" in most other senses, yes, an infinite string like these cannot have a right endpoint. However, that doesn't mean the idea is inconceivable. If an infinite string is normally like "there's a first character and a second character, and similarly a character for every counting number", then you could certainly make up something like a super-string which has a character for every counting number, and then three extra characters which are considered to come after all of the others. This is getting very close to the mathematical idea of "ordinals".

    • @MrDannyDetail
      @MrDannyDetail Год назад +2

      @@donaverboxwood Maths is the study of patterns, not the study of numbers. If you mean you are not good at manually performing additions, subtractions, multiplications or divisions where the numbers are not trivially small and easy to work with then it is arithmetic you are not good at, rather than mathematics (and in any case you're probably better than you think at arithmetic). What you demonstrated in your original comment is the ability to see the range of patterns already exisiting in a mathematical system and then concevie an entirely new way of extending that system with new patterns that build on the exising system, rather than merely replacing it with a whole new system. Being able to conceive of ways of extending patterns beyond what is 'normally' done in maths classes is actually being very good at maths. Having a play with what happens if you put a finite rightmost digit (or digits) beyond a infinite string of digits on the righthand side of the decimal point could lead to all manner of interesting conclusions, to new ways of viewing existing open maths problems etc so the ability to have 'outside the box' thoughts like this about mathematical systems is what enables mathematicians to keep pushing the boundaries, finding out new things and making new theories. It's a shame that school systems in many parts of the world leave a lot of their pupils thinking that maths is just about doing hard additions, subtractions, mutilpications and divisions and similar other things like square roots and so on when really that is just arithmetic, which is merely a mathematician's basic tools for doing actual maths, and for which we have extremely good calculators and software these day anyway, whilst true mathematics almost always requires human inquisitiveness, inutittion and creativity which a machine cannot really replicate.

    • @mesplin3
      @mesplin3 Год назад

      Let x = 9 + 90 + 900 + 9000 +...
      I like that 0.999... = -1 * x.

  • @The_Queens_Quest
    @The_Queens_Quest Год назад +251

    This guy spent an infinite amount of time writing an infinite amount of "9"s after "0." for a video. Respect.

    • @sirfzavers8634
      @sirfzavers8634 Год назад +29

      Would’ve been cool if he’d shown them all… but then the video would be infinitely long and he wouldn’t get any full views. ☹️
      Edit: At least it’ll keep that fire fueled infinitely (we’ve done it boys; we’ve prevented the heat death of the universe).

    • @silver6054
      @silver6054 Год назад +32

      @greyjaguar725 Don't think he did. He spent 1 second writing the first 9, half a second writing the next, a quarter of a second writing the next and so on (practice makes perfect). So he did the whole thing in 2 seconds, which really does earn respect.

    • @sirfzavers8634
      @sirfzavers8634 Год назад +9

      @@silver6054 that could explain the lack of the time machine needed for our theory… 🤔

    • @The_Queens_Quest
      @The_Queens_Quest Год назад +2

      @@sirfzavers8634 I think he's referring to the sum to infinity of the geometroc series:1 +1/2 +1/4+1/8+... Which is a/(1-r) where a is the first term and r is the ratio (next term /previous term) So plugging in the numbers we get: 1/(1-[1/2])=1/(1/2)=2 so it takes 2 seconds to write infinite 9s.

    • @tacobell2009
      @tacobell2009 Год назад +5

      ​@@sirfzavers8634 Maybe he did, but the video is still uploading...

  • @first_m2999
    @first_m2999 Год назад +321

    Domotro has mastery over squirrels and numbers. If he would only learn to control fire, he would be unstoppable.

    • @hkayakh
      @hkayakh Год назад +20

      And a way to prevent things from falling over

    • @kamikeserpentail3778
      @kamikeserpentail3778 Год назад +11

      Squirrel Girl just needs squirrels to beat Thanos, Dr. Doom, Galactus, whomever.
      He's got this.

    • @nitehawk86
      @nitehawk86 Год назад +10

      There's a reason why Squirrel Girl is invulnerable and all of the fire based superheroes are not.

    • @MawdyDev
      @MawdyDev Год назад +12

      He's dual classing Wizard and Druid, it might be hard for him to continue leveling if he adds Sorcerer to that list

    • @peppermann
      @peppermann Год назад

      😃🤣❤️👏👍

  • @nitehawk86
    @nitehawk86 Год назад +101

    I just wanna way the camera work, on this episode is particularly fantastic. Capturing the disaster just as it happens without taking away from the lecture.

    • @ComboClass
      @ComboClass  Год назад +38

      Thanks. Shout out to my main camera guy Carlo (who’s in the credits). Although I “direct” the episodes, he has some freedom behind the camera and helps capture all the rarities :)

    • @kylebowles9820
      @kylebowles9820 Год назад +3

      😂 that's such a perfect way to describe this channel in general; love the chaos

  • @TheBalthassar
    @TheBalthassar Год назад +65

    In arguments like this I always like the engineers answer "It's close enough, it fits the spec."

    • @willo7734
      @willo7734 6 месяцев назад

      It’s within the tolerance.

    • @JimmyMatis-h9y
      @JimmyMatis-h9y 2 месяца назад

      I like the engineering solution to "is the glass half full or half empty?"
      The glass is twice as large as it needs to be.
      🤓 🥰 Lol

  • @Zombie_Chess
    @Zombie_Chess Год назад +72

    This is the best video explanation I have ever seen talking about this phenomena in our arithmetic system. Thank you. You're a great teacher.

    • @ComboClass
      @ComboClass  Год назад +10

      Glad you enjoyed and it helped you learn, thanks for the compliment :)

    • @strangedivine
      @strangedivine Год назад +4

      You’re right, he’s a great teacher. I sometimes struggled with math and it was usually because of the teacher/prof’s approach in teaching.

  • @jackputnam4273
    @jackputnam4273 Год назад +41

    So glad i clicked on the first combo class vid that was recommended to me. I was immediately hooked by domotro’s style and it just keeps getting better! Such an amazing channel and it deserves a lot more attention :)

    • @ComboClass
      @ComboClass  Год назад +4

      Thanks, glad you’ve been enjoying! :)

  • @stickmandaninacan
    @stickmandaninacan Год назад +41

    Somehow the chaotic constantly interrupted style of presentation in combo class is actually really effective at keeping the attention of my adhd brain, it feels soothing 🧠 cute squirrel

    • @Fire_Axus
      @Fire_Axus 10 месяцев назад +1

      your feelings are irrational

    • @samueldeandrade8535
      @samueldeandrade8535 9 месяцев назад

      ​@@Fire_Axus haha. More than irrational, transcendental.

  • @mattiviljanen8109
    @mattiviljanen8109 Год назад +22

    (Edit: a few minutes later just this was covered in the video!)
    As a kid when I learned about 0.999... = 1, the mind-opener thought was that there is more than one way to represent a number, e.g. 1.5 = 3/2.
    As for the usual 1 / 3 = 0.333... --> 0.333 * 3 = 0.999... --> 1 - 0.999... = 0.000... counter-argument, the trick is to get infinity right. In order for the 0.000... to ever end, there would need to be a final non-zero digit. But as per definition, 0.000... does _not_ have a final digit, hence it must be all zeros, and be exactly equal to zero.

  • @diribigal
    @diribigal Год назад +28

    I teach things like the surreals and the hyperreals and I'm very pleased with how you handled things here. My one real quibble is that around 17:12 when you defined the archimedean property, I wish you'd said/written "integer n" instead of "number n". Excellent work giving a fair and clear presentation that doesn't go too far into irrelevant detail!

    • @ComboClass
      @ComboClass  Год назад +5

      Thanks for the feedback, and I’m glad you enjoyed! :)

    • @pedrogarcia8706
      @pedrogarcia8706 Год назад

      the archimedian principle is not just true for integers though.

    • @diribigal
      @diribigal Год назад +1

      @@pedrogarcia8706 In a nonarchimedean ordered field like Robinson's Hyperreals, you can always find a "number" n. If a and b are positive, then certainly (2b/a)×a is larger than b, even if a is infinitesimal and b isn't, for instance.

  • @Ninja20704
    @Ninja20704 Год назад +31

    While I never really doubted it, the most convincing argument to me is that theres no number you could fit strictly between 0.99… and 1. Most people can see that intuitively, but there are also rigorous ways to show that.
    Usually i just tend to say if we don’t accept it, we cannot accpet any fraction with a non-terminating decimal, like 1/7 or 1/11 as well.
    I appreciate you adressing topics like this, maybe do more of them.

