One Step Subgroup Test | Abstract Algebra | MSc, DU, ISI, BHU, IIT JAM, BSc(H), CSIR NET |

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  • Опубликовано: 15 дек 2024

Комментарии • 42

  • @tripBohemia
    @tripBohemia  5 лет назад +5

    Corrections :
    G is a group of functions from R to R-star, IE from R to set of non zero real numbers.
    So to be precise we can define identity function as
    e(x):= x when x is a non zero real
    And e(x):= 1 when x is zero
    But then e(x) will not be invertible hence we should consider functions from R-star to R-star.

    • @raojaved6078
      @raojaved6078 4 года назад

      Very nice lecture

    • @shubhzz2779
      @shubhzz2779 4 года назад

      1)I think the said group G of functions is under 'Multiplication' operation for which identity element is e(x)=1.
      (2)On the other hand group G of functions under 'Composition' operation will have identity function e(x)=x as its identity element...
      (3) e(x)=1 is a kind of 'constant function' of the form e(x)=k. I think this function maps from R to R*.
      4) While identity function e(x)=x cant map from R to R* as you mentioned above