    • @BlackBull.
      @BlackBull. Год назад +4

      0.99...95

    • @pepebriguglio6125
      @pepebriguglio6125 Год назад +1

      Per my intuition, I agree because an infinite string of decimal 9's WILL get literally infinitely close to the number 1, and only 1 can be 'infinitely close to' 1.
      BUT technically, I don't find it difficult to find an infinite amount of real numbers between 0.999... and 1. Of course I must be overlooking something. But here it is:
      0.999... = S(9/(10^n)) for n=1->inf.
      But this is an infinite sum with ordered place holders (n=1, n=2, etc.). So let's construct an infinite sum, which approaches 1, say 11/10, times faster, which would be: S(99/(100^n)), n=1->inf.
      Normally we would say that this is just an alternative way to describe 0.999..., because the decimal places would then simply be occupied pair-wise, instead of one by one. But still it stands to reason, that for every value of n, the number grows by 11/10 more than in the case of S(9/(10^n)).
      Another way to look at it, could be in base100. Here we have 0.99;99;99;..., which again would approach 1 by a factor of 11/10 faster than 0.999... in base10 would.
      So I suppose the question is, whether 'faster than' implies 'bigger than', when it comes to infinite sums.

    • @pyropulseIXXI
      @pyropulseIXXI Год назад +5

      There is a number, and it is 0.99... + ε, where ε is an infinitesimal. You can literally prove 0.99... = 1 with infinitesimals, so idk why he said introducing them messes things up; it doesn't. The hyperreals are an ordered field with all the same properties as the reals, so associativity and commutativity holds.
      The reals are a subfield of the hyperreals, just as the rationals are a subfield of the reals.
      What you meant to say is that there is no *_real number_* that fits in-between 0.99... and 1. Also, your intuition says that 0.9... = 1 is obvious; or at least my intuition does. It is so far beyond obvious, but saying "it is hard to prove, therefore the intuition is wrong!" is pure absurdity. Proving 1 + 1 = 2 rigorously is also quite hard, for the non-math initiated, but we don't say our intuition of 1 + 1 = 2 is wrong because of a challenging proof

    • @martind2520
      @martind2520 Год назад +3

      @@pyropulseIXXI No, you are incorrect. 0.999... + ε is not a number between 0.999... and 1. 0.999... _is_ 1, they are the _same number_ so there can be no number between them. 0.999... + ε is equal to 1 + ε, which is a number slightly higher than 1.

    • @martind2520
      @martind2520 Год назад +5

      @@BlackBull. You number ends, it ends at ...95. The number 0.999... _doesn't end_ and so is larger than your number.

  • @howdy832
    @howdy832 Год назад +15

    In Knuth's base 1+i, any gaussian integer is represented as a + b(1+i) +c(1+I)²… wher the coefficients are 0, ±1, or ±i. Each integer has 4 representations, where leading non-zero coefficient is each option.
    E.g. 1 is either 1, -i +(1+i), i -(1+i), or -1+(1+i)² -(1+i)³

    • @howdy832
      @howdy832 Год назад +5

      You can do this with eisenstein integers too: the digits become 0, 1, w=-½+sqrt3/2, & z=w², allowing multiples of ±1, while the base is b=1-z.
      Now you can write 1 as 1, b+z, or w - w*b

    • @samueldeandrade8535
      @samueldeandrade8535 9 месяцев назад

      Nice ... very nice.

  • @rmdodsonbills
    @rmdodsonbills Год назад +19

    I believe it's been proven that the infinite series 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ... (and so on) equals 1. Has to be equal to 1. In binary that's represented by 0.11111111.... (and so on). Seems like a similar logic would work for 0.9999999999... (and so on).

    • @MuffinsAPlenty
      @MuffinsAPlenty Год назад +3

      "I believe it's been proven that the infinite series 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ... (and so on) equals 1. *_Has to_* be equal to 1." (emphasis added)
      It _has to_ be equal to 1 in the same sense that Domotro talked about in the video. It doesn't really _have to._ There's no _a priori_ reason that 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ... should have any value at all. However, if we impose upon ourselves the restrictions that it _should_ have a value, and that value should be consistent with certain arithmetic properties working in a reasonable way, then we have no other option but to recognize 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ... as being equal to 1. However, this conclusion relies on self-impositions, not on some universal truth or "nature" or anything like that.

  • @thewatcher7579
    @thewatcher7579 5 дней назад +1

    I love how Domotro normalises math and brings it into nature, absolute legend

  • @briangronberg6507
    @briangronberg6507 Год назад +3

    I’m thrilled I found your channel! This was a really solid presentation and I appreciated the reference to the p-adics and the small taste of the idea that there exist number systems/algebras that may not satisfy commutativity or even associativity like the quaternions or octonions.

  • @acelinkio
    @acelinkio 21 день назад

    This was an absolute blast to watch. Appreciate the format and keeping the dialog open!

  • @matematicke_morce
    @matematicke_morce Год назад +5

    18:43 Here we see Domotro and the squirrel, a failed version of Achilles and the tortoise where the animal actually runs off to infinity

  • @otonanoC
    @otonanoC Год назад +1

    He fed squirrels, and burned a guitar. After the smoke cleared, we concluded 0.9999.. = 1.0

  • @JonBrase
    @JonBrase Год назад +27

    The binary version of this gets really interesting. Two's complement is used to represent signed integers in computers, but some early machines used one's complement. But if you allow an infinite number of digits on either side of the radix point, two's complement and one's complement are equivalent.

    • @CassandraComar
      @CassandraComar Год назад

      these are the 2-adic numbers. some of the other p-adics can even represent i (ie solutions to x^2 + 1 = 0).

    • @JonBrase
      @JonBrase Год назад

      @@CassandraComar Not exactly. The 2-adics don't include digits to the right of the radix point.

    • @CassandraComar
      @CassandraComar Год назад

      @@JonBrase the 2-adic integers don't but the 2-adic rationals do. they represent fractions with power of 2 denominators.

    • @JonBrase
      @JonBrase Год назад

      @@CassandraComar I'm still a bit nervous about saying that what I'm talking about is too closely related to the p-adics, because there's some weird topological stuff going on with the p-adics that I don't understand and I'm not sure if it's intrinsic to all digit sequences extending infinitely to the left in a positional number system, or if it's just a useful topology to define on top of such digit sequences for the type of problems the p-adics have been used as a tool for. I think there may be multiple concepts in that space that are related to the p-adics in terms of their representations in a positional number system, but quite distinct in their deeper structure.

    • @hughobyrne2588
      @hughobyrne2588 Год назад

      For years after I learned about 1s complement and 2s complement, I had this nagging feeling that the extra '+1' step of 2s complement was... hiding something. It took me a long time, but I came to the same conclusion as you did, including all the digits after the 'point' makes it all harmonious.

  • @WillToWinvlog
    @WillToWinvlog Год назад +7

    When I was a kid we used to assume it was wrong but we used to troll each other saying if 1/3 = 333... then 3/3 = 999... I guess our intuitions were correct!

  • @eiman2498
    @eiman2498 Год назад +3

    I love watching this channel. You always upload interesting content that never fails to enlighten others (including me) !

  • @arcturuslight_
    @arcturuslight_ Год назад +2

    I remember back in school opening an algebra textbook on a small print "conventions" section, where one of the points is "for the purposes of this book we will define 0.9...=1"

  • @nnnnick
    @nnnnick Год назад +14

    some day i will understand why this man has so many clocks

    • @Programmable_Rook
      @Programmable_Rook Год назад +2

      Assuming a clock ticks exactly once every second, a clock that ticks normally has slight variation from other clocks, meaning it could be wrong at every point of the day. A clock that doesn’t tick is exactly right twice a day. So if you have many clocks that don’t tick, they will be exactly right more often than a normal clock. His clocks are more likely to tell you the exact time of day than a normal one. The real puzzle is why he doesn’t make them tick backward, then they’d be exactly right 4 times a day.

    • @MarloTheBlueberry
      @MarloTheBlueberry Год назад

      How is a backward.clock right four times a day?

    • @AaronHollander314
      @AaronHollander314 Год назад

      He hates to be late

    • @StevenLubick
      @StevenLubick Год назад

      You still have time. 😀😀😀😀

    • @MarloTheBlueberry
      @MarloTheBlueberry Год назад

      Bro.........@@StevenLubick

  • @olly8453
    @olly8453 Год назад +1

    Subscribed! You have given this the most thorough, intuitive explanation I've ever seen. You are exceptional as a teacher. Also, I love the chaos of your approach and the set lol It's a great schtick that keeps the vids entertaining. If you keep going you're going to hit 100,000 subs and beyond in no time. Keep up the great work.

  • @consciouscode8150
    @consciouscode8150 Год назад +7

    After watching, I think I would consider it a notational quirk which emerges from the imprecision of what is meant by overbar, ellipses, etc. Rather it's probably better to think of real numbers represented using base-10 notation constructively, such that 1 approximately equals 0.9, 0.99, 0.999, etc but this notation alone can't ever equal 1. As soon as you say some variation of "and so on" however, what you've effectively done is taken the limit of the pattern - so it becomes almost obvious that it would be exactly equal to 1, because notationally it's essentially the same as an explicit limit. But maybe that doesn't feel so obvious because we think of the overbar or ellipses as being part of the base-10 notation itself rather than an implicit operation.

    • @kazedcat
      @kazedcat Год назад +1

      All real numbers are defined by an infinite sequence of rational numbers. So when the domain is in the set of real numbers then it is by definition a limit.

  • @maxerboi20
    @maxerboi20 Год назад +7

    Combo class be comboling my brain

  • @EpicMathTime
    @EpicMathTime Год назад +4

    You can get as close as you want to 1 with _finitely_ many 9s, and 0.999... is greater than all of those numbers.
    The common objection that continuing to add 9's will "never reach" 1 does not make sense as an objection, because such a process never reaches 0.999... either.

    • @agentofforce3467
      @agentofforce3467 Год назад

      Its probably not possible to add an infinite amount of numbers.

    • @MuffinsAPlenty
      @MuffinsAPlenty Год назад

      Perfectly explanation for a common misconception, like always.

    • @isaacbruner65
      @isaacbruner65 Год назад

      @@agentofforce3467 it's absolutely possible. Just look at any convergent infinite series, for example.

  • @busomite
    @busomite Год назад +1

    I’d seen all the explanations but the one about points on a number line, that’s one I hadn’t considered before. Somehow that lands well with me, it says they need to be the same point. Very cool, thanks!

  • @TankorSmash
    @TankorSmash Год назад +3

    This was both greatly educational and yet greatly uncomfortable. Looking forward to more!

  • @Kopiovastaava
    @Kopiovastaava Год назад +1

    I saw a squirrel, some blue tetrominoes, burning stuff and there might have been some numbers somewhere along the way. Lovely stuff as always.

  • @mrmistmonster
    @mrmistmonster Год назад +4

    I uhh didn't prove but demonstrated this to myself with Zeno's paradox shenanigans a month ago. If Achilles starts 90 meters behind the Hare and moves at 10 m/s while the Hare moves 1 m/s. If you go through it you get to Achilles passing the Hare at 9.99999999 etc meters past the Hare's starting point. But if you just solve the equation you'll get 10 meters.

  • @CatherineKimport
    @CatherineKimport Год назад +2

    The argument that finally got me *comfortable* with the idea that 0.99999.... = 1 was one about how there isn't anything special about base ten. So, like, assume that 0.99999.... was some number infintessimally smaller than one. Then, shouldn't hexadecimal 0.FFFFF...... ALSO be some number infintessimally smaller than one? Would it be the SAME number as decimal 0.99999....? That seems weird, because 0.9 and 0.F are not the same, nor 0.99 and 0.FF, nor 0.999 and 0.FFF, and so on.
    So if 0.99999... and 0.FFFFF... represented DIFFERENT numbers, then that would mean that every base had a unique set of numbers it could possibly represent, and had a whole bunch of gaps about numbers that it COULDN'T represent. But if 0.99999.... and 0.FFFFF... both secretly equal 1, then those gaps go away. And the latter just felt less uncomfortable than the former.

  • @orterves
    @orterves Год назад +7

    You're right - I think something that maybe isn't taught enough in school are the constraints of the maths people are taught.
    There is confusion about the answers to questions like this because people don't realise that the answer depends on the rules of the system they are working with.
    I think that this also applies to many disagreements in life, people argue about some question not realising the question doesn't even apply given the constraints of the topic.
    Perhaps in general we should spend more time figuring out where we really are before arguing about where we want to get to.

  • @ehxolotl4194
    @ehxolotl4194 Год назад +1

    17:10 As written, "Archimedian property" should be spelt "Archimedean property", and it would be inaccurate, pick x=0, y=1 and we have no number n such that nx>y. If x, y are restricted to the positive reals (and n to a positive integer), this would work.

    • @ComboClass
      @ComboClass  Год назад +1

      You're right. I misspelled it, and also didn't clarify the positive/integer restrictions, so I added a clarification to the description.

  • @pvzpokra8602
    @pvzpokra8602 Год назад +6

    why does this guy speak in 0.75x speed

    • @samueldeandrade8535
      @samueldeandrade8535 9 месяцев назад +1

      Sorry to tell you,he doesn't. It is you. you hear in 0.75 speed.

    • @Ethan13371
      @Ethan13371 8 месяцев назад

      Since his speech contains 25% more info per word than normal, he slows it down for us plebeians

    • @JimmyMatis-h9y
      @JimmyMatis-h9y 2 месяца назад

      Because we're all in too big of a hurry

  • @gilililili
    @gilililili Год назад

    Me: wants to sleep
    The shark biologist from Jaws in a backyard of clocks slowly losing sanity: I don't think so

  • @kqawiyy
    @kqawiyy Год назад +4

    I used to deny that the two were equal, but now I see just how wrong I was in *many* different avenues. Thx

    • @gonegahgah
      @gonegahgah Год назад +1

      You were right the first time.

    • @AlexanderScott66
      @AlexanderScott66 10 месяцев назад

      No, you were right. What people leave out is two fold. One, the infinite sum series specifies that it's the limit. Two, limits do not mean the function(in tis case 9/10^n)has to equal anything, rather, it simply approaches it, getting closer and closer. It explains why there's no number between(although, if we were to talk about just integers with no decimals for illustration purposes, there is no number between 1 and 2, so is 1 equal to 2? No, because being as close as possible doesn't mean it's exact), it explains why it mentions limit in the sum of an infinite series, it explains why both sides think the way they do. But no. People have to argue with baseless facts, like saying 0.333... or 0.999... is even defined at all, despite an infinite sequence inherently being unable to be defined, which is where Wiki nerds get it wrong.
      Why there's no number in between? There is. You'll use a number line and say plot it, but what about plotting based on precision? Plot 0.9, zoom in, then 0.99, then zoom in again and 0.999, so on and so on: 0.9999, 5 9s, 6 9s, 60 9s, 100 9s, 9 novemdecillion 9s. Tell me when you mathematically can't zoom in and plot again.
      TLDR people forget the beautiful thing called limits and how they work.

    • @HassanAkhtar-n1p
      @HassanAkhtar-n1p Месяц назад

      Don't let the negativity in the replies get to you. Good job on having an open mind.

  • @ThisCanBePronounced
    @ThisCanBePronounced Год назад

    9:42: Wow. While I admit I may have caught a glance, I wasn't looking at the screen but I instantly RECOGNIZED the sound of what had just fallen over. It's been 20 years since we threw that thing away after finally being too damaged.

  • @strangedivine
    @strangedivine Год назад +3

    Math was not my best subject in school, especially post-secondary math, but damn you make it fascinating!

  • @SirWilliamKidney
    @SirWilliamKidney Год назад +1

    I went from liking this channel to loving this channel @18:31 haha

  • @TerranIV
    @TerranIV Год назад +5

    This reminds me of Fourier trigonometric series that basically shows that you can make any shape out of an infinite number of smaller and smaller cosine and sine waves. Its like everything is made of an infinite series of waves, but we just mostly interact with things that have a harmonic form.

  • @JerusalemStrayCat
    @JerusalemStrayCat Год назад +1

    I am reminded of the bijective base notation system - I don't remember whether it was covered on the channel yet. The idea is that instead of having numerals from 0 to b-1 (for base b), there would be numerals from 1 to b. This prevents quirks like 0.999...=1, but also cannot represent 0, among other drawbacks.

  • @BenHebert-no4qp
    @BenHebert-no4qp Год назад +3

    I believe base i has an infinite amount of decimal representations for numbers, as the values for each digit position repeat every four positions.
    For example,
    i^8 = i^4 = i^0 = i^-4,
    therefore 10000000 = 10000 = 1 = 0.0001, which would all represent the number 1.
    Despite having infinite representations for real and imaginary integers, base i has no representations for non-integer numbers.

  • @maynardtrendle820
    @maynardtrendle820 Год назад

    The squirrel running up and down " Yggdrasil" was awesome!😂🐿️

  • @erwinmulder1338
    @erwinmulder1338 Год назад +4

    Can you repeat part of that? I got distracted by a squirrel.

  • @RichardBuckman
    @RichardBuckman Год назад +1

    I realized that what bothered me about it when I first learned this is it seemed like there could be a way to make it so these could be considered different. Now I realized the concept I was sniffing was the infinitesimals and hyper real numbers that can be used to define nonstandard analysis.

    • @martind2520
      @martind2520 Год назад +1

      Except that in the hyper-reals 0.999... is _still_ exactly equal to 1.

    • @RichardBuckman
      @RichardBuckman Год назад

      @@martind2520 In spirit though, it was neat to find out that the idea I had a long time ago before I knew much math had some merit to it even if it didn’t apply directly.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul Год назад

      ​@@martind2520I'd like to see that proof. I could learn a lot.

    • @Chris_5318
      @Chris_5318 Год назад

      @@johnlabonte-ch5ul Karen, you have proven that you are incapable of learning any math. You don't even know that if a number can be written as p/q where p and q are natural numbers, that it is a rational number. You don't even know how to write 0.999.... In the surreals and the hyperreals, 0.999... = 1.

  • @adamswierczynski
    @adamswierczynski Год назад +9

    I tried to explain that numbers have infinite names for the same identity (due to fractions behaving as you explained) in 7th grade honors math and the class laughed at me. Even the teacher treated me like I was crazy.

    • @mokey345
      @mokey345 Год назад

      Similarly in my 7th grade honors class, my teacher convinced most of my class that “of” in word problems means “divided by” instead of “times”

  • @justsomeguy5628
    @justsomeguy5628 Год назад +1

    This video is great. Btw, floating point arithmetic (of any arbitrarily large but value) is an example of a non-archemedian system, as floatingpoint +0 is the smallest number.

  • @cmilkau
    @cmilkau Год назад +3

    Did you know 1/99 = 0.01010101..., 1/999 = 0.001001001...? Stumbled over this (in fact the general geometric series limit) on my own in middle school and turned it into a popular little school calculator program that could recover arbitrary fractions from their infinite decimal representation.

    • @mrosskne
      @mrosskne Год назад

      so, the frac > dec button that every calculator already has?

    • @MuffinsAPlenty
      @MuffinsAPlenty Год назад

      It's very nice to be able to figure out a pattern like that at your own, especially at such a young age!

  • @danieldover3745
    @danieldover3745 9 месяцев назад +1

    I had already been convinced that 0.9999... was 1, but the explanation that helped me really understand what was really going on, and why my initial repulsion to it was also correct, was the concept of a limit. At no specific, definable point does 0.999... equal 1, it just approximates 1 and approaches the limit of 1 if the sequence is taken to infinity.

    • @Chris-5318
      @Chris-5318 9 месяцев назад

      Your faulty reasoning is revealed by your, " At no specific, definable point does 0.999... equal 1" and your "approaches the limit of 1 if the sequence is taken to infinity". What you don't realise is that 0.999... is constant/unchanging/fixed/static and so cannot approach anything. It doesn't approach a limit, it's value IS a limit. You are confusing the series 0.999... (= 0.9 + 0.09 + 0.009 + ...) with the sequence 0.9, 0.99, 0.999, .... It's that sequence that approaches 1 as you step through. Here's the thing, it also approaches [the value of] 0.999.... The n th term of that sequence is 0.999...9 (n 9s), and that is easily seen to be 1 - 1/10^n.
      In fact, the value of 0.999... := lim n->oo 0.999...9 (n 9s) = lim n->oo 1 - 1/10^n = 1.
      The " := " means is equal by definition. The last equality follows from the definition of limit.
      I suggest that you look up "geometric series". The Wiki is especially relevant.

  • @caspermadlener4191
    @caspermadlener4191 Год назад +4

    I find it really refreshing how you acknowledge that it is not possible to give a satisfying proof of this.
    Axioms aren't as important as their direct consequences, those shaped the axioms in the first place.

    • @mrosskne
      @mrosskne Год назад +1

      There's nothing to prove. A decimal expansion is just another way of writing the same number.

  • @glarynth
    @glarynth Год назад

    Been waiting for this one. Well done!

  • @ilikemitchhedberg
    @ilikemitchhedberg Год назад +4

    Are you surreal right meow?

    • @ComboClass
      @ComboClass  Год назад +4

      I often live in semi-surreality

  • @manloeste5555
    @manloeste5555 Год назад

    19:40 Max Planck: "Halt' ma' mein Bier!" (hold my beer)

  • @AaronALAI
    @AaronALAI Год назад +3

    It's the same as 1 because you would need to add 0.000 repeating with a "1" at the end which is infinity small; for 0.999 repeating to equal 1.

    • @wiggles7976
      @wiggles7976 Год назад +1

      How can a real number have a digit after an infinite amount of digits to the right past the decimal point? The number 0.123 has a 1 in the 10^-1 place, a 2 in the 10^-2 place, and a 3 in the 10^-3 place. In you number, 0.000...1, you say 1 is in the 10^n place. What is n?

    • @marvinmallette6795
      @marvinmallette6795 Год назад +1

      @@wiggles7976 "n" is an unsolvable.
      Because you can't convert 1/3 into Base 10, you also cannot get the final component of 0.999... to reverse the operation. 0.333... is not a finite number from which to perform inerrant calculations upon. All subsequent calculations are based on an unfinished calculations and are therefore incorrect.
      By graphing the "limit" of 0.999... it makes it obvious in the abstract, but Aaron's statement is also an observation in the abstract. He understands the problem.
      0.999... is incorrect, but the margin of error is infinitely small to the point of meaninglessness.

    • @wiggles7976
      @wiggles7976 Год назад +1

      @@marvinmallette6795 It seems like you and Aaron accept that 0.999... is equal to 1. You do accept that 0.999... is exactly equal to 1?

    • @AaronALAI
      @AaronALAI Год назад

      @@wiggles7976 Yes, 0.999 repeating is exactly equal to 1, "0.999" by itself is not equal to 1 because you could add 0.001. If I add 0.0000 repeating with a 1 at the end to any number, the sum does not change because 0.0000...1 is infinitely small.
      I think ""n" is an unsolvable" is the correct response, but consider this to your original question, "you say 1 is in the 10^n place. What is n?"
      What if n were inf then it would be 10^-inf * 1 which is 0

    • @wiggles7976
      @wiggles7976 Год назад +1

      @@AaronALAI OK, you are right about repeating decimals; 0.999... = 1. However, this idea of putting a 1 after infinitely many 0s does not make sense for real numbers. I don't know if some exotic number set could be defined using ordinals instead of integers for the powers of 10 that each get scaled by some digit from 0 to 9. In the real numbers however, integers are used for the exponents. When we have 10^n, n is an integer, not an ordinal or something else. Infinity is not an integer. Thus, it does not make sense to talk about the digit in the "infinitieths place" of a real number. What you are writing as "0.000...1" is just a haphazard way of describing something exactly equal to 0.

  • @cinnamoncat8950
    @cinnamoncat8950 Год назад

    In the first half I was somewhat hating the video cause it just kept repeating the same "proofs" everyone would use to say 1=0.999... but right after halfway the explanation of epsilon and the infinitesimals helped me realize how to describe the fundamental disagreement I have with this argument.
    The fundamental thing I disagree on is that I think that 1/3 does NOT equal 0.333..and π does NOT equal 3.1415... I think they are APPROXIMATIONS for values that do not work in our system. They are approximations that functionally have no difference compared to the actual number in the real world but one that exists mathematically, which is why the epsilon now helps me know the difference. It is an infinitesimally small difference but just like actual infinity, it is something that can not be represented through numbers in this system.
    Thanks for coming to my Ted talk.
    Also I appreciate the video for exploring deeper than most :)

  • @ilikemitchhedberg
    @ilikemitchhedberg Год назад +3

    0.99999...st!

    • @ComboClass
      @ComboClass  Год назад +3

      I sometimes nickname it “zero point ninefinity” haha, but I didn’t say that nickname in this episode because I thought it might add confusion

    • @ilikemitchhedberg
      @ilikemitchhedberg Год назад

      @@ComboClass thank you for the lovely lecture!

    • @tyruskarmesin5418
      @tyruskarmesin5418 Год назад

      0.99999st!

    • @ilikemitchhedberg
      @ilikemitchhedberg Год назад

      @@tyruskarmesin5418 yeah, that's what I should have said

  • @asseroy
    @asseroy Год назад +1

    It feels rlly nice being that early, I rlly rlly appreciate your content 💛

    • @ComboClass
      @ComboClass  Год назад

      And I appreciate you for appreciating/commenting! :)

  • @gumenski
    @gumenski Год назад +3

    Since when was this controversial? We're stuck back in the 1700's again?

    • @ComboClass
      @ComboClass  Год назад +4

      Maybe you define controversial differently, but if you look at the comments of any video like this, you will see that people still have a wide variety of different opinions on this question

    • @MuffinsAPlenty
      @MuffinsAPlenty Год назад

      Yeah, I can understand both sides of this. The equality 0.999... = 1 is absolutely not controversial among experts in mathematics, but it is controversial among the general public, and any online discussion of 0.999... will reveal that.
      However, at the same time, I don't know how many people would be defending a video which claims that anthropogenic climate change is controversial, even if there is a sizeable portion of the general public which denies it, since there is no controversy among the experts.
      To be fair, the equality 0.999... = 1 won't have as direct of an impact on most people's lives as climate change will, but I do think the comparison gives me pause to completely agree with Domotro here.

    • @gumenski
      @gumenski Год назад

      I didn't know mathematics was opinion-based. Would you consider flat-earth vs the regular known globe earth model to also be a controversy since there are many unintelligent people rooting for us living under a dome that god made?@@ComboClass

  • @АлёшаИнкогнитов
    @АлёшаИнкогнитов 8 месяцев назад +1

    3:27 How to become a believer in a god of math.
    "something off" and paper of infinity immediately drop off.

  • @jaybingham3711
    @jaybingham3711 Год назад

    Squirrel ain't up for being played as fool. He rolled out the sniff test. The bite test. And the lick test. "Noice. But ffs the same can't be said for that lab coat!"

  • @Bombito_
    @Bombito_ 8 месяцев назад

    Finally, a video that matches how people tend to see me when i tell them that there's a number between 3 and 4 which has no decimal representation because its a new kind of value when we consider that numbers are pixels, meaning there are numbers that are right at the sides of each one

    • @Chris-5318
      @Chris-5318 8 месяцев назад

      Your comment is pure nonsense.

  • @chimpochimpay
    @chimpochimpay Год назад

    This is the most definitive discussion on this subject as far as I'm concerned. Bravo!

  • @beolach
    @beolach Год назад

    I'm a Pythagorean cultist. I don't believe in irrational numbers - not in any concrete real world way (irrationals only exist in a fictional albeit consistent & useful imaginary abstract world). But even in my philosophy 0.999... == 0.(9) == 1. It is rational & it is the unit one, from which all other real (read: rational (Pythagorean, remember)) numbers are defined. Excellent job explaining why here.
    This was something I struggled with when younger, going through a few different phases of my understanding of this difficult concept. I remember at one point feeling frustrated, and thinking it basically didn't really matter - at the time I was still wanting to trust my instinct & felt like 0.(9) != 1, but I was willing to (grudgingly - I was also in a pretty contrarian phase at the time) concede that the difference was immaterial. But it does actually matter, and I think you also did a good job explaining why it matters in this video. Ceci n'est pas une pipe, the map is not the territory, and symbols are not what they symbolize - but it is still very important to have a correct understanding of the symbolism; any flaws in understanding the fundamental symbolism can lead to flaws in the overall understanding. And it is perfectly acceptable to have multiple different symbols representing the same concept.

  • @Elrog3
    @Elrog3 Год назад

    Your presentation style is great. I prefer to include infinitesimals as numbers and though you may not, I'm glad you acknowledged that it is whatever we define it to be rather than stated that .999... = 1.
    You don't need to throw out the assumptions we are using for everyday math. You just need to treat the equals sign we are using as if it has an asterisk where things are not truly equal, but instead, are within a given range of each other. Then, you can continue on using our same symbolic rules we are used to and simultaneously not say it means .999... is literally 1.
    Do you want the world to switch to base 6? I think we should go for 12 or 30. We already learn multiplication tables up to 12x12 in school anyway, at least in the US. 10 is not great because 3 is a better prime number to evenly divide than 5 because it gives us more frequent terminating divisions. But with 6, numbers would start to require more digits to write out. I know memorizing isn't fun, but you only need to do it once. And even multiplications up to 30x30 are well within the amount of information people can retain. People that rarely do math may not know them that well, but for the people who do math a lot, it would be a benefit. I think we should make the tool specialized for the people who do the job. They do the job, so their needs should come first. We don't need to take specialized systems within every discipline of knowledge known to mankind and dumb them down for the lay person. And we don't need to here either.

    • @Elrog3
      @Elrog3 Год назад

      For the argument that goes:
      x=0.999...
      10x=9.999...
      the .999... in the first expression shouldn't be considered the same as the .999... in the second expression. It will have 1 less 9 in it. People say often say some infinities are the same size, but that's a conflation between terms. What they mean is they are the same cardinality. I also reject the notion that linear bijection reflects what 'size' is.

  • @TerranIV
    @TerranIV Год назад

    This is an amazing video! So educational and entertaining. That squirrel is hilarious! :)

  • @science_gang
    @science_gang Год назад

    you are late on the topic! science gang has covered this months ago.
    yk, we love your content! well done ❤

  • @PlebRoyale
    @PlebRoyale Год назад

    Amazing episode. Thank you Domotro.
    You may appreciate a poem I once wrote:
    "I have seen where the one mad God lives
    Far from here, yet, just a heirs breadth away
    I saw him whisper into his own ear
    'The world is not made,' He said
    'It is Mad'
    A bit of a weird fellow."

  • @oddlyspecificmath
    @oddlyspecificmath Год назад +1

    I've had terrible luck lately developing anything discussion-worthy, so I'm just going to kludge out the method I prefer. _There's no need to fully fill a division slot_ ... i.e., 4 / 2 is 2...sure, but that "fills" the slot. You can say instead that 4/2 is 1 remainder 2. Then 2/2 is 0.9 remainder 0.2, and so on...so you get 1.999999999.... with a remainder of 0.00000000...2 until you decide the "limit" has been reached and you fully "fill" the last division, then (under conversion from carryless arithmetic slots to based-digit slots) finally carry and end up with 2.000000.... as your answer. While I did develop this on my own, I found extensive references / wasn't first so suspect "delayed completion" isn't crazy.

  • @AlaaBanna
    @AlaaBanna 8 месяцев назад +1

    Perfect video, thanks.
    Although I thought you'd be the perfect person to mention this, but here's how I look at it,
    The issue with those infinate 3s of (1/3) or infinate 9s .. etc, NOT a real one, but language related one (the base system we're using).
    For example, if we're using base-3 to calcualte 1/3 we'll simply have 0.1 (with a terminating 1, not repeating), And there in base-3: 0.1x3 (actually it's 10 in base-3, because only 0,1,2 are allowed) = 1.0 simple and clear.
    Of course, even in base-3 (or all other base systems as mentioned in the video), we'll find infinately repeating digits for other ratios (Let alone irrational numbers), but ALL rational numbers can have a terminating representation in some other system that fits them. So, finding the proper base for representing the scenario you'll find that 0.999... WILL actually actually mean 1.

    • @Chris-5318
      @Chris-5318 8 месяцев назад

      Bases have nothing to do with languages. If b is a natural number, then 0.bbb... (base b+1) = 1. There is nothing special about base 10.

    • @AlaaBanna
      @AlaaBanna 8 месяцев назад +1

      @@Chris-5318 You are correct and that's what I'm saying.
      I just meant specifically for the 1=0.999 conflict could simply be resolved in the base-3 system as it will clearly be 1 and no-one would even think otherwise, that's why I mentioned it's a language (or the base) used.
      Similarly, ALL 0.bbb (related to rational numbers or ratios) can have a clear exact answer if another base, of course base-10 is not special here.

    • @Chris-5318
      @Chris-5318 8 месяцев назад

      @@AlaaBanna I have no idea what your reply (or your original post) is supposed to be achieving. What conflict are you referring to, and what is resolved by using base 3? FWIW 0.222... (base 3) = 1. There is nothing special about base 3, or any base.

    • @AlaaBanna
      @AlaaBanna 8 месяцев назад +1

      @@Chris-5318OK let me put it in another way :),
      - Main conflict the OP (the video we're commenting) is: "Is 1 = 0.99999", right?
      - He offers many proofs or alternative points of views, to show us how it's normal we can find other representations of any number, and that 1, can be expressed as 0.9999..
      - I did the same, offering another point of view, to indicate that if we looked at same numbers, from base-3 system, we'll find that conflict is resolved by itself, that because 1/3 will be represented as 0.1 in base-3 and not (0.333 in base-10), 2/3 will be represented as 0.2 base-3, and 3/3 will be 1 (without these 0.3333 * 2 = 0.66666 and *3 = 0.99999), that with base-3 for this problem specifically, we will not even have an issue.
      And that is not an special case with base-3 of course, nor something special with base-10 (agreeing with you here), but some bases are better for specific numbers to help us avoid inaccuracies of other bases.
      I hope my point is clear this time 🥲

    • @Chris-5318
      @Chris-5318 8 месяцев назад

      ​@@AlaaBanna You: "- Main conflict the OP (the video we're commenting) is: "Is 1 = 0.99999", right?"
      Me: First it's 0.999... = 1, not 0.99999 = 1, and second there is no conflict. What is it supposed to be conflicting with? I'll ignore the fact that you are not using the correct ... notation for now.
      You: "- He offers many proofs or alternative points of views, to show us how it's normal we can find other representations of any number, and that 1, can be expressed as 0.9999.."
      Me: So what?
      You: "- I did the same, offering another point of view, ..."
      Me: No you didn't.
      You: "... to indicate that if we looked at same numbers, from base-3 system, we'll find that conflict is resolved by itself, that because 1/3 will be represented as 0.1 in base-3 ..."
      Me: You resolved nothing and I have no idea what you think needs to be resolved. 0.1 (base 3) = 0.0222... (base 3) and 1 = 0.222... (base 3).
      You: "... and not (0.333 in base-10), 2/3 will be represented as 0.2 base-3, and 3/3 will be 1 (without these 0.3333 * 2 = 0.66666 and *3 = 0.99999), that with base-3 for this problem specifically, we will not even have an issue."
      Me: 1/3 = 0.333... (base 10) = 0.1 (base 3) = 0.0222... (base 3). 2/3 = 0.666... (base 10) = 0.2 (base 3) = 0.1222... (base 3). 1 = 0.999... (base 10) = 0.222... (base 3).
      You: "And that is not an special case with base-3 of course, nor something special with base-10 (agreeing with you here), but some bases are better for specific numbers to help us avoid inaccuracies of other bases.
      Me: The only inaccuracies I see are when you write, e.g., 0.99999 instead of 0.999.... 0.bbb... (base b+1) = 1 precisely in every natural number base - there is no inaccuracy. Every real number can be represented in every natural been with perfect precision. No base is more accurate than another.
      You: "I hope my point is clear this time"
      Me: I have no idea what this "point" is that you think that you are making.

  • @Point5_
    @Point5_ 8 месяцев назад

    This video made me go through all 5 stages of grief

  • @mikumikudice
    @mikumikudice Год назад

    personally, I don't consider this a glitch. it's a consequence of what math is. a representation of the nature; anything that represents something but isn't really that thing, will end up with multiple ways to represent it. many ways you can represent a car (a drawing, a word, etc). I think it's beautiful that one of the most complex things we ever invented is not a science, but a language that represents the really and events on it

  • @tomgooch1422
    @tomgooch1422 Год назад

    Excellent solution!!! (The fire, I mean.) Dr. John Gustafson, of Gustafson's law, has written an excellent book, The End of Error, dealing superbly with this maddening ambiguity. It will end the era of heating computer rooms with wasted compute cycles seeking false precision when adopted.

  • @ThePiiX
    @ThePiiX Год назад

    Not gonna argue both sides. I was fermly on the "different" side at the start. because of my computer science mind (where you never test equalities for floating points numbers)
    But now I'm on the "Equal" side. And could defend it pretty well. Nice video.
    Still got chills over all the destroyed material though..

  • @enoyna1001
    @enoyna1001 Год назад

    Squirrel is the protagonist we didn't know we needed

  • @emilyrln
    @emilyrln Год назад

    I wish you had showed the entire infinite string of 9s so we could fully appreciate the level of effort you put into your videos 😢

  • @qwertyuuytrewq825
    @qwertyuuytrewq825 Год назад

    Wow! Very funny and interesting. Great style )

  • @samsibbens8164
    @samsibbens8164 Год назад

    "people who say 0.999... can't equal 1 are the most wrong" gave me a good chuckle XD

  • @smaza2
    @smaza2 Год назад +1

    welp you conviced me pretty quickly and to be honest your explanations are very intuitive. the thing that got it for me was limits. thank you as always for your phenomenal vids

  • @bgg-ji8dc
    @bgg-ji8dc Год назад +2

    Different systems of numbers are more or less useful in different situations. If you need to count how many people are on board a bus, either the integers or the whole numbers are natural choices for that purpose. If you want to accurately measure the weight of an object in kilograms, the real number system is a better fit. Complex numbers can model real world phenomena directly a la quantum wave functions or electrical circuits, but can also be used in an abstract setting to assist in proof or calculation, even if what you're actually interested in is better modeled by real numbers. Differential calculus can be, and indeed historically *was* defined via the use of infinitesimal numbers. The surreal number system can be useful when analyzing certain infinite two-person games in game theory. There are many other number systems of theoretical interest such as finite fields or general linear groups.
    Alternate number systems are not some attempt to make a better system of numbers so as to replace the system we have, nor are they some exercise in imagining how our mathematics might have developed differently if we had adopted strange or foreign conventions. They are their own tools with their own uses - Tools that nobody can learn to use properly as long as they continue to believe that the convenient properties held by ℝ are fundamental truths of the universe. Even with complex numbers, which extremely useful even among non-mathematicians, there is this stigma against them that they are fictitious or that they are a result of "breaking the normal rules of math" - even among the highly educated. We need to get away from the idea that the "real numbers" are the only "real" numbers.

  • @coltenh581
    @coltenh581 Год назад

    This video has given me much respect for the word “infinitesimal”
    Thank you Master Domo

  • @universallanguageproject
    @universallanguageproject 7 месяцев назад

    Seems like the ship of Theseus paradox. If we lose a chunk of our skin through an injury, are we still ourselves? We would be more different for from the infinitesimal difference of .9 recurring and 1. I love your point about the numbers we create as being representational. Love your work 🙂

    • @Chris-5318
      @Chris-5318 7 месяцев назад

      1 - 0.999... = 0. There is no difference, even if infinitesimals are allowed.

  • @peterpike
    @peterpike Год назад

    My go to demonstration method on this is the fact that there are mathematical proofs that every infinitely repeating decimal is rational (i.e., a ratio of integers). 0.9... is an infinitely repeating decimal, therefore it must be a rational number, which by definition can be expressed by the ratio of two integers. If 0.9... is infinitesimally smaller than 1, then the "integers" in the ratio must be infinite--but integers can only be arbitrarily large, not infinite; thus 0.9... cannot be infinitesimally smaller than 1.

  • @maxwchase
    @maxwchase 9 месяцев назад

    As far as avoiding glitches goes, I think p-adic numbers with representations that terminate on the right avoid them... as well as the ability to represent most irrational numbers, so.

    • @Chris_5318
      @Chris_5318 9 месяцев назад

      Don't you regard ...999... = -1 as being a "glitch" in the same ways 0.999... = 1 is?

  • @ryewaldman2214
    @ryewaldman2214 Год назад

    23:42 "Any number that has a terminating decimal expansion ... will have another form [with infinite digit string]"
    I think you mean any number other than 0.
    I could be wrong, but i cannot see how to represent 0 with a digit string terminating in infinite 9s. I think to generate a second decimal representation of a terminating decimal number, you have to consider which size of zero your number is on, so you can take the least digit down (toward zero) by one before appending the infinite string of 9s. In zero, you cannot take the least digit down toward zero by one. It's the same type of singularity that occurs with a compass at a magnetic pole, you are already at "zero" so any step you take can only go in the wrong direction.

    • @ComboClass
      @ComboClass  Год назад

      True I should have said non-zero there. I’ll add a clarification to the description

  • @dananichols349
    @dananichols349 Год назад +1

    Just a thought...
    If I travel at 0.999(repeating) the speed of light, would I be traveling at the speed of light???

    • @gabrielgabi543
      @gabrielgabi543 5 месяцев назад

      Haha still need infinite energy

  • @landsgevaer
    @landsgevaer Год назад +1

    On the Q that was posed, a system with a non-integer base would allow numbers to be written in more than two ways (unless you insist on allowing only a canonical form, but that also deals with decimal 0.999..).
    Like, in base phi, the number one equals
    1.0000000..
    or
    0.1100000..
    or
    0.1011000..
    or
    0.1010101..
    and many more.
    (I suspect *uncountably infinitely* many more even!)

    • @HopUpOutDaBed
      @HopUpOutDaBed Год назад

      I think it's still countable, just map them to the natural numbers following the pattern
      1-> 1
      2->0.11
      3-> .1011
      n -> n-1 representation but change the last 1 to an 011
      of course you still have the infinite string of .01010101... forever but that's still just ONE number you can easily map by mapping 0 to it (or whatever trick you want to account for it.) Where are the uncountable representations coming from?

    • @landsgevaer
      @landsgevaer Год назад +1

      @@HopUpOutDaBed I was thinking about non-canonical forms that feature multiple pairs of 1s or series of more than two 1s in a row, but those indeed never seem to add to 1.000.. exactly. Have to give it some thought whether the number one is special in that sense, or even all integers are special.
      My reasoning was that when you are forming the digit expansion and you have a remainder that is just a tiny bit over the value of the next digit, then you can always choose to continue either ..100.. or ..011.. (which have the same value base phi). Another way to put it is that you can replace any ..100.. in an expansion with a ..011.. These latter forms are not canonical, but they are expressable (just like 0.999.. is not a canonical form for 1.000..). I surmised that for a typical 'random' number, such opportunities will occur arbitrarily often, i.e. there will be arbitrary many places where the expansion would have a 1 followed by two 0s, so you get a countably infinite number of places where you can choose between two representations, and 2^countably_inf equals uncountably_inf.
      On second thought, that might only hold for 'random' numbers (not exactly sure what the requirement is, but the numbers with arbitrary many ..100.. in base phi should be dense on the real line, I bet).
      So maybe I should rephrase it more narrowly that *with the exception of only a countably infinite number of reals* (including the integers as these exceptions), base phi allows uncountably infinitely many different expansions of a number. Or, alternatively, the numbers that can be written in uncountably infinitely many different ways in base phi are dense on R.

  • @percy9228
    @percy9228 Год назад

    loved the explanation and enthusiasm! ty

  • @avibank
    @avibank Год назад

    Excellent camera work

    • @ComboClass
      @ComboClass  Год назад

      Shout out to my main camera guy Carlo! And a few other friends who helped me film some of the title cards, who are named in the credits/description :)

  • @pepebriguglio6125
    @pepebriguglio6125 Год назад

    Per my intuition, I agree because an infinite string of decimal 9's WILL get literally infinitely close to the number 1, and only 1 can be 'infinitely close to' 1.
    BUT technically, I don't find it difficult to find an infinite amount of real numbers between 0.999... and 1. Of course I must be overlooking something. But here it is:
    0.999... = S(9/(10^n)) for n=1->inf.
    But this is an infinite sum with ordered place holders (n=1, n=2, etc.). So let's construct an infinite sum, which approaches 1, say 11/10, times faster, which would be: S(99/(100^n)), n=1->inf.
    Normally we would say that this is just an alternative way to describe 0.999..., because the decimal places would then simply be occupied pair-wise, instead of one by one. But still it stands to reason, that for every value of n, the number grows by 11/10 more than in the case of S(9/(10^n)).
    Another way to look at it, could be in base100. Where 0.99;99;99;..., which again would approach 1 by a factor of 11/10 faster than 0.999... in base10 would.
    So I suppose the question is, whether 'faster than' implies 'bigger than', when it comes to infinite sums.

    • @martind2520
      @martind2520 Год назад +1

      It doesn't. Your sequence is just the equivalent of 0.999... in base 100.
      In binary the equivalent is 0.111... = 1/2 + 1/4 + 1/8 + ... = 1.
      Ternary: 0.222... = 2/3 + 2/9 + 2/27 + ... = 1.
      Etc.

    • @pepebriguglio6125
      @pepebriguglio6125 Год назад

      @@martind2520
      Yes, I know. And said so myself. "Normally we would say that this is just an alternative way to describe 0.999...". But it doesn't explain why faster and denser convergence doesn't imply a bigger sum with greater approximation to the limit value, i.e. 1.
      Of course, if you have already established that 0.999...=1, then it's self-explanatory because then you have defined the difference to be 0, and
      (10/11)×0 = (11/10)×0 = 0.
      But I think the answer lies in the convergence. If the sums didn't converge, then the greatness of each step would matter. But when they converge to a finite value, then you can chop up or put together steps as you please without changing the value of the infinite sum.

  • @phyarth8082
    @phyarth8082 Год назад

    Simple computer software has built-in functions of approximation of numbers: Floor and Ceiling functions, rounding function and truncation function of numbers. Controversial matter when simple computer software has 4 dedicated functions to approximate number. Plus in physics we have capital Greek letter ∆ - difference of terms, in computer science we have δ value very small but finite it used to do numerical integration (summation loop) operation on digital computer. And in mathematics we have  (epsilon) infinite small value that is basis of calculus which nobody proven that that it exist or define value of this small value, Zeno paradox is space continuous and uniform. Exist computer software that can perform symbolical integration but it is done not numerically but using logic, Wolfram alpha can make symbolic integration and give answer in letters x, y ..., etc. But that is not real numerical calculation. Mathematics calculus and epsilon is still abstract value hanging on trust that calculus always match observable Nature.

  • @martymoo
    @martymoo Год назад

    After seeing use of the vinculum symbol instead of dots or ellipsis, I just wanted to point out, as Wikipedia says "At present, there is no single universally accepted notation or phrasing for repeating decimals." and "There are several notational conventions for representing repeating decimals. None of them are accepted universally."

    • @ComboClass
      @ComboClass  Год назад +1

      That's true. The vinculum is most common where I live so that's what I use to make it understandable to most people, but I have no specific dedication to it and I'm fine with any method that's understandable

  • @LordAziki
    @LordAziki Год назад

    I think the problem with number systems being broken by infinite decimals is the fact nothing real can be infinitely small. It may be possible for a digit string to include infinite digits after a decimal point, but no number which exists in any tangible form can be perfectly represented by it because that number would eventually become precise down to the quantum scale. Once it gets that small, we have to accept that anything measurable has a discrete Planck unit measuring the smallest it can be.
    There is no distance shorter than 1 Planck length, represented with the symbol ℓP. While 10/3 would normally equal 3.3333333..., 10ℓP/3 can't equal 3.3333333...ℓP because each digit after the decimal point represents a distance too short to exist. If you scale it up to dividing 1cm by 3, the 3s being infinite means one of them will eventually represent a distance shorter than ℓP. No matter what number system you use, no matter what units you use, some things simply can't be divided into perfectly equal parts. Unless somebody manages to come up with a revolutionary new way to represent numbers, the best we can do is get as close as possible and consider it close enough.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul Год назад

      The problem is in the past we were nowhere near being close to the definition of the smallest number. How can we say that now we are close to the smallest number seeing what the future can do. When we find the definition of the smallest number it will change our number system.

  • @FantyPegasus
    @FantyPegasus 8 месяцев назад

    I like to think about it in this way:
    Point is a shape without dimensions. Like it has not any, so it's 0-dimensional shape. However, we can draw a line using infinite amount of points. This leads us to paradox where 0 * infinity = C where C is some number larger than 0. Which is not acceptable. To solve this paradox we can consider point has size and its size is 1/infinity. Then our paradox will be "solved", because some number that differs from 0 can be increased or decreased by multiplying and dividing. Now if we look at the line with length of 1 we can "count" how many points creates this line.I know it may sound crazy but it's not a big problem, since there can be infinite points anyway, because we have different infinities. Then we look at the number 0.(9) In this situation we can get that number by removing one point out of our line with 1 length. I am not saying that you're or other mathematicians wrong or something. I'm not professional after all. I just gave my point to this problem. Also, this representation of point explains why if 0.(9)=1 then 0.(9) is not equal to 0.(9)8. Thank you, for reading my long comment.

    • @Chris_5318
      @Chris_5318 8 месяцев назад +1

      The size of a point is precisely 0. Infinity, oo, is not a number. The convention is that 1/oo = lim n->oo 1/n and that is 0. You CANNOT count the number of points there are in a line because there are more points in a line than there are natural numbers (and that there are more real numbers than natural numbers).
      To get some insight as to how complex the issue is, see "Number Line - Numberphile".

    • @FantyPegasus
      @FantyPegasus 8 месяцев назад

      @@Chris_5318 I know. I just assumed that there can be. We created whole imaginary numbers in this way.

    • @Chris_5318
      @Chris_5318 8 месяцев назад

      ​@@FantyPegasus I just noticed that I hadn't read all of your original post. You have more mistakes. For instance, you said, "Then we look at the number 0.(9) In this situation we can get that number by removing one point out of our line with 1 length". That is wrong. There isn't a missing point. You seem to think that 0.999... is a point adjacent to 1. There is no such thing as two adjacent points. Either 0.999... is the same point as 1 (on the real number line), or there are uncountably infinitely many points between them. Consider the infinite union of closed intervals:
      [0, 0.9] U [0, 0.99] U [0, 0.999] U ... = [0, 0.999...) = [0, 1)
      That's because none of the intervals contains 0.999... or 1. (Skipping a few obvious details).
      You seem to think that [0, 0.999...] = [0, 1) and that is not possible. An open interval is fundamentally different to a closed interval. NB The length of [a, b] = length [a, b) and least upper bound / supremum of [a, b] is the same as for [a, b).
      Whatever 0 * oo is undefined because oo is not a number. However, using the convention that whenever you see infinity being used as if it is a number, then I'd say that 0 * oo means lim n->oo 0 * n = 0 is the only sensible interpretation. The 0 is an actual 0, not a number arbitrarily close to 0. 0 * oo is NOT an indeterminate form as many people say. It is only a label for a type of indeterminate form.
      0.(9)8 is not equal to 0.(9) because 0.(9)8 is not a valid decimal. You can't have and endless string of 9s with an 8 at the non-existent end.
      I get the feeling that you are not familiar with the aleph numbers (cardinalities).
      This has nothing to do with imaginary numbers. I see no analogy at all.
      Your post is not particularly long.

  • @R.B.
    @R.B. Год назад

    I feel like on the left of the decimal 9-bar.9-bar works as an equivalent of Infinity, for the same reason 0.9-bar is equal to 1. For the left side of the decimal, that is the only number which seems to have any meaning, but I'd argue it follows the same number system.
    The problem I see with this is you should define that as dividing by one less than the base, so 1-bar.1-bar + 8-bar.8-bar = 9-bar.9-bar, but defining 1-bar or 8-bar isn't definable in the same way which 0.9-bar is definable as 1/9 + 8/9... So it is more difficult to define.
    One of the other strange properties that this reveals is that 9-bar.9-bar is infinitesimaly smaller than Infinity just like 0.9-bar is infinitesimaly smaller than 1, which suggests that 9-bar.9-bar might be argued to be 2*Epsilon smaller than Infinity, but in the same way I think it actually reinforces the notion that 9-bar.9-bar is Infinity and 0.9-bar is 1, because Epsilon would be equal to 2*Epsilon for the same reason Infinity is equal to 2*Infinity.

    • @martind2520
      @martind2520 Год назад

      No. Infinite 9s on both sides actually ends up being equal to 0, not infinity. (It is also a mathematical mess of a concept, but still ends up as 0.)
      And _no_ 0.999... is _not_ "infinitesimally smaller" than 1. They are _exactly_ equal. There are a multitude of proofs to this fact.

    • @R.B.
      @R.B. Год назад

      @@martind2520 you'll have to explain to me how an infinite number of nines on the left side of the decimal point is equal to 0. As for infinite nines to the right, the infinitesimally close to 1, but not quite reaching it was a point of view discussed in the video. I don't question that it is, myself, but I was trying to relate the concept to 0.9-bar as was discussed.

  • @mr.bulldops7692
    @mr.bulldops7692 Год назад

    This brings to mind how Conway described some surreal numbers as being "confused" with one another. Even if it doesn't make intuitive sense that a number that clearly isn't 1 is equal to 1, it can be substituted for 1 in a expression without changing the meaning of the expression. 0.9999... can be "confused" for 1.

    • @Chris-5318
      @Chris-5318 Год назад

      Numerals are not numbers. You think 0.999... isn't 1 based only on appearances. Do you think that 2/2 is a "confused" version of 1? There are many expressions that evaluate to 1. It'd be better if you thought of surreal numerals as being expressions.

    • @mr.bulldops7692
      @mr.bulldops7692 Год назад

      @@Chris-5318 what's a "surreal numeral"?

    • @Chris-5318
      @Chris-5318 Год назад

      @@mr.bulldops7692 I thought you'd read Conway. A relevant one is { 0.9, 0.99, 0.999, ... | 1.1, 1.01, 1.001, ... }. That's the most natural surreal numeral for 0.999..., and it happens to equal 1 as well.

    • @mr.bulldops7692
      @mr.bulldops7692 Год назад

      @@Chris-5318 I have not read Conway, yet. Only videos.
      I guess I didn't consider the aforementioned set construction as a "numeral" in the same way that the symbol "1" is. I see it as a relationship between two sets that describes 1.
      From a layman's (my own) perspective, I see the real number 0.999... as a description of number that is so arbitrarily close to 1 that it is indistinguishable from 1. Similar to the example in the video of π being represented as the infinitely long real number 3.14159..., being described by a ratio of the perimeter of a circle to twice it's radius, and all three describing the same thing.
      To me, the respective symbols "1" and "π" could be thought to be designations for the set of all descriptions sharing such an equivalency.
      Is that an incorrect way of thinking about numbers?

    • @Chris-5318
      @Chris-5318 Год назад

      @@mr.bulldops7692 As I indicated, the surreal for 0.999... corresponds to 1 also. There is no infinitesimal difference. There are infinitely many surreals that are infinitesimally less than (and greater than) 1. None of them is 0.999...
      A few mathematicians use the abysmal definition 0.999... = 1 - 1/10^H where H is a [particular] hypernatural number. But then there is no decimal for 10 * 0.999... - 9. It can't be 0.999.... i.e. decimals cannot cope with infinitesimals.
      You: "To me, the respective symbols "1" and "π" could be thought to be designations for the set of all descriptions sharing such an equivalency."
      If my understanding is correct, you have got it right. I'll go further and say that is incredibly insightful. See the Cauchy section of the Wiki about the construction of the real numbers for a realisation of that.

  • @cmilkau
    @cmilkau Год назад

    It's controversial because subconsciously, people realize that the standard definition isn't the only one possible.
    It's subtle even for mathematicians I think because we're so used to the real numbers behaving in a certain way. A metric maps to the reals. And what you take to be a valid distance critically affects what convergence means.
    What leads people astray is that they see infinite decimals as a sequence rather than a limit. And you can make that a defining feature of the reals (they are no longer a completion of the rationals because you get unnecessary extra numbers). Usually if the difference of two sequences of rational numbers gets closer to zero than any rational number, we say both sequences represent the same real number. We could instead require the difference to be zero forever after some point, yielding a topology where basically no two decimals are the same, but it's also highly disconnected (no continuum, it shatters the number line into pieces and holes similar to the rationals).
    But you can also be a bit more graceful and just require the difference to shrink faster than they do for infinite decimals, in general superexponentially. You will get numbers that don't have a decimal representation obviously. And 1/9 will be such a number, it won't equal 0.11111... anymore, and likewise 0.99999... won't equal 1 anymore.
    Such extended reals are still useful because they have infinitesimally small numbers that can represent quantities we usually have no number to assign to.

  • @tuqann
    @tuqann Год назад

    the controversy (imho) is based on the erroneous conflation of two different types of math; today in binary we denote numbers by filling bits from the starting point so for example an 8bits integer of 1 would be O#00000001 now the inverse of this process so that to count to the first number you subtract bits from a full 8bits then you have O#11111110.
    Now imagine being able to write a number an infinite number of bits using this way; the first number would O#11111111.... endlessly since we can never arrive at the slot where the value is not the 1 bit. since in binary a one bit flips to a zero with decimal system a 9 digit flips into a zero, and suddenly 0.99999...endlessly is how you write the first number (i.e. 1)

  • @micknamens8659
    @micknamens8659 4 месяца назад

    The more interesting question would be whether the number which has infinitly many 9's BEFORE the decimal point equals -1 modulo infinity.

    • @Chris-5318
      @Chris-5318 4 месяца назад

      ...999 = -1 (mod 10)
      ...999 = -1 (10s complement)
      ...999 = -1 2-adic, 5-adic and 10-adic
      I hadn't heard of modulo infinity before, but I doubt that ...999 = -1 (modulo oo) where oo is a place holder for a definite infinite number, but my confidence in that guess is low.

  • @zionfultz8495
    @zionfultz8495 Год назад

    You can find an identical representation for any number by adding the 0.9 repeating representation of 1 and subtracting the normal single digit representation of 1.

    • @Chris-5318
      @Chris-5318 Год назад

      That's only true for terminating decimals. You can't do it for 0.121212... but you can do it for 0.25 = 0.24999